blocks|key|1147143|text|+require+'ftools'|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1147144|File.makedirs|unstyled|offset|length|1147145|entityMap|0|LINK|mutability|MUTABLE|url|http://ruby-doc.org/core/classes/File.html#M002586^0|0|0|D|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|R|8|@]|9|@$G|S|H|T|1|U]]|A|$]]|$1|I|3|-4|5|F|7|V|8|@]|9|@]|A|$]]]|J|$K|$5|L|M|N|A|$O|P]]]]

<pre><code> require 'ftools'
</code></pre>

<a href="http://ruby-doc.org/core/classes/File.html#M002586" rel="nofollow noreferrer">File.makedirs</a>

blocks|key|932774|text|使用mkdir_p|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|932775|FileUtils.mkdir_p+'/a/b/c'|code-block|syntax|javascript|932776|_p是父/路径的unix保留项，如果对您更有意义，还可以使用别名mkpath。|932777|FileUtils.mkpath+'/a/b/c'|932778|在Ruby1.9中，FileUtils已从内核中移除，因此您必须使用require+'fileutils'。|932779|entityMap|0|LINK|mutability|MUTABLE|url|http://www.ruby-doc.org/stdlib/libdoc/fileutils/rdoc/FileUtils.html#method-c-mkdir_p|1|http://www.ruby-doc.org/stdlib/libdoc/fileutils/rdoc/FileUtils.html#method-c-mkdir^0|2|7|2|7|0|0|0|0|2|W|6|W|6|1|0|0|Y|J|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@$9|13|A|14|1|15]]|E|$]]|$1|F|3|G|5|H|7|16|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|17|8|@$9|18|A|19|B|C]|$9|1A|A|1B|B|C]]|D|@$9|1C|A|1D|1|1E]]|E|$]]|$1|M|3|N|5|H|7|1F|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|1G|8|@$9|1H|A|1I|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|1J|8|@]|D|@]|E|$]]]|R|$S|$5|T|U|V|E|$W|X]]|Y|$5|T|U|V|E|$W|Z]]]]

Use <a href="http://www.ruby-doc.org/stdlib/libdoc/fileutils/rdoc/FileUtils.html#method-c-mkdir_p" rel="noreferrer"><code>mkdir_p</code></a>:

<pre><code>FileUtils.mkdir_p '/a/b/c'
</code></pre>

The <code>_p</code> is a unix holdover for parent/path you can also use the alias <a href="http://www.ruby-doc.org/stdlib/libdoc/fileutils/rdoc/FileUtils.html#method-c-mkdir" rel="noreferrer"><code>mkpath</code></a> if that makes more sense for you.

<pre><code>FileUtils.mkpath '/a/b/c'
</code></pre>

In Ruby 1.9 FileUtils was removed from the core, so you'll have to <code>require 'fileutils'</code>.

blocks|key|1147281|text|如果你在unixy机器上运行，别忘了你总是可以在ruby下运行shell命令，只需要把它放在反引号里。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1147282|`mkdir+-p+/a/b/c`|code-block|syntax|javascript|1147283|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you are running on unixy machines, don't forget you can always run a shell command under ruby by placing it in backticks.

<pre><code>`mkdir -p /a/b/c`
</code></pre>

blocks|key|932939|text|使用mkdir_p递归创建目录|type|unstyled|depth|inlineStyleRanges|entityRanges|data|932940|path+=+"/tmp/a/b/c"

FileUtils.mkdir_p(path)+unless+File.exists?(path)|code-block|syntax|javascript|932941|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Use mkdir_p to create directory recursively

<pre><code>path = "/tmp/a/b/c"

FileUtils.mkdir_p(path) unless File.exists?(path)
</code></pre>

blocks|key|1147398|text|你也可以使用你自己的逻辑|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1147399|def+self.create_dir_if_not_exists(path)
++recursive+=+path.split('/')
++directory+=+''
++recursive.each+do+%7Csub_directory%7C
++++directory+%2B=+sub_directory+%2B+'/'
++++Dir.mkdir(directory)+unless+(File.directory?+directory)
++end
end|code-block|syntax|javascript|1147400|因此，如果路径是'tmp/a/b/c‘，如果'tmp’不存在，则会创建'tmp‘，然后是'tmp/a/’，依此类推。|1147401|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You could also use your own logic

<pre><code>def self.create_dir_if_not_exists(path)
 recursive = path.split('/')
 directory = ''
 recursive.each do |sub_directory|
 directory += sub_directory + '/'
 Dir.mkdir(directory) unless (File.directory? directory)
 end
end
</code></pre>

So if path is 'tmp/a/b/c'
if 'tmp' doesn't exist 'tmp' gets created, then 'tmp/a/' and so on and so forth.

blocks|key|1147406|text|Pathname出手相救！|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1147407|Pathname('/a/b/c/d.txt').dirname.mkpath|code-block|syntax|javascript|1147408|entityMap|0|LINK|mutability|MUTABLE|url|https://ruby-doc.org/stdlib-2.5.3/libdoc/pathname/rdoc/Pathname.html^0|0|8|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

<a href="https://ruby-doc.org/stdlib-2.5.3/libdoc/pathname/rdoc/Pathname.html" rel="nofollow noreferrer">Pathname</a> to the rescue!

<pre><code>Pathname('/a/b/c/d.txt').dirname.mkpath
</code></pre>

I want to store a file as /a/b/c/d.txt, but I do not know if any of these directories exist and need to recursively create them if necessary.
How can one do this in ruby?

How to create directories recursively in ruby?

文件存储

我希望将文件存储为/a/b/c/d.txt，但是我不知道这些目录中是否存在，如果需要，需要递归地创建它们。如何在ruby中做到这一点？

问如何在ruby中递归创建目录？
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