blocks|key|1098895|text|Dir.glob("**/*/")+#+for+directories
Dir.glob("**/*")+#+for+all+files|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1098896|除了Dir.glob(foo)，您还可以编写Dir[foo]+(但是Dir.glob也可以接受一个块，在这种情况下，它将生成每个路径，而不是创建一个数组)。|unstyled|offset|length|style|CODE|1098897|Ruby+Glob+Docs|1098898|entityMap|0|LINK|mutability|MUTABLE|url|http://ruby-doc.org/core-2.2.0/Dir.html#method-c-glob^0|0|2|D|M|8|Y|8|0|0|E|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|V|8|@$G|W|H|X|I|J]|$G|Y|H|Z|I|J]|$G|10|H|11|I|J]]|9|@]|A|$]]|$1|K|3|L|5|F|7|12|8|@]|9|@$G|13|H|14|1|15]]|A|$]]|$1|M|3|-4|5|F|7|16|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

<pre><code>Dir.glob("**/*/") # for directories
Dir.glob("**/*") # for all files
</code></pre>

Instead of <code>Dir.glob(foo)</code> you can also write <code>Dir[foo]</code> (however <code>Dir.glob</code> can also take a block, in which case it will yield each path instead of creating an array).

<a href="http://ruby-doc.org/core-2.2.0/Dir.html#method-c-glob" rel="noreferrer">Ruby Glob Docs</a>

blocks|key|1099359|text|我相信这里没有一个解决方案涉及隐藏目录(例如'.test')：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1099360|require+'find'
Find.find('.')+{+%7Ce%7C+puts+e+if+File.directory?(e)+}|code-block|syntax|javascript|1099361|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I believe none of the solutions here deal with hidden directories (e.g. '.test'):

<pre><code>require 'find'
Find.find('.') { |e| puts e if File.directory?(e) }
</code></pre>

blocks|key|1313929|text|有关目录列表，请尝试|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1313930|Dir['**/']|code-block|syntax|javascript|1313931|文件列表更难，因为在Unix目录中也是一个文件，所以您需要测试类型或从返回的列表中删除其他条目的父条目。|1313932|Dir['**/*'].reject+{%7Cfn%7C+File.directory?(fn)+}|1313933|对于所有文件和目录的列表，只需|1313934|Dir['**/*']|1313935|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

For list of directories try

<pre><code>Dir['**/']
</code></pre>

List of files is harder, because in Unix directory is also a file, so you need to test for type or remove entries from returned list which is parent of other entries.

<pre><code>Dir['**/*'].reject {|fn| File.directory?(fn) }
</code></pre>

And for list of all files and directories simply

<pre><code>Dir['**/*']
</code></pre>

blocks|key|1098703|text|Fast+one班轮|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1098704|仅目录|1098705|`find+-type+d`.split("\n")|code-block|syntax|javascript|1098706|目录和普通文件|1098707|`find+-type+d+-or+-type+f`.split("\n")`|1098708|纯净美丽的红宝石|1098709|require+"pathname"

def+rec_path(path,+file=+false)
++puts+path
++path.children.collect+do+%7Cchild%7C
++++if+file+and+child.file?
++++++child
++++elsif+child.directory?
++++++rec_path(child,+file)+%2B+[child]
++++end
++end.select+{+%7Cx%7C+x+}.flatten(1)
end

#+only+directories
rec_path(Pathname.new(dir),+false)
#+directories+and+normal+files
rec_path(Pathname.new(dir),+true)|1098710|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|V|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|W|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$]]|$1|O|3|P|5|F|7|Y|8|@]|9|@]|A|$G|H]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

<h1>Fast one liner</h1>

Only directories

<pre><code>`find -type d`.split("\n")
</code></pre>

Directories and normal files

<pre><code>`find -type d -or -type f`.split("\n")`
</code></pre>

<h1>Pure beautiful ruby</h1>

<pre><code>require "pathname"

def rec_path(path, file= false)
 puts path
 path.children.collect do |child|
 if file and child.file?
 child
 elsif child.directory?
 rec_path(child, file) + [child]
 end
 end.select { |x| x }.flatten(1)
end

