blocks|key|1566440|text|UIApplication有一个名为openURL的方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1566441|示例：|1566442|NSURL+*url+=+[NSURL+URLWithString:@"http://www.stackoverflow.com"];

if+(![[UIApplication+sharedApplication]+openURL:url])+{
++NSLog(@"%25@%25@",@"Failed+to+open+url:",[url+description]);
}|code-block|syntax|javascript|1566443|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

UIApplication has a method called openURL:

example:

<pre><code>NSURL *url = [NSURL URLWithString:@"http://www.stackoverflow.com"];

if (![[UIApplication sharedApplication] openURL:url]) {
 NSLog(@"%@%@",@"Failed to open url:",[url description]);
}
</code></pre>

blocks|key|1351079|text|应如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1351080|NSURL+*url+=+[NSURL+URLWithString:@"http://www.stackoverflow.com"];

if+(![[UIApplication+sharedApplication]+openURL:url])+{
++++NSLog(@"%25@%25@",@"Failed+to+open+url:",[url+description]);
}|code-block|syntax|javascript|1351081|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

should be the following : 

<pre><code>NSURL *url = [NSURL URLWithString:@"http://www.stackoverflow.com"];

if (![[UIApplication sharedApplication] openURL:url]) {
 NSLog(@"%@%@",@"Failed to open url:",[url description]);
}
</code></pre>

blocks|key|1566580|text|您可以使用以下命令在safari中打开url：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1566581|[[UIApplication+sharedApplication]+openURL:[NSURL+URLWithString:@"https://www.google.com"]];|code-block|syntax|javascript|1566582|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

you can open the url in safari with this:

<pre><code>[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"https://www.google.com"]];
</code></pre>

blocks|key|1566666|text|也许有人可以使用Swift版本：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1566667|在swift+2.2中：|1566668|UIApplication.sharedApplication().openURL(NSURL(string:+"https://www.google.com")!)|code-block|syntax|javascript|1566669|和3.0：|1566670|UIApplication.shared().openURL(URL(string:+"https://www.google.com")!)|1566671|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Maybe someone can use the Swift version:

In swift 2.2:

<pre><code>UIApplication.sharedApplication().openURL(NSURL(string: "https://www.google.com")!)
</code></pre>

And 3.0:

<pre><code>UIApplication.shared().openURL(URL(string: "https://www.google.com")!)
</code></pre>

blocks|key|1351246|text|在swift+4和5中，当OpenURL被折旧时，一个简单的方法是|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1351247|if+let+url+=+URL(string:+"https://stackoverflow.com")+{
++++UIApplication.shared.open(url,+options:+[:])+
}|code-block|syntax|javascript|1351248|您也可以使用SafariServices。类似于应用程序中的Safari窗口。|offset|length|style|CODE|1351249|import+SafariServices

...

if+let+url+=+URL(string:+"https://stackoverflow.com")+{
++++let+safariViewController+=+SFSafariViewController(url:+url)++++++++
++++self.present(safariViewController,+animated:+true)
}|1351250|entityMap^0|0|0|6|E|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

In swift 4 and 5, as OpenURL is depreciated, an easy way of doing it would be just

<pre class="lang-swift prettyprint-override"><code>if let url = URL(string: "https://stackoverflow.com") {
 UIApplication.shared.open(url, options: [:]) 
}
</code></pre>

You can also use <code>SafariServices</code>. Something like a Safari window within your app.

<pre class="lang-swift prettyprint-override"><code>import SafariServices

...

if let url = URL(string: "https://stackoverflow.com") {
 let safariViewController = SFSafariViewController(url: url) 
 self.present(safariViewController, animated: true)
}

</code></pre>

This might be a rather obvious question, but can you launch the Safari browser from an iPhone app?

How can I launch Safari from an iPhone app?

Swift

这可能是一个相当明显的问题，但是您能从iPhone应用程序启动Safari浏览器吗？

问如何从iPhone应用程序启动Safari？
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