blocks|key|3315858|text|在C#中，与VB.NET和Java不同，您不能使用实例语法访问static成员。您应该执行以下操作：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3315859|MyClass.MyItem.Property1|code-block|syntax|javascript|3315860|引用该属性或从Property1中删除static修饰符(这可能是您想要做的)。以获得关于static+is,+see+my+other+answer的概念。|3315861|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/413898/what-does-the-static-keyword-do-in-java/413904#413904^0|V|6|0|0|7|9|J|6|19|6|19|U|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|C]|$9|13|A|14|B|C]]|D|@$9|15|A|16|1|17]]|E|$]]|$1|M|3|-4|5|6|7|18|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]]]

In C#, unlike VB.NET and Java, you can't access <code>static</code> members with instance syntax. You should do:

<pre><code>MyClass.MyItem.Property1
</code></pre>

to refer to that property or remove the <code>static</code> modifier from <code>Property1</code> (which is what you probably want to do). For a conceptual idea about what <a href="https://stackoverflow.com/questions/413898/what-does-the-static-keyword-do-in-java/413904#413904"><code>static</code> is, see my other answer</a>.

blocks|key|3315882|text|只能使用类型的名称访问静态成员。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3315883|因此，您需要编写以下代码，|3315884|MyClass.MyItem.Property1|code-block|syntax|javascript|3315885|或者(这可能是您需要做的)通过从其定义中删除static关键字来使Property1成为实例属性。|offset|length|style|CODE|3315886|静态属性在其类的所有实例之间共享，因此它们只有一个值。按照现在的定义方式，创建MyItem类的任何实例都没有意义。|3315887|entityMap^0|0|0|0|M|6|X|9|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|V|8|@$K|W|L|X|M|N]|$K|Y|L|Z|M|N]]|9|@]|A|$]]|$1|O|3|P|5|6|7|10|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|R|$]]

You can only access static members using the name of the type.

Therefore, you need to either write,

<pre><code>MyClass.MyItem.Property1
</code></pre>

Or (this is probably what you need to do) make <code>Property1</code> an instance property by removing the <code>static</code> keyword from its definition.

Static properties are shared between all instances of their class, so that they only have one value. The way it's defined now, there is no point in making any instances of your MyItem class.

blocks|key|3315976|text|我也遇到了同样的问题--尽管几年后，有些人可能会发现一些提示很有帮助：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3315977|不要无端使用‘static’！|3315978|理解“静态”在运行时和编译时语义(行为)和语法方面的含义。|3315979|3315980|静态实体将在一段时间之前自动构建|unordered-list-item|3315981|3315982|它的第一个用法。|3315983|静态实体分配了一个存储位置，即|3315984|3315985|由访问该实体的所有用户共享。|3315986|静态实体只能通过其类型名称进行访问，而不是|3315987|3315988|3315989|静态方法没有隐式的‘this’参数，实例方法也没有。(因此静态方法的执行次数较少|3315990|3315991|开销-使用它们的一个原因。)|3315992|在使用静态实体时考虑线程安全。|3315993|3315994|关于MSDN中的静态的一些细节：|3315995|3315996|Static+Classes+in+C#|offset|length|3315997|Static+Constructors+in+C#|3315998|3315999|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/79b3xss3(v=vs.90).aspx|1|http://msdn.microsoft.com/en-us/library/k9x6w0hc(v=vs.90).aspx^0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|K|0|0|0|P|1|0|0^^$0|@$1|2|3|4|5|6|7|1N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|1O|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|1P|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|1Q|8|@]|9|@]|A|$]]|$1|G|3|H|5|I|7|1R|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|1S|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|1T|8|@]|9|@]|A|$]]|$1|M|3|N|5|I|7|1U|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|1V|8|@]|9|@]|A|$]]|$1|P|3|Q|5|6|7|1W|8|@]|9|@]|A|$]]|$1|R|3|S|5|I|7|1X|8|@]|9|@]|A|$]]|$1|T|3|-4|5|6|7|1Y|8|@]|9|@]|A|$]]|$1|U|3|-4|5|6|7|1Z|8|@]|9|@]|A|$]]|$1|V|3|W|5|I|7|20|8|@]|9|@]|A|$]]|$1|X|3|-4|5|6|7|21|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|6|7|22|8|@]|9|@]|A|$]]|$1|10|3|11|5|I|7|23|8|@]|9|@]|A|$]]|$1|12|3|-4|5|6|7|24|8|@]|9|@]|A|$]]|$1|13|3|14|5|6|7|25|8|@]|9|@]|A|$]]|$1|15|3|-4|5|6|7|26|8|@]|9|@]|A|$]]|$1|16|3|17|5|I|7|27|8|@]|9|@$18|28|19|29|1|2A]]|A|$]]|$1|1A|3|1B|5|I|7|2B|8|@]|9|@$18|2C|19|2D|1|2E]]|A|$]]|$1|1C|3|-4|5|6|7|2F|8|@]|9|@]|A|$]]|$1|1D|3|-4|5|6|7|2G|8|@]|9|@]|A|$]]]|1E|$1F|$5|1G|1H|1I|A|$1J|1K]]|1L|$5|1G|1H|1I|A|$1J|1M]]]]

