blocks|key|3088281|text|如果您知道包名称，请使用以下代码片段|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3088282|ApplicationInfo+ai;
try+{
++++ai+=+pm.getApplicationInfo(packageName,+0);
}+catch+(final+NameNotFoundException+e)+{
++++ai+=+null;
}
final+String+applicationName+=+(String)+(ai+!=+null+?+pm.getApplicationLabel(ai)+:+"(unknown)");|code-block|syntax|javascript|3088283|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you know Package name then Use following snippet

<pre><code>ApplicationInfo ai;
try {
 ai = pm.getApplicationInfo(packageName, 0);
} catch (final NameNotFoundException e) {
 ai = null;
}
final String applicationName = (String) (ai != null ? pm.getApplicationLabel(ai) : "(unknown)");
</code></pre>

blocks|key|3088321|text|您尝试过使用PackageManager#getActivityInfo()方法吗？将会有一个包含应用程序名称的字段。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3088322|请参阅一个非常类似问题的答案here。|3088323|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/1457803/how-do-i-access-androidlabel-for-an-activity^0|6|W|0|E|4|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|S|8|@]|D|@$9|T|A|U|1|V]]|E|$]]|$1|H|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|I|$J|$5|K|L|M|E|$N|O]]]]

Have you tried using the <code>PackageManager#getActivityInfo()</code> method? There will be a field that should contain the name of the application.

See the answer to a very similar question <a href="https://stackoverflow.com/questions/1457803/how-do-i-access-androidlabel-for-an-activity">here</a>.

blocks|key|2874536|text|使用RunningAppProcessInfo获取应用程序名称：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2874537|ActivityManager+am+=+(ActivityManager)this.getSystemService(ACTIVITY_SERVICE);
List+l+=+am.getRunningAppProcesses();
Iterator+i+=+l.iterator();
PackageManager+pm+=+this.getPackageManager();
while(i.hasNext())+{
++ActivityManager.RunningAppProcessInfo+info+=+(ActivityManager.RunningAppProcessInfo)(i.next());
++try+{
++++CharSequence+c+=+pm.getApplicationLabel(pm.getApplicationInfo(info.processName,+PackageManager.GET_META_DATA));
++++Log.w("LABEL",+c.toString());
++}catch(Exception+e)+{
++++//Name+Not+FOund+Exception
++}
}|code-block|syntax|javascript|2874538|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Get Appliction Name Using RunningAppProcessInfo as:

<pre><code>ActivityManager am = (ActivityManager)this.getSystemService(ACTIVITY_SERVICE);
List l = am.getRunningAppProcesses();
Iterator i = l.iterator();
PackageManager pm = this.getPackageManager();
while(i.hasNext()) {
 ActivityManager.RunningAppProcessInfo info = (ActivityManager.RunningAppProcessInfo)(i.next());
 try {
 CharSequence c = pm.getApplicationLabel(pm.getApplicationInfo(info.processName, PackageManager.GET_META_DATA));
 Log.w("LABEL", c.toString());
 }catch(Exception e) {
 //Name Not FOund Exception
 }
}
</code></pre>

blocks|key|3088369|text|有一种比其他答案更简单的方法，它不需要您显式地命名资源，也不需要担心包名的异常。如果您直接使用字符串而不是资源，它也可以工作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3088370|只需这样做：|3088371|public+static+String+getApplicationName(Context+context)+{
++++ApplicationInfo+applicationInfo+=+context.getApplicationInfo();
++++int+stringId+=+applicationInfo.labelRes;
++++return+stringId+==+0+?+applicationInfo.nonLocalizedLabel.toString()+:+context.getString(stringId);
}|code-block|syntax|javascript|3088372|希望这能有所帮助。|3088373|编辑|offset|length|style|BOLD|3088374|根据Snicolas的评论，我已经修改了上面的代码，这样如果id为0，它就不会尝试解析它。相反，它使用nonLocalizedLabel作为退避。不需要在try/catch中包装。|CODE|3088375|entityMap^0|0|0|0|0|0|2|0|1F|H|0^^$0|@$1|2|3|4|5|6|7|V|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|W|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|X|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|Y|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|Z|8|@$M|10|N|11|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|12|8|@$M|13|N|14|O|S]]|9|@]|A|$]]|$1|T|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|U|$]]

There's an easier way than the other answers that doesn't require you to name the resource explicitly or worry about exceptions with package names. It also works if you have used a string directly instead of a resource.

Just do:

<pre><code>public static String getApplicationName(Context context) {
 ApplicationInfo applicationInfo = context.getApplicationInfo();
 int stringId = applicationInfo.labelRes;
 return stringId == 0 ? applicationInfo.nonLocalizedLabel.toString() : context.getString(stringId);
}
</code></pre>

Hope this helps.

