blocks|key|699712|text|您可以弹出最后一项，然后将其与文本连接起来：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|699713|$yourArray+=+('a',+'b',+'c');
$lastItem+=+array_pop($yourArray);+//+c
$text+=+implode(',+',+$yourArray);+//+a,+b
$text+.=+'+and+'.$lastItem;+//+a,+b+and+c|code-block|syntax|javascript|699714|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can pop last item and then join it with the text:

<pre><code>$yourArray = ('a', 'b', 'c');
$lastItem = array_pop($yourArray); // c
$text = implode(', ', $yourArray); // a, b
$text .= ' and '.$lastItem; // a, b and c
</code></pre>

blocks|key|483864|text|尝尝这个,|type|unstyled|depth|inlineStyleRanges|entityRanges|data|483865|<?php
$listArray+=+array("coke","sprite","fanta");

foreach($listArray+as+$key+=>+$value)
{
+if(count($listArray)-1+==+$key)
++echo+"and+"+.+$value;
+else+if(count($listArray)-2+==+$key)
++echo+$value+.+"+";
+else
++echo+$value+.+",+";
}
?>|code-block|syntax|javascript|483866|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try this,

<pre><code>&lt;?php
$listArray = array("coke","sprite","fanta");

foreach($listArray as $key =&gt; $value)
{
 if(count($listArray)-1 == $key)
 echo "and " . $value;
 else if(count($listArray)-2 == $key)
 echo $value . " ";
 else
 echo $value . ", ";
}
?&gt;
</code></pre>

blocks|key|483873|text|尝尝这个|type|unstyled|depth|inlineStyleRanges|entityRanges|data|483874|$arr+=+Array("coke","sprite","fanta");
$str+=+"";
$lenArr+=+sizeof($arr);
for($i=0;+$i<$lenArr;+$i%2B%2B)
{
++++if($i==0)
++++++++$str+.=+$arr[$i];
++++else+if($i==($lenArr-1))
++++++++$str+.=+"+and+".$arr[$i];
++++else
++++++++$str+.=+"+,+".$arr[$i];
}
print_r($str);|code-block|syntax|javascript|483875|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

try this

<pre><code>$arr = Array("coke","sprite","fanta");
$str = "";
$lenArr = sizeof($arr);
for($i=0; $i&lt;$lenArr; $i++)
{
 if($i==0)
 $str .= $arr[$i];
 else if($i==($lenArr-1))
 $str .= " and ".$arr[$i];
 else
 $str .= " , ".$arr[$i];
}
print_r($str);
</code></pre>

blocks|key|699787|text|它比deceze的解决方案更快，并且可以处理大型数组(1M%2B元素)。这两种解决方案的唯一缺陷是由于array_filter的使用，在少于三个元素的数组中与数字0的交互很差。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|699788|echo+implode('+and+',+array_filter(array_reverse(array_merge(array(array_pop($array)),+array(implode(',+',$array))))));|code-block|syntax|javascript|699789|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

It's faster then deceze's solution and works with huge arrays (1M+ elements). The only flaw of both solutions is a poor interaction with a number 0 in a less then three elements arrays becouse of array_filter use.

<pre><code>echo implode(' and ', array_filter(array_reverse(array_merge(array(array_pop($array)), array(implode(', ',$array))))));
</code></pre>

blocks|key|699867|text|我知道我来晚了，但这肯定是一种更好的方式？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|699868|$list+=+array('breakfast',+'lunch',+'dinner');
$list[count($list)-1]+=+"and+"+.+$list[count($list)-1];
echo+implode(',+',+$list);|code-block|syntax|javascript|699869|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I know im way to late for the answer, but surely this is a better way of doing it?

<pre><code>$list = array('breakfast', 'lunch', 'dinner');
$list[count($list)-1] = "and " . $list[count($list)-1];
echo implode(', ', $list);
</code></pre>

blocks|key|699885|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|699886|$str+=+array_pop($array);
if+($array)
++++$str+=+implode(',+',+$array)."+and+".$str;|code-block|syntax|javascript|699887|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try this:

<pre><code>$str = array_pop($array);
if ($array)
 $str = implode(', ', $array)." and ".$str;
</code></pre>

blocks|key|699951|text|另一种可能的简短解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|699952|$values+=+array('coke',+'sprite',+'fanta');

