我从数据库中获取数据,并使用jquery选项卡显示数据:
<script>
$(function () {
$( "#treeTabs" ).tabs();
});
</script>
<div id="treeTabs">
<ul>
<?php
$hod_result = getFamilyTree();
$i = 0;
while($hod_row = mysqli_fetch_array($hod_result))
{
?>
<li>
<a href="#<?php echo $hod_row["staff_id"]?>" class="tab_header"><span class="closer" data-id3="<?php echo $hod_row["staff_id"] ?>"><i class="fa fa-times" aria-hidden="true"></i></span><?php echo $hod_row["longname"].' ('.$hod_row["team_role"].')' ?></a>
</li>
<?php $i++;} ?>
</ul>
<?php
$hod_result_tabs = getFamilyTree();
$i_tabs = 0;
while($hod_row_tabs = mysqli_fetch_array($hod_result_tabs))
{
?>
<div id="<?php echo $hod_row_tabs["staff_id"]?>">
<div class="tree" id="<?php echo $hod_row_tabs["staff_id"]?>">
<ul>
<li>
<?php
$hod_id_list = $hod_row_tabs["staff_id"];
$sv_result_list= getSupervisorRole($hod_id_list);
?>
<a href="#">
<table>
<tr>
<th colspan="3">Head Of The Department:</th>
</tr>
<tr>
<td>
<?php echo $hod_row_tabs["username"].' '.$hod_row_tabs["staff_id"]; ?>
<span class="closer" data-id3="<?php echo $hod_row_tabs["staff_id"]; ?>"><i class="fa fa-times" aria-hidden="true"></i></span>
<a href="#" style="background-color:#808080; color:white; font-size: 8px; padding: 3px 3px 3px 3px;"><?php echo substr($hod_row_tabs["team_role"], 0, 3); ?></a>
<span class="createTree" data-id3="<?php echo $hod_row_tabs["staff_id"].'|Supervisor';?>"><!--<img alt="" src="imagesAssessment/add.png">--><i class="fa fa-user-plus fa-lg" aria-hidden="true"></i></span>
<span class="btn_details" data-id3="<?php echo $hod_row_tabs["staff_id"]; ?>"><!--<img title="View Evaluation Details" src="imagesAssessment/details.png">--><i class="fa fa-search fa-lg" aria-hidden="true"></i></span>
</td>
</tr>
</table>
</a>
<?php
$sv_result= getSupervisorRole($hod_id_list);
if(mysqli_num_rows($sv_result) > 0){
?>
<ul>
<?php
while($sv_row = mysqli_fetch_array($sv_result))
{
?>
<!--<ul>-->
<li>
<a href="#" >
<table style='all:unset;'>
<tr>
<td>
<a href="#" style='all:unset;' class="expand" data-id3="<?php echo $sv_row["staff_id"].'|'.$sv_row["username"].'|'.$sv_row["importance"]; ?>">
<?php echo $sv_row["username"]; ?>
</a>
<span class="closer" data-id3="<?php echo $sv_row["staff_id"]; ?>"><i class="fa fa-times" aria-hidden="true"></i></span>
<a href="#" style="background-color:#808080; color:white; font-size: 8px; padding: 3px 3px 3px 3px;"><?php echo strtoupper(substr($sv_row["team_role"], 0, 3)); ?></a>
</td>
</tr>
<tr>
<td>
<?php echo $sv_row["staff_id"]; ?>
<span class="createTree" data-id3="<?php echo $sv_row["staff_id"].'|Checker'; ?>"><!--<img alt="" src="imagesAssessment/add.png">--><i class="fa fa-user-plus fa-lg" aria-hidden="true"></i></span>
<span class="btn_details" data-id3="<?php echo $sv_row["staff_id"]; ?>"><!--<img title="View Evaluation Details" src="imagesAssessment/details.png">--><i class="fa fa-search fa-lg" aria-hidden="true"></i></span>
</td>
</tr>
</table>
</a>
<?php
$sv_id=$sv_row["staff_id"];
$ch_result= getCheckerRole($sv_id);
if (mysqli_num_rows($ch_result) > 0){?>
<ul style='' >
<li >
<?php
while($ch_row = mysqli_fetch_array($ch_result)){ ?>
<a href="#" style='display: block;'>
<table style='all:unset;'>
<tr>
<td>
<a href="#" style='all:unset;' class="expand" data-id3="<?php echo $ch_row["staff_id"].'|'.$ch_row["username"].'|'.$ch_row["importance"]; ?>">
<?php echo $ch_row["username"]; ?>
</a>
<span class="closer" data-id3="<?php echo $ch_row["staff_id"]; ?>"><i class="fa fa-times" aria-hidden="true"></i></span>
<a href="#" style="background-color:#808080; color:white; font-size: 8px; padding: 3px 3px 3px 3px;"><?php echo strtoupper(substr($ch_row["team_role"], 0, 3)); ?></a>
</td>
</tr>