I had the same issue - although a few years later, some may find a few pointers helpful:

Do not use ‘static’ gratuitously! 

Understand what ‘static’ implies in terms of both run-time and compile time semantics (behavior) and syntax. 

<ul>
<li>A static entity will be automatically constructed some time before 
its first use.</li>
<li>A static entity has one storage location allocated, and that is 
shared by all who access that entity.</li>
<li>A static entity can only be accessed through its type name, not 
through an instance of that type.</li>
<li>A static method does not have an implicit ‘this’ argument, as does an
instance method. (And therefore a static method has less execution 
overhead – one reason to use them.)</li>
<li>Think about thread safety when using static entities.</li>
</ul>

Some details on static in MSDN:

<ul>
<li><a href="http://msdn.microsoft.com/en-us/library/79b3xss3(v=vs.90).aspx">Static Classes in C#</a></li>
<li><a href="http://msdn.microsoft.com/en-us/library/k9x6w0hc(v=vs.90).aspx">Static Constructors in C#</a></li>
</ul>

blocks|key|3316031|text|检查您的代码是否包含一个名称空间，该名称空间最右边的部分与静态类名称匹配。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3316032|给定在命名空间Foo上定义的静态跳跃栏类，实现方法跳转或属性，您可能会收到编译器错误，因为还有另一个命名空间以栏结尾。是的，fishi的东西;-)|offset|length|style|BOLD|3316033|如果是这样，这意味着您使用了一个使用Bar的；和一个Bar.Jump()调用，因此以下解决方案之一应该满足您的需求：|3316034|在Foo.Bar.Jump()声明中，|3316035|使用相应命名空间完全限定静态类名。您还需要使用Bar;+statement|unordered-list-item|3316036|Rename+namespace+Bar+by+a+diffente+name来删除名称。|3316037|3316038|在我的例子中，在一次Database.SetInitializer()调用中，EF+(Entity+Framework)存储库项目出现了愚蠢的编译器错误：|3316039|Member+'Database.SetInitializer<MyDatabaseContext>(IDatabaseInitializer<MyDatabaseContext>)'+cannot+be+accessed+with+an+instance+reference;+qualify+it+with+a+type+name+instead+MyProject.ORM|code-block|syntax|javascript|3316040|这个错误是在添加MyProject.ORM.Database名称空间时引起的，正如您可能注意到的，sufix+(数据库)与Database.SetInitializer类名称相匹配。|3316041|在这种情况下，由于我无法控制EF的数据库静态类，并且我还想保留我的自定义命名空间，因此我决定使用其命名空间System.Data.Entity，完全限定EF的数据库静态类，这导致使用以下命令，编译成功：|3316042|System.Data.Entity.Database.SetInitializer<MyDatabaseContext>(MyMigrationStrategy)|3316043|希望能有所帮助|3316044|entityMap^0|0|7|3|P|2|1J|1|0|M|1|Q|A|0|1|E|0|0|H|3|0|0|A|P|13|2|17|G|0|0|8|M|1K|3|1P|N|0|H|3|1H|I|0|0|0^^$0|@$1|2|3|4|5|6|7|18|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