$values[]+=+implode('+and+',+array_splice($values,+-2));
print+implode(',+',+$values);++//+"coke,+sprite+and+fanta"|code-block|syntax|javascript|699953|它可以很好地处理任意数量的值。|699954|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Another possible short solution:

<pre><code>$values = array('coke', 'sprite', 'fanta');

$values[] = implode(' and ', array_splice($values, -2));
print implode(', ', $values); // "coke, sprite and fanta"
</code></pre>

It works fine with any number of values.

blocks|key|484205|text|我不确定one+liner是这个问题最优雅的解决方案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|484206|我在一段时间前写了这段代码，并根据需要将其放入：|484207|/**
+*+Join+a+string+with+a+natural+language+conjunction+at+the+end.+
+*+https://gist.github.com/angry-dan/e01b8712d6538510dd9c
+*/
function+natural_language_join(array+$list,+$conjunction+=+'and')+{
++$last+=+array_pop($list);
++if+($list)+{
++++return+implode(',+',+$list)+.+'+'+.+$conjunction+.+'+'+.+$last;
++}
++return+$last;
}|code-block|syntax|javascript|484208|您不必使用"+and“作为您的连接字符串，它是有效的，可以处理从0到无限数量的任何项：|484209|//+null
var_dump(natural_language_join(array()));
//+string+'one'
var_dump(natural_language_join(array('one')));
//+string+'one+and+two'
var_dump(natural_language_join(array('one',+'two')));
//+string+'one,+two+and+three'
var_dump(natural_language_join(array('one',+'two',+'three')));
//+string+'one,+two,+three+or+four'
var_dump(natural_language_join(array('one',+'two',+'three',+'four'),+'or'));|484210|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

I'm not sure that a one liner is the most elegant solution to this problem.

I wrote this a while ago and drop it in as required:

<pre><code>/**
 * Join a string with a natural language conjunction at the end. 
 * https://gist.github.com/angry-dan/e01b8712d6538510dd9c
 */
function natural_language_join(array $list, $conjunction = 'and') {
 $last = array_pop($list);
 if ($list) {
 return implode(', ', $list) . ' ' . $conjunction . ' ' . $last;
 }
 return $last;
}
</code></pre>

You don't have to use "and" as your join string, it's efficient and works with anything from 0 to an unlimited number of items:

<pre><code>// null
var_dump(natural_language_join(array()));
// string 'one'
var_dump(natural_language_join(array('one')));
// string 'one and two'
var_dump(natural_language_join(array('one', 'two')));
// string 'one, two and three'
var_dump(natural_language_join(array('one', 'two', 'three')));
// string 'one, two, three or four'
var_dump(natural_language_join(array('one', 'two', 'three', 'four'), 'or'));
</code></pre>

blocks|key|484265|text|我只是根据这个页面上的建议进行了编码。我在注释中留下了我的伪代码，以防有人需要它。我的代码与这里的其他代码不同，因为它以不同的方式处理不同大小的数组，并且对三个或更多的列表使用牛津逗号表示法。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|484266|++++/**
+++++*+Create+a+comma+separated+list+of+items+using+the+Oxford+comma+notation.++A
+++++*+single+item+returns+just+that+item.++2+array+elements+returns+the+items
+++++*+separated+by+"and".++3+or+more+items+return+the+comma+separated+list.
+++++*
+++++*+@param+array+$items+Array+of+strings+to+list
+++++*+@return+string+List+of+items+joined+by+comma+using+Oxford+comma+notation
+++++*/
++++function+_createOxfordCommaList($items)+{
++++++++if+(count($items)+==+1)+{
++++++++++++//+return+the+single+name
++++++++++++return+array_pop($items);
++++++++}
++++++++elseif+(count($items)+==+2)+{
++++++++++++//+return+array+joined+with+"and"
++++++++++++return+implode("+and+",+$items);
++++++++}
++++++++else+{
++++++++++++//+pull+of+the+last+item
++++++++++++$last+=+array_pop($items);

++++++++++++//+join+remaining+list+with+commas
++++++++++++$list+=+implode(",+",+$items);

++++++++++++//+add+the+last+item+back+using+",+and"
++++++++++++$list+.=+",+and+"+.+$last;

++++++++++++return+$list;
++++++++}
++++}|code-block|syntax|javascript|484267|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I just coded this based on the suggestions on this page. I left in my pseudo-code in the comments in case anyone needed it. My code differs from others here as it handles different-sized arrays differently and uses the Oxford comma notation for lists of three or more.