# only directories
rec_path(Pathname.new(dir), false)
# directories and normal files
rec_path(Pathname.new(dir), true)
</code></pre>

blocks|key|1314443|text|正如在这里的其他答案中所指出的，您可以使用Dir.glob。请记住，文件夹中可能有许多奇怪的字符，而全局参数是模式，因此一些字符具有特殊的含义。因此，这样做是不安全的：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1314444|Dir.glob("#{folder}/**/*")|code-block|syntax|javascript|1314445|取而代之的是：|1314446|Dir.chdir(folder)+{+Dir.glob("**/*").map+{%7Cpath%7C+File.expand_path(path)+}+}|1314447|entityMap^0|L|8|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

As noted in other answers here, you can use <code>Dir.glob</code>. Keep in mind that folders can have lots of strange characters in them, and glob arguments are patterns, so some characters have special meanings. As such, it's unsafe to do something like the following:

<pre><code>Dir.glob("#{folder}/**/*")
</code></pre>

Instead do:

<pre><code>Dir.chdir(folder) { Dir.glob("**/*").map {|path| File.expand_path(path) } }
</code></pre>

blocks|key|1314107|text|在PHP或其他语言中，要获取目录及其所有子目录的内容，您必须编写几行代码，但在Ruby中只需两行：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1314108|require+'find'
Find.find('./')+do+%7Cf%7C+p+f+end|code-block|syntax|javascript|1314109|这将打印当前目录及其所有子目录的内容。|1314110|或者更短，您可以使用’**’表示法：|offset|length|style|CODE|1314111|p+Dir['**/*.*']|1314112|您会用PHP或Java编写多少行才能获得相同的结果？|1314113|entityMap^0|0|0|0|A|4|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|X|8|@$K|Y|L|Z|M|N]]|9|@]|A|$]]|$1|O|3|P|5|D|7|10|8|@]|9|@]|A|$E|F]]|$1|Q|3|R|5|6|7|11|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

In PHP or other languages to get the content of a directory and all its subdirectories, you have to write some lines of code, but in Ruby it takes 2 lines:

<pre><code>require 'find'
Find.find('./') do |f| p f end
</code></pre>

this will print the content of the current directory and all its subdirectories.

Or shorter, You can use the <code>’**’</code> notation :

<pre><code>p Dir['**/*.*']
</code></pre>

How many lines will you write in PHP or in Java to get the same result?

blocks|key|1099537|text|下面是一个将Rails项目目录的动态发现与Dir.glob相结合的示例：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1099538|dir+=+Dir.glob(Rails.root.join('app',+'assets',+'stylesheets',+'*'))|code-block|syntax|javascript|1099539|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here's an example that combines dynamic discovery of a Rails project directory with Dir.glob:

<pre><code>dir = Dir.glob(Rails.root.join('app', 'assets', 'stylesheets', '*'))
</code></pre>

blocks|key|1099251|text|虽然不是一行解决方案，但我认为这是使用ruby调用的最好方法。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1099252|首先递归删除所有文件|1099253|第二，删除所有的空目录|1099254|Dir.glob("./logs/**/*").each+{+%7Cfile%7C+File.delete(file)+if+File.file?+file+}
Dir.glob("./logs/**/*/").each+{+%7Cdirectory%7C+Dir.delete(directory)+}|code-block|syntax|javascript|1099255|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|O|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|P|8|@]|9|@]|A|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Although not a one line solution, I think this is the best way to do it using ruby calls.

First delete all the files recursively 
Second delete all the empty directories

<pre><code>Dir.glob("./logs/**/*").each { |file| File.delete(file) if File.file? file }
Dir.glob("./logs/**/*/").each { |directory| Dir.delete(directory) }
</code></pre>

blocks|key|1314250|text|Dir.open(Dir.pwd).map+{+%7Ch%7C+(File.file?(h)+?+"#{h}+-+file"+:+"#{h}+-+folder")+if+h[0]+!=+'.'+}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1314251|点返回nil，使用紧凑|unstyled|1314252|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>Dir.open(Dir.pwd).map { |h| (File.file?(h) ? "#{h} - file" : "#{h} - folder") if h[0] != '.' }
</code></pre>

dots return nil, use compact

What is the fastest, most optimized, one-liner way to get an array of the directories (excluding files) in Ruby? 

How about including files?

One-liner to recursively list directories in Ruby?

Java

Unix

在Ruby中获取目录(不包括文件)数组的最快、最优化、一行的方法是什么？包含文件怎么样？

问在Ruby中递归列出目录的一行程序？
EN

回答 9

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问在Ruby中递归列出目录的一行程序？EN

回答 9

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问在Ruby中递归列出目录的一行程序？
EN