|19|8|@$D|1A|E|1B|F|G]|$D|1C|E|1D|F|G]|$D|1E|E|1F|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|1G|8|@$D|1H|E|1I|F|G]|$D|1J|E|1K|F|G]]|9|@]|A|$]]|$1|J|3|K|5|6|7|1L|8|@$D|1M|E|1N|F|G]]|9|@]|A|$]]|$1|L|3|M|5|N|7|1O|8|@]|9|@]|A|$]]|$1|O|3|P|5|N|7|1P|8|@$D|1Q|E|1R|F|G]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|1S|8|@]|9|@]|A|$]]|$1|R|3|S|5|6|7|1T|8|@$D|1U|E|1V|F|G]|$D|1W|E|1X|F|G]|$D|1Y|E|1Z|F|G]]|9|@]|A|$]]|$1|T|3|U|5|V|7|20|8|@]|9|@]|A|$W|X]]|$1|Y|3|Z|5|6|7|21|8|@$D|22|E|23|F|G]|$D|24|E|25|F|G]|$D|26|E|27|F|G]]|9|@]|A|$]]|$1|10|3|11|5|6|7|28|8|@$D|29|E|2A|F|G]|$D|2B|E|2C|F|G]]|9|@]|A|$]]|$1|12|3|13|5|V|7|2D|8|@]|9|@]|A|$W|X]]|$1|14|3|15|5|6|7|2E|8|@]|9|@]|A|$]]|$1|16|3|-4|5|6|7|2F|8|@]|9|@]|A|$]]]|17|$]]

Check whether your code contains a namespace which the right most part matches your static class name.

Given the a static Bar class, defined on namespace Foo, implementing a method Jump or a property, chances are you are receiving compiler error because there is also another namespace ending on Bar. Yep, fishi stuff ;-)

If that's so, it means your using a Using Bar; and a Bar.Jump() call, therefore one of the following solutions should fit your needs:

<ul>
<li>Fully qualify static class name with according namepace, which result on Foo.Bar.Jump() declaration. You will also need to remove Using Bar; statement</li>
<li>Rename namespace Bar by a diffente name.</li>
</ul>

In my case, the foollowing compiler error occurred on a EF (Entity Framework) repository project on an Database.SetInitializer() call:

<pre><code>Member 'Database.SetInitializer&lt;MyDatabaseContext&gt;(IDatabaseInitializer&lt;MyDatabaseContext&gt;)' cannot be accessed with an instance reference; qualify it with a type name instead MyProject.ORM
</code></pre>

This error arouse when I added a MyProject.ORM.Database namespace, which sufix (Database), as you might noticed, matches Database.SetInitializer class name.

In this, since I have no control on EF's Database static class and I would also like to preserve my custom namespace, I decided fully qualify EF's Database static class with its namepace System.Data.Entity, which resulted on using the following command, which compilation succeed:

<pre><code>System.Data.Entity.Database.SetInitializer&lt;MyDatabaseContext&gt;(MyMigrationStrategy)
</code></pre>