<pre><code> /**
 * Create a comma separated list of items using the Oxford comma notation. A
 * single item returns just that item. 2 array elements returns the items
 * separated by "and". 3 or more items return the comma separated list.
 *
 * @param array $items Array of strings to list
 * @return string List of items joined by comma using Oxford comma notation
 */
 function _createOxfordCommaList($items) {
 if (count($items) == 1) {
 // return the single name
 return array_pop($items);
 }
 elseif (count($items) == 2) {
 // return array joined with "and"
 return implode(" and ", $items);
 }
 else {
 // pull of the last item
 $last = array_pop($items);

 // join remaining list with commas
 $list = implode(", ", $items);

 // add the last item back using ", and"
 $list .= ", and " . $last;

 return $list;
 }
 }
</code></pre>

blocks|key|484339|text|这在这一点上是相当陈旧的，但我认为将我的解决方案添加到堆中并不会有什么坏处。与其他解决方案相比，它的代码要多一点，但我对此没有意见。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|484340|我想要一些灵活性的东西，所以我创建了一个实用方法，允许设置最后的分隔符应该是什么(例如，您可以使用&符号)以及是否使用牛津逗号。它还可以正确地处理包含0、1和2项的列表(这里的一些答案做不到的事情)|484341|$androidVersions+=+['Donut',+'Eclair',+'Froyo',+'Gingerbread',+'Honeycomb',+'Ice+Cream+Sandwich',+'Jellybean',+'Kit+Kat',+'Lollipop',+'Marshmallow'];

echo+joinListWithFinalSeparator(array_slice($androidVersions,+0,+1));+//+Donut
echo+joinListWithFinalSeparator(array_slice($androidVersions,+0,+2));+//+Donut+and+Eclair
echo+joinListWithFinalSeparator($androidVersions);+//+Donut,+Eclair,+Froyo,+Gingerbread,+Honeycomb,+Ice+Cream+Sandwich,+Jellybean,+Kit+Kat,+Lollipop,+and+Marshmallow
echo+joinListWithFinalSeparator($androidVersions,+'&',+false);+//+Donut,+Eclair,+Froyo,+Gingerbread,+Honeycomb,+Ice+Cream+Sandwich,+Jellybean,+Kit+Kat,+Lollipop+&+Marshmallow

function+joinListWithFinalSeparator(array+$arr,+$lastSeparator+=+'and',+$oxfordComma+=+true)+{
++++if+(count($arr)+>+1)+{
++++++++return+sprintf(
++++++++++++'%25s%25s+%25s+%25s',+
++++++++++++implode(',+',+array_slice($arr,+0,+-1)),
++++++++++++$oxfordComma+&&+count($arr)+>+2+?+',':'',
++++++++++++$lastSeparator+?:+'',+
++++++++++++array_pop($arr)
++++++++);
++++}

++++//+not+a+fan+of+this,+but+it's+the+simplest+way+to+return+a+string+from+an+array+of+0-1+items+without+warnings
++++return+implode('',+$arr);
}|code-block|syntax|javascript|484342|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

This is quite old at this point, but I figured it can't hurt to add my solution to the pile. It's a bit more code than other solutions, but I'm okay with that.

I wanted something with a bit of flexibility, so I created a utility method that allows for setting what the final separator should be (so you could use an ampersand, for instance) and whether or not to use an Oxford comma. It also properly handles lists with 0, 1, and 2 items (something quite a few of the answers here do not do)

<pre><code>$androidVersions = ['Donut', 'Eclair', 'Froyo', 'Gingerbread', 'Honeycomb', 'Ice Cream Sandwich', 'Jellybean', 'Kit Kat', 'Lollipop', 'Marshmallow'];

echo joinListWithFinalSeparator(array_slice($androidVersions, 0, 1)); // Donut
echo joinListWithFinalSeparator(array_slice($androidVersions, 0, 2)); // Donut and Eclair
echo joinListWithFinalSeparator($androidVersions); // Donut, Eclair, Froyo, Gingerbread, Honeycomb, Ice Cream Sandwich, Jellybean, Kit Kat, Lollipop, and Marshmallow
echo joinListWithFinalSeparator($androidVersions, '&amp;', false); // Donut, Eclair, Froyo, Gingerbread, Honeycomb, Ice Cream Sandwich, Jellybean, Kit Kat, Lollipop &amp; Marshmallow

function joinListWithFinalSeparator(array $arr, $lastSeparator = 'and', $oxfordComma = true) {
 if (count($arr) &gt; 1) {
 return sprintf(
 '%s%s %s %s', 
 implode(', ', array_slice($arr, 0, -1)),
 $oxfordComma &amp;&amp; count($arr) &gt; 2 ? ',':'',
 $lastSeparator ?: '', 
 array_pop($arr)
 );
 }

