blocks|key|1003680|text|我要展示的是lines.pop(0)+l.remove()和del+l的组合可以达到这个效果。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1003681|from+matplotlib+import+pyplot
import+numpy,+weakref
a+=+numpy.arange(int(1e3))
fig+=+pyplot.Figure()
ax++=+fig.add_subplot(1,+1,+1)
lines+=+ax.plot(a)

l+=+lines.pop(0)
wl+=+weakref.ref(l)++#+create+a+weak+reference+to+see+if+references+still+exist
#++++++++++++++++++++++to+this+object
print+wl++#+not+dead
l.remove()
print+wl++#+not+dead
del+l
print+wl++#+dead++(remove+either+of+the+steps+above+and+this+is+still+live)|code-block|syntax|javascript|1003682|我检查了你的大型数据集，内存的释放也在系统监视器上得到了确认。|1003683|当然，更简单的方法(当不是故障排除时)是从列表中弹出它，并在line对象上调用remove，而不创建对它的硬引用：|1003684|lines.pop(0).remove()|1003685|entityMap^0|6|C|J|A|U|5|0|0|0|13|6|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|10|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|11|8|@$9|12|A|13|B|C]]|D|@]|E|$]]|$1|O|3|P|5|H|7|14|8|@]|D|@]|E|$I|J]]|$1|Q|3|-4|5|6|7|15|8|@]|D|@]|E|$]]]|R|$]]

I'm showing that a combination of <code>lines.pop(0)</code> <code>l.remove()</code> and <code>del l</code> does the trick.

<pre><code>from matplotlib import pyplot
import numpy, weakref
a = numpy.arange(int(1e3))
fig = pyplot.Figure()
ax = fig.add_subplot(1, 1, 1)
lines = ax.plot(a)

l = lines.pop(0)
wl = weakref.ref(l) # create a weak reference to see if references still exist
# to this object
print wl # not dead
l.remove()
print wl # not dead
del l
print wl # dead (remove either of the steps above and this is still live)
</code></pre>

I checked your large dataset and the release of the memory is confirmed on the system monitor as well.

Of course the simpler way (when not trouble-shooting) would be to pop it from the list and call <code>remove</code> on the line object without creating a hard reference to it: 

<pre><code>lines.pop(0).remove()
</code></pre>

blocks|key|789812|text|(使用与上面的人相同的示例)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|789813|from+matplotlib+import+pyplot
import+numpy
a+=+numpy.arange(int(1e3))
fig+=+pyplot.Figure()
ax++=+fig.add_subplot(1,+1,+1)
lines+=+ax.plot(a)

for+i,+line+in+enumerate(ax.lines):
++++ax.lines.pop(i)
++++line.remove()|code-block|syntax|javascript|789814|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

(using the same example as the guy above)

<pre><code>from matplotlib import pyplot
import numpy
a = numpy.arange(int(1e3))
fig = pyplot.Figure()
ax = fig.add_subplot(1, 1, 1)
lines = ax.plot(a)

for i, line in enumerate(ax.lines):
 ax.lines.pop(i)
 line.remove()
</code></pre>

blocks|key|1003817|text|我在不同的论坛上尝试了很多不同的答案。我猜这取决于你开发的机器。但是我用了这个语句|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1003818|ax.lines+=+[]|code-block|syntax|javascript|1003819|而且工作得很完美。我不使用cla()，因为它删除了我对绘图所做的所有定义|offset|length|style|CODE|1003820|例如。|1003821|pylab.setp(_self.ax.get_yticklabels(),+fontsize=8)|1003822|但我已经多次尝试删除这些行了。当我在删除的时候，我也使用弱引用库来检查对该行的引用，但是对我来说什么都不起作用。|1003823|希望这对其他人有效=D|1003824|entityMap^0|0|0|D|5|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@$I|Z|J|10|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|11|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|12|8|@]|9|@]|A|$E|F]]|$1|Q|3|R|5|6|7|13|8|@]|9|@]|A|$]]|$1|S|3|T|5|6|7|14|8|@]|9|@]|A|$]]|$1|U|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|V|$]]