Hope it helps

blocks|key|3103211|text|我在这里通过谷歌搜索C#编译器错误问题，通过(复制)+CS0176+Static+member+instance+reference+issue。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3103212|在我的例子中，错误发生是因为我有一个静态方法和一个同名的扩展方法。有关这一点，请参阅Static+method+and+extension+method+with+same+name。|3103213|也许这应该是一个评论。对不起，我还没有足够的名气。|3103214|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/q/21019492|1|https://stackoverflow.com/q/34317817^0|Y|12|0|0|16|1D|1|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@$A|S|B|T|1|U]]|C|$]]|$1|D|3|E|5|6|7|V|8|@]|9|@$A|W|B|X|1|Y]]|C|$]]|$1|F|3|G|5|6|7|Z|8|@]|9|@]|C|$]]|$1|H|3|-4|5|6|7|10|8|@]|9|@]|C|$]]]|I|$J|$5|K|L|M|C|$N|O]]|P|$5|K|L|M|C|$N|Q]]]]

I got here googling for C# compiler error CS0176, through (duplicate) question <a href="https://stackoverflow.com/q/21019492">Static member instance reference issue</a>. 

In my case, the error happened because I had a static method and an extension method with the same name. For that, see <a href="https://stackoverflow.com/q/34317817">Static method and extension method with same name</a>.

[May be this should have been a comment. Sorry that I don't have enough reputation yet.]

blocks|key|3316087|text|我知道这是一个老帖子，但我刚刚花了3个小时试图弄清楚我的问题是什么。我通常知道这个错误是什么意思，但您也可以以更微妙的方式遇到这个错误。我的问题是我的客户机类(从实例类调用静态方法的那个类)有一个不同类型的属性，但命名与静态方法相同。编译器报告的错误与这里报告的错误相同，但问题基本上是名称冲突。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3316088|对于得到此错误的其他任何人，尝试使用名称空间名称完全限定您的实例类。..()，这样编译器就可以看到您所指的确切名称。|3316089|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

I know this is an old thread, but I just spent 3 hours trying to figure out what my issue was. I ordinarily know what this error means, but you can run into this in a more subtle way as well. My issue was my client class (the one calling a static method from an instance class) had a property of a different type but named the same as the static method. The error reported by the compiler was the same as reported here, but the issue was basically name collision. 

For anyone else getting this error and none of the above helps, try fully qualifying your instance class with the namespace name. ..() so the compiler can see the exact name you mean.

blocks|key|340118|text|在这种情况下，不需要使用static，因为已经详细解释过了。你最好在不使用GetItem()方法的情况下初始化你的属性，下面是两者的例子：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|340119|namespace+MyNamespace
{
++++using+System;

++++public+class+MyType
++++{
++++++++public+string+MyProperty+{+get;+set;+}+=+new+string();
++++++++public+static+string+MyStatic+{+get;+set;+}+=+"I'm+static";
++++}
}|code-block|syntax|javascript|340120|消费：|340121|using+MyType;

public+class+Somewhere+
{
++++public+void+Consuming(){

++++++++//+through+instance+of+your+type
++++++++var+myObject+=+new+MyType();+
++++++++var+alpha+=+myObject.MyProperty;

++++++++//+through+your+type+
++++++++var+beta+=+MyType.MyStatic;
++++}
}+++++++|340122|entityMap^0|11|9|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

No need to use static in this case as thoroughly explained. You might as well initialise your property without <code>GetItem()</code> method, example of both below:

<pre><code>namespace MyNamespace
{
 using System;

 public class MyType
 {
 public string MyProperty { get; set; } = new string();
 public static string MyStatic { get; set; } = "I'm static";
 }
}
</code></pre>

Consuming:

<pre><code>using MyType;

public class Somewhere 
{
 public void Consuming(){

 // through instance of your type
 var myObject = new MyType(); 
 var alpha = myObject.MyProperty;

 // through your type 
 var beta = MyType.MyStatic;
 }
} 
</code></pre>

blocks|key|3316111|text|YourClassName.YourStaticFieldName|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3316112|对于静态字段，如下所示：|unstyled|3316113|public+class+StaticExample+
{
+++public+static+double+Pi+=+3.14;
}|3316114|从另一个类中，您可以访问staic字段，如下所示：|3316115|++++class+Program
++++{
+++++static+void+Main(string[]+args)
+++++{
+++++++++double+radius+=+6;
+++++++++double+areaOfCircle+=+0;