 // not a fan of this, but it's the simplest way to return a string from an array of 0-1 items without warnings
 return implode('', $arr);
}
</code></pre>

blocks|key|700218|text|好吧，这已经变得相当陈旧了，但我不得不说，我认为大多数的答案都是非常低效的，比如多次内爆或数组合并之类的事情，所有这些都比必要的IMO复杂得多。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|700219|为什么不干脆：|700220|implode(',',+array_slice($array,+0,+-1))+.+'+and+'+.+array_slice($array,+-1)[0]|code-block|syntax|javascript|700221|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

OK, so this is getting pretty old, but I have to say I reckon most of the answers are very inefficient with multiple implodes or array merges and stuff like that, all far more complex than necessary IMO.

Why not just:

<pre><code>implode(',', array_slice($array, 0, -1)) . ' and ' . array_slice($array, -1)[0]
</code></pre>

blocks|key|484434|text|我的go-+to，类似于Enrique的答案，但可选地处理牛津逗号。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|484435|public+static+function+listifyArray($array,$conjunction='and',$oxford=true)+{
++++$last+=+array_pop($array);
++++$remaining+=+count($array);
++++return+($remaining+?
++++++++implode(',+',$array)+.+(($oxford+&&+$remaining+>+1)+?+','+:+'')+.+"+$conjunction+"
++++++++:+'')+.+$last;
}|code-block|syntax|javascript|484436|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

My go-to, similar to Enrique's answer, but optionally handles the oxford comma.

<pre><code>public static function listifyArray($array,$conjunction='and',$oxford=true) {
 $last = array_pop($array);
 $remaining = count($array);
 return ($remaining ?
 implode(', ',$array) . (($oxford &amp;&amp; $remaining &gt; 1) ? ',' : '') . " $conjunction "
 : '') . $last;
}
</code></pre>

blocks|key|484500|text|使用正则表达式的简单human_implode。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|484501|function+human_implode($glue+=+",",+$last+=+"y",+$elements+=+array(),+$filter+=+null){
++++if+($filter)+{
++++++++$elements+=+array_map($filter,+$elements);
++++}

++++$str+=+implode("{$glue}+",+$elements);

++++if+(count($elements)+==+2)+{
++++++++return+str_replace("{$glue}+",+"+{$last}+",+$str);
++++}

+++return+preg_replace("/[{$glue}](?!.*[{$glue}])/",+"+{$last}",+$str);
}

print_r(human_implode(",",+"and",+["Joe","Hugh",+"Jack"]));+//+=>+Joe,+Hugh+and+Jack|code-block|syntax|javascript|484502|entityMap|0|LINK|mutability|MUTABLE|url|https://gist.github.com/fdorantesm/642582d184fe38ac4ca250f72c9288c8^0|A|D|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

Simple <a href="https://gist.github.com/fdorantesm/642582d184fe38ac4ca250f72c9288c8" rel="nofollow noreferrer">human_implode</a> using regex.

<pre><code>function human_implode($glue = ",", $last = "y", $elements = array(), $filter = null){
 if ($filter) {
 $elements = array_map($filter, $elements);
 }

 $str = implode("{$glue} ", $elements);

 if (count($elements) == 2) {
 return str_replace("{$glue} ", " {$last} ", $str);
 }

 return preg_replace("/[{$glue}](?!.*[{$glue}])/", " {$last}", $str);
}

print_r(human_implode(",", "and", ["Joe","Hugh", "Jack"])); // =&gt; Joe, Hugh and Jack
</code></pre>