<tr>
<td>
<?php echo $ch_row["staff_id"]; ?>
<span class="createTree" data-id3="<?php echo $ch_row["staff_id"].'|Squad Leader'; ?>"><!--<img alt="" src="imagesAssessment/add.png">--><i class="fa fa-user-plus fa-lg" aria-hidden="true"></i></span>
<span class="btn_details" data-id3="<?php echo $ch_row["staff_id"]; ?>"><!--<img title="View Evaluation Details" src="imagesAssessment/details.png">--><i class="fa fa-search fa-lg" aria-hidden="true"></i></span>
</td>
</tr>
</table>
</a>
<?php } ?>
</li>
</ul>
<?php } ?>
</li>
<!--</ul>-->
<?php }} ?>
</ul>
</li>
</ul>
</div>
<div class="input"></div>
</div>
<?php $i_tabs++;} ?>
</div>
在每个选项卡中,我都有一个名称树:
然后通过单击
图标有一个带有用户列表的弹出窗口:
下面是对话框窗口的代码:
var addUserDlg, form;
/*create and open pop up window to create a team*/
addUserDlg = $("#addUserDialog").dialog({
autoOpen: false,
height: 650,
width: 570,
modal: true,
position: { my: "center", at: "top" },
buttons: {
"Create a tree": addUser,
Cancel: function () {
addUserDlg.dialog("close");
}
},
close: function () {
form[ 0 ].reset();
}
});
$(document).on('click', '.createTree', function(){
addUserDlg.dialog("open");
var leader_role = $(this).data("id3");
$.ajax({
url: "comAssessment/hr_tree_list.php",
method: "POST",
data: {leader_role: leader_role},
success: function (data) {
$('#users').html(data);
}
});
});
form = addUserDlg.find("form").on("submit", function (event) {
event.preventDefault();
addUser();
});
和函数addUser:
/*function to add new user to team*/
function addUser() {
var insert = [];
if ($('input[name="chk"]:checked').length > 0)
{
$('.get_value').each(function () {
if ($(this).is(":checked"))
{
insert.push($(this).val());
}
});
var user_to_leader = $('#user_to_leader').val();
var team_role = $('#team_role').val();
insert = insert.toString();
$.ajax({
url: "comAssessment/hr_tree_insert.php",
method: "POST",
data: {insert: insert, user_to_leader:user_to_leader, team_role:team_role},
success: function (data) {
location.reload();
addUserDlg.dialog("close");
}
});
}
}
现在我更新了整个页面的location.reload();
,但它看起来并不好,因为它每次都会打开第一个选项卡。如何在添加新用户后仅更新当前页签?
编辑
好的,我试着获取标签的索引并刷新它。我添加了测试按钮:
<button id="button">Click me</button>
<div class="test_bt"></div>
和jquery:
$("#button").click(function() {
var current_index = $("#treeTabs").tabs("option","active");
$("#treeTabs").tabs('load',current_index);
$('.test_bt').html(current_index);
});
然后,我从ajax成功函数中删除了location.reload();
,以检查我的按钮是否可以完成工作。但是它不起作用。我只得到索引,没有加载发生。
function addUser() {
var insert = [];
if ($('input[name="chk"]:checked').length > 0)
{
$('.get_value').each(function () {
if ($(this).is(":checked"))
{
insert.push($(this).val());
}
});
var user_to_leader = $('#user_to_leader').val();
var team_role = $('#team_role').val();
insert = insert.toString();
$.ajax({
url: "comAssessment/hr_tree_insert.php",
method: "POST",
data: {insert: insert, user_to_leader:user_to_leader, team_role:team_role},
success: function (data) {
addUserDlg.dialog("close");
}
});
}
}
发布于 2017-09-06 02:09:11
您可以从填充选项卡内容的循环中提取代码,并创建一个新文件。新文件应该使用querystring参数中的staffid/hod,而不是使用循环中的id。然后,在主页上,每个选项卡只获得一个空的div,其中包含员工的id。当您第一次加载页面时,使用ajax从新脚本填充第一个选项卡。在更新任何选项卡时,只需使用ajax发布更改,如果成功,则再次将当前选项卡的内容重新加载到div中。更好的做法是,从post返回更新后的结果,并将其插入div。
发布于 2017-09-06 13:53:26
它目前还不支持ajax标签页。令人难以置信的是,还没有人要求它,所以我从来没有抽出时间在里面构建它。我可能会在下一个版本中使用它。
在此期间,您可以这样做:
<div id="container">
<a href="#panel-1" data-url="/some/url/path" class="tabs">I'm a tab</a>
...
<div id="panel-1"></div>
...
</div>
然后在你的javascript中,拥有类似这样的东西:
$('#container').easytabs();
$('.tabs').click(function(){
var $this = $(this);
$($this.attr('href')).load($this.data('url'));
});
我认为这场讨论对
https://stackoverflow.com/questions/45911786
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