I've tried lots of different answers in different forums. I guess it depends on the machine your developing. But I haved used the statement
<pre><code>ax.lines = []
</code></pre>
and works perfectly. I don't use <code>cla()</code> cause it deletes all the definitions I've made to the plot
Ex.
<pre><code>pylab.setp(_self.ax.get_yticklabels(), fontsize=8)
</code></pre>
but I've tried deleting the lines many times. Also using the weakref library to check the reference to that line while I was deleting but nothing worked for me.
Hope this works for someone else =D

blocks|key|789937|text|希望这能帮助其他人:上面的例子使用了ax.lines。在较新的mpl+(3.3.1)中，有了ax.get_lines()。这样就不需要调用ax.lines=[]了|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|789938|for+line+in+ax.get_lines():+#+ax.lines:
++++line.remove()
#+ax.lines=[]+#+needed+to+complete+removal+when+using+ax.lines|code-block|syntax|javascript|789939|entityMap^0|I|8|1A|E|1X|B|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|U|8|@]|D|@]|E|$]]]|L|$]]

Hopefully this can help others: The above examples use <code>ax.lines</code>.
With more recent mpl (3.3.1), there is <code>ax.get_lines()</code>.
This bypasses the need for calling <code>ax.lines=[]</code>
<pre><code>for line in ax.get_lines(): # ax.lines:
 line.remove()
# ax.lines=[] # needed to complete removal when using ax.lines
</code></pre>

blocks|key|789987|text|而您可以删除轴上具有特定索引的任何线，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|789988|import+matplotlib.pyplot+as+plt

fig+=+plt.figure()
ax1+=+fig.add_subplot(1,+2,+1)
ax2+=+fig.add_subplot(1,+2,+1)

axes+=+fig.axes++#+=+[ax1,+ax2]

#+add+two+lines+to+ax1
ax1.plot([0,+1,+2,+3,+4],+[10,+1,+20,+3,+40],+lw=2,+color='k',+label='2+Hz')
ax1.plot([0,+1,+2,+3,+4],+[15,+6,+25,+8,+45],+lw=2,+color='r',+label='4+Hz')

#+remove+one+line+from+ax1
ax1.lines[0].remove()++#+remove+the+first+line+in+ax1
#+axes[0].lines[0].remove()++#+equivalent+to+the+line+above|code-block|syntax|javascript|789989|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

while you can remove any line with specific index in an axes as following:
<pre class="lang-py prettyprint-override"><code>import matplotlib.pyplot as plt

fig = plt.figure()
ax1 = fig.add_subplot(1, 2, 1)
ax2 = fig.add_subplot(1, 2, 1)

axes = fig.axes # = [ax1, ax2]

# add two lines to ax1
ax1.plot([0, 1, 2, 3, 4], [10, 1, 20, 3, 40], lw=2, color='k', label='2 Hz')
ax1.plot([0, 1, 2, 3, 4], [15, 6, 25, 8, 45], lw=2, color='r', label='4 Hz')

# remove one line from ax1
ax1.lines[0].remove() # remove the first line in ax1
# axes[0].lines[0].remove() # equivalent to the line above

</code></pre>

How can I remove a line (or lines) of a matplotlib axes in such a way as it actually gets garbage collected and releases the memory back? The below code appears to delete the line, but never releases the memory (even with explicit calls to <code>gc.collect()</code>)
<pre><code>from matplotlib import pyplot
import numpy
a = numpy.arange(int(1e7))
# large so you can easily see the memory footprint on the system monitor.
fig = pyplot.Figure()
ax = pyplot.add_subplot(1, 1, 1)
lines = ax.plot(a) # this uses up an additional 230 Mb of memory.
# can I get the memory back?
l = lines[0]
l.remove()
del l
del lines
# not releasing memory
ax.cla() # this does release the memory, but also wipes out all other lines.
</code></pre>
So is there a way to just delete one line from an axes and get the memory back?
<a href="https://stackoverflow.com/questions/2732578/delete-lines-in-matplotlib">This potential solution</a> also does not work.

How to remove lines in a Matplotlib plot

如何删除matplotlib轴的一行(或多行)，因为它实际上被垃圾回收并释放回内存？下面的代码似乎删除了该行，但从未释放内存(即使显式调用gc.collect())from matplotlib import pyplotimport numpya = numpy.arange(int(1e7))# large so ...

问如何删除Matplotlib图中的线条
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