blocks|key|700317|text|这可以使用array_fill和array_map来完成。它也是一行代码(似乎很多人喜欢它)，但为了可读性而格式化：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|700318|$string+=+implode(array_map(
++++function+($item,+$glue)+{+return+$item+.+$glue;+},+
++++$array,
++++array_slice(array_fill(0,+count($array),+',+')+%2B+['last'+=>+'+and+'],+2)
));|code-block|syntax|javascript|700319|虽然不是最优的解决方案，但是。|700320|这是the+demo。|700321|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/manual/en/function.array-fill.php|1|http://php.net/manual/en/function.array-map.php|2|http://sandbox.onlinephpfunctions.com/code/29a058fa7652d5ae19261dc692008cdc579dbdf4^0|5|A|G|9|5|A|0|G|9|1|0|0|0|2|8|2|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]|$9|13|A|14|B|C]]|D|@$9|15|A|16|1|17]|$9|18|A|19|1|1A]]|E|$]]|$1|F|3|G|5|H|7|1B|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1C|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|1D|8|@]|D|@$9|1E|A|1F|1|1G]]|E|$]]|$1|O|3|-4|5|6|7|1H|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]|W|$5|R|S|T|E|$U|X]]|Y|$5|R|S|T|E|$U|Z]]]]

This can be done with <a href="http://php.net/manual/en/function.array-fill.php" rel="nofollow noreferrer"><code>array_fill</code></a> and <a href="http://php.net/manual/en/function.array-map.php" rel="nofollow noreferrer"><code>array_map</code></a>. It is also a one-liner (seems that many enjoy them)), but formated for readability:

<pre><code>$string = implode(array_map(
 function ($item, $glue) { return $item . $glue; }, 
 $array,
 array_slice(array_fill(0, count($array), ', ') + ['last' =&gt; ' and '], 2)
));
</code></pre>

Not the most optimal solution, but nevertheless.

Here is <a href="http://sandbox.onlinephpfunctions.com/code/29a058fa7652d5ae19261dc692008cdc579dbdf4" rel="nofollow noreferrer">the demo</a>.

blocks|key|484594|text|我想出了另一个解决方案，虽然略显冗长。在我的情况下，我想让数组中的单词成为复数，所以这将在每一项的末尾添加一个"s“(除非单词已经以”s“结尾：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|484595|$models+=+array("F150","Express","CR-V","Rav4","Silverado");
foreach($models+as+$k=>$model){+
++++echo+$model;
++++if(!preg_match("/s%7CS$/",$model))+
++++++++echo+'s';+//+add+S+to+end+(if+it+doesn't+already+end+in+S)
++++if(isset($models[$k%2B1]))+{+//+if+there+is+another+after+this+one.
++++++++echo+",+";+
++++++++if(!isset($models[$k%2B2]))+
++++++++++++echo+"and+";+//+If+this+is+next-to-last,+add++",+and"+
++++++++}
++++}
}|code-block|syntax|javascript|484596|输出：|484597|F150s,+Express,+CR-Vs,+Rav4s,+and+Silverados|484598|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Another, although slightly more verbose, solution I came up with. In my situation, I wanted to make the words in the array plural, so this will add an "s" to the end of each item (unless the word already ends in 's': 

<pre><code>$models = array("F150","Express","CR-V","Rav4","Silverado");
foreach($models as $k=&gt;$model){ 
 echo $model;
 if(!preg_match("/s|S$/",$model)) 
 echo 's'; // add S to end (if it doesn't already end in S)
 if(isset($models[$k+1])) { // if there is another after this one.
 echo ", "; 
 if(!isset($models[$k+2])) 
 echo "and "; // If this is next-to-last, add ", and" 
 }
 }
}
</code></pre>

outputs:

<pre><code>F150s, Express, CR-Vs, Rav4s, and Silverados
</code></pre>

This array holds a list of items, and I want to turn it into a string, but I don't know how to make the last item have a &amp;/and before it instead of a comma.

<pre><code>1 =&gt; coke 2=&gt; sprite 3=&gt; fanta
</code></pre>

should become

<pre><code>coke, sprite and fanta
</code></pre>

This is the regular implode function:

<pre><code>$listString = implode(', ', $listArrau);
</code></pre>

What's an easy way to do it?

Implode an array with ", " and add "and " before the last item

这个数组包含一个条目列表，我想把它转换成一个字符串，但是我不知道如何让最后一个条目前面有一个&/，而不是逗号。1 => coke 2=> sprite 3=> fanta应该变成coke, sprite and fanta这是常规的内爆函数：$listString = implode(', ', $listArrau)...

问使用"，“内爆数组，并在最后一项前添加"and”
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