Edit

In light of the comment from Snicolas, I've modified the above so that it doesn't try to resolve the id if it is 0. Instead it uses, <code>nonLocalizedLabel</code> as a backoff. No need for wrapping in try/catch.

blocks|key|3088412|text|如果没有在字符串中提到/由于任何原因硬编码在AndroidManifest.xml中，就像android:label="MyApp"|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|3088413|public+String+getAppLable(Context+context)+{
++++PackageManager+packageManager+=+context.getPackageManager();
++++ApplicationInfo+applicationInfo+=+null;
++++try+{
++++++++applicationInfo+=+packageManager.getApplicationInfo(context.getApplicationInfo().packageName,+0);
++++}+catch+(final+NameNotFoundException+e)+{
++++}
++++return+(String)+(applicationInfo+!=+null+?+packageManager.getApplicationLabel(applicationInfo)+:+"Unknown");
}|code-block|syntax|javascript|3088414|或者，如果您知道字符串资源ID，则可以直接通过|3088415|getString(R.string.appNameID);|3088416|entityMap^0|B|1J|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

If not mentioned in the strings.xml/hardcoded in AndroidManifest.xml for whatever reason like android:label="MyApp" 

<pre><code>public String getAppLable(Context context) {
 PackageManager packageManager = context.getPackageManager();
 ApplicationInfo applicationInfo = null;
 try {
 applicationInfo = packageManager.getApplicationInfo(context.getApplicationInfo().packageName, 0);
 } catch (final NameNotFoundException e) {
 }
 return (String) (applicationInfo != null ? packageManager.getApplicationLabel(applicationInfo) : "Unknown");
}
</code></pre>

Or if you know the String resource ID then you can directly get it via

<pre><code>getString(R.string.appNameID);
</code></pre>

blocks|key|3088430|text|Java|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3088431|public+static+String+getApplicationName(Context+context)+{
++++return+context.getApplicationInfo().loadLabel(context.getPackageManager()).toString();
}|code-block|syntax|javascript|3088432|Kotlin+(as扩展)|3088433|fun+Context.getAppName():+String+=+applicationInfo.loadLabel(packageManager).toString()|3088434|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<h1>Java</h1>
<pre><code>public static String getApplicationName(Context context) {
 return context.getApplicationInfo().loadLabel(context.getPackageManager()).toString();
}
</code></pre>
<h1>Kotlin (as extension)</h1>
<pre><code>fun Context.getAppName(): String = applicationInfo.loadLabel(packageManager).toString()
</code></pre>

blocks|key|3088463|text|如果您只需要应用程序名称，而不需要包名，那么只需编写以下代码。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3088464|+String+app_name+=+packageInfo.applicationInfo.loadLabel(getPackageManager()).toString();|code-block|syntax|javascript|3088465|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you need only the application name, not the package name, then just write this code.

<pre><code> String app_name = packageInfo.applicationInfo.loadLabel(getPackageManager()).toString();
</code></pre>

blocks|key|219974|text|在任何上下文中使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|219975|getApplicationInfo().loadLabel(getPackageManager()).toString();|code-block|syntax|javascript|219976|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

From any Context use:

<pre><code>getApplicationInfo().loadLabel(getPackageManager()).toString();
</code></pre>

blocks|key|3088504|text|好的，伙计们，另一个时髦的选择是|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3088505|Application.Context.ApplicationInfo.NonLocalizedLabel|offset|length|style|CODE|3088506|已验证应用程序元素上的硬编码android标签。|3088507|<application+android:label="Big+App"></application>|3088508|参考：http://developer.android.com/reference/android/content/pm/PackageItemInfo.html#nonLocalizedLabel|3088509|entityMap|0|LINK|mutability|MUTABLE|url|http://developer.android.com/reference/android/content/pm/PackageItemInfo.html#nonLocalizedLabel^0|0|0|1H|0|0|0|1F|0|3|2O|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|W|8|@$D|X|E|Y|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|Z|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|10|8|@$D|11|E|12|F|G]]|9|@]|A|$]]|$1|L|3|M|5|6|7|13|8|@]|9|@$D|14|E|15|1|16]]|A|$]]|$1|N|3|-4|5|6|7|17|8|@]|9|@]|A|$]]]|O|$P|$5|Q|R|S|A|$T|U]]]]

Okay guys another sleek option is

<code>Application.Context.ApplicationInfo.NonLocalizedLabel</code>

verified for hard coded android label on application element.

<code>&lt;application android:label="Big App"&gt;&lt;/application&gt;</code>

Reference:
<a href="http://developer.android.com/reference/android/content/pm/PackageItemInfo.html#nonLocalizedLabel" rel="nofollow">http://developer.android.com/reference/android/content/pm/PackageItemInfo.html#nonLocalizedLabel</a>

blocks|key|220001|text|添加到NonLocalizedLabel的源评论现在将我们引导到：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|220002|return+context.getPackageManager().getApplicationLabelFormatted(context.getApplicationInfo());|code-block|syntax|javascript|220003|entityMap^0|3|H|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

The source comment added to <code>NonLocalizedLabel</code> directs us now to:

<pre><code>return context.getPackageManager().getApplicationLabelFormatted(context.getApplicationInfo());
</code></pre>

blocks|key|225382|text|在Kotlin中，使用以下代码获取应用程序名称：|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|225383|++++++++//+Get+App+Name
++++++++var+appName:+String+=+""
++++++++val+applicationInfo+=+this.getApplicationInfo()
++++++++val+stringId+=+applicationInfo.labelRes
++++++++if+(stringId+==+0)+{
++++++++++++appName+=+applicationInfo.nonLocalizedLabel.toString()
++++++++}
++++++++else+{
++++++++++++appName+=+this.getString(stringId)
++++++++}|code-block|syntax|javascript|225384|entityMap^0|1|6|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