+++++++++areaOfCircle+=+StaticExample.Pi+*+radius+*+radius;
+++++++++Console.WriteLine("Area+=+"%2BareaOfCircle);

+++++++++Console.ReadKey();
+++++}
++}|3316116|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|P|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|I|3|J|5|F|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$B|C]]|$1|M|3|-4|5|F|7|T|8|@]|9|@]|A|$]]]|N|$]]

<pre><code>YourClassName.YourStaticFieldName
</code></pre>

For your static field would look like:

<pre><code>public class StaticExample 
{
 public static double Pi = 3.14;
}
</code></pre>

From another class, you can access the staic field as follows:

<pre><code> class Program
 {
 static void Main(string[] args)
 {
 double radius = 6;
 double areaOfCircle = 0;

 areaOfCircle = StaticExample.Pi * radius * radius;
 Console.WriteLine("Area = "+areaOfCircle);

 Console.ReadKey();
 }
 }
</code></pre>

blocks|key|336703|text|这会导致以下错误：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|336704|MyClass+aCoolObj+=+new+MyClass();
aCoolObj.MyCoolStaticMethod();|code-block|syntax|javascript|336705|修复方法如下：|336706|MyClass.MyCoolStaticMethod();|336707|解释：|336708|不能从对象的实例调用静态方法。静态方法的全部要点不是绑定到对象的实例，而是在该对象的所有实例中持久化，和/或在没有该对象的任何实例的情况下使用。|336709|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

This causes the error:

<pre><code>MyClass aCoolObj = new MyClass();
aCoolObj.MyCoolStaticMethod();
</code></pre>

This is the fix:

<pre><code>MyClass.MyCoolStaticMethod();
</code></pre>

Explanation:

You can't call a static method from an instance of an object. The whole point of static methods is to not be tied to instances of objects, but instead to persist through all instances of that object, and/or to be used without any instances of the object.

blocks|key|3103309|text|删除您试图调用的函数中的静态变量。这为我解决了这个问题。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3103310|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Remove the static in the function you are trying to call. This fixed the problem for me.

I am getting into C# and I am having this issue:

<pre><code>namespace MyDataLayer
{
 namespace Section1
 {
 public class MyClass
 {
 public class MyItem
 {
 public static string Property1{ get; set; }
 }
 public static MyItem GetItem()
 {
 MyItem theItem = new MyItem();
 theItem.Property1 = "MyValue";
 return theItem;
 }
 }
 }
 }
</code></pre>

I have this code on a UserControl:

<pre><code>using MyDataLayer.Section1;

public class MyClass
{
 protected void MyMethod
 {
 MyClass.MyItem oItem = new MyClass.MyItem();
 oItem = MyClass.GetItem();
 someLiteral.Text = oItem.Property1;
 }
}
</code></pre>

Everything works fine, except when I go to access <code>Property1</code>. The intellisense only gives me "<code>Equals</code>, <code>GetHashCode</code>, <code>GetType</code>, and <code>ToString</code>" as options. When I mouse over the <code>oItem.Property1</code>, Visual Studio gives me this explanation:

<blockquote>
 <code>Member</code>MyDataLayer.Section1.MyClass.MyItem.Property1.get<code>cannot be accessed with an instance reference, qualify it with a type name instead</code>
</blockquote>

I am unsure of what this means, I did some googling but wasn't able to figure it out.

Member '<member name>' cannot be accessed with an instance reference

Visual Studio

数据库

编译器

Java

我正在进入C#，我遇到了这个问题：namespace MyDataLayer{    namespace Section1    {        public class MyClass        {            public class MyItem            {             ...

问无法使用实例引用访问成员“< Member name>”
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问无法使用实例引用访问成员“< Member name>”
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