In Kotlin, use the following codes to get Application Name:

<pre><code> // Get App Name
 var appName: String = ""
 val applicationInfo = this.getApplicationInfo()
 val stringId = applicationInfo.labelRes
 if (stringId == 0) {
 appName = applicationInfo.nonLocalizedLabel.toString()
 }
 else {
 appName = this.getString(stringId)
 }
</code></pre>

blocks|key|2874730|text|在Kotlin中，它很简单：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2874731|val+appLabel+=+context.applicationInfo.nonLocalizedLabel.toString()|code-block|syntax|javascript|2874732|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In Kotlin its simple:
<pre><code>val appLabel = context.applicationInfo.nonLocalizedLabel.toString()
</code></pre>

blocks|key|3088666|text|默认情况下，您有一个由AndroidStudio生成的名为"app_name“的字符串资源。为什么不简单地使用它呢？或为此目的而创建的任何其他字符串资源。这比调用几个内部方法来计算一个值要容易得多，您必须首先自己设置一个值。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3088667|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

By default you have a string resource called &quot;app_name&quot; generated by AndroidStudio. Why not simply use that? Or any other string resource created for this purpose. Much easier than calling several internal methods to come up with a value you have to set yourself in the first place.

blocks|key|223257|text|你可以使用这个|type|unstyled|depth|inlineStyleRanges|entityRanges|data|223258|223259|+JAVA|blockquote|223260|223261|223262|ApplicationInfo+appInfo+=+getApplicationContext().getApplicationInfo();
String+applicationLabel+=+getApplicationContext().getPackageManager().getApplicationLabel(appInfo).toString();|code-block|syntax|javascript|223263|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|P|8|@]|9|@]|A|$]]|$1|C|3|D|5|E|7|Q|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|R|8|@]|9|@]|A|$]]|$1|G|3|-4|5|6|7|S|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|T|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|U|8|@]|9|@]|A|$]]]|N|$]]

You can use this
<blockquote>
JAVA
</blockquote>
<pre class="lang-java prettyprint-override"><code>ApplicationInfo appInfo = getApplicationContext().getApplicationInfo();
String applicationLabel = getApplicationContext().getPackageManager().getApplicationLabel(appInfo).toString();
</code></pre>

blocks|key|3088688|text|Kotlin|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|3088689|3088690|一个简单的函数，用于以kotlin格式获取应用程序的名称|blockquote|3088691|3088692|3088693|fun+getApplicationName()+:+String{
++++var+applicationName+=+""
++++try+{
++++++++val+applicationInfo+=+application.applicationInfo
++++++++val+stringId+=+applicationInfo.labelRes
++++++++if+(stringId+==+0)+{
++++++++++++applicationName+=+applicationInfo.nonLocalizedLabel.toString()
++++++++}
++++++++else+{
++++++++++++applicationName+=+application.getString(stringId)
++++++++}
++++}+catch+(e:+Exception)+{
++++++++e.printStackTrace()
++++}
++++return+applicationName
}|code-block|syntax|javascript|3088694|entityMap^0|0|6|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|V|8|@]|D|@]|E|$]]|$1|G|3|H|5|I|7|W|8|@]|D|@]|E|$]]|$1|J|3|-4|5|6|7|X|8|@]|D|@]|E|$]]|$1|K|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]|$1|L|3|M|5|N|7|Z|8|@]|D|@]|E|$O|P]]|$1|Q|3|-4|5|6|7|10|8|@]|D|@]|E|$]]]|R|$]]

Kotlin
<blockquote>
A simple function to get the name of the application in kotlin
</blockquote>
<pre><code>fun getApplicationName() : String{
 var applicationName = &quot;&quot;
 try {
 val applicationInfo = application.applicationInfo
 val stringId = applicationInfo.labelRes
 if (stringId == 0) {
 applicationName = applicationInfo.nonLocalizedLabel.toString()
 }
 else {
 applicationName = application.getString(stringId)
 }
 } catch (e: Exception) {
 e.printStackTrace()
 }
 return applicationName
}
</code></pre>

In my manifest I have:

<pre><code> &lt;application
 android:name=".MyApp"
 android:icon="@drawable/ic_launcher_icon"
 android:label="@string/app_name"
 android:debuggable="true"&gt;
</code></pre>

How do I get the label element? 

Note: My code is running inside of someone else's, so I don't have access to @string/app_name

Android - How to get application name? (Not package name)

Kotlin

Java

在我的清单中，我有： <application android:name=".MyApp" android:icon="@drawable/ic_launcher_icon" android:label="@string/app_name" android:debuggable="true">...

问Android -如何获取应用程序名称？(不是包名)
EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问Android -如何获取应用程序名称？(不是包名)EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问Android -如何获取应用程序名称？(不是包名)
EN