blocks|key|262902|text|为什么你需要获取这个根url？你不能直接生成绝对URL吗？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|262903|{{+url('_demo_hello',+{+'name':+'Thomas'+})+}}|code-block|syntax|javascript|262904|这段Twig代码将生成指向_demo_hello路由的完整url。|262905|实际上，获取网站的基本url仅仅是获取主页路径的完整url：|262906|{{+url('homepage')+}}|262907|(主页，或者您在路由文件中对它的任何称呼)。|262908|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|U|8|@]|9|@]|A|$E|F]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Why do you need to get this root url ? Can't you generate directly absolute URL's ?

<pre><code>{{ url('_demo_hello', { 'name': 'Thomas' }) }}
</code></pre>

This Twig code will generate the full http:// url to the _demo_hello route.

In fact, getting the base url of the website is only getting the full url of the homepage route :

<pre><code>{{ url('homepage') }}
</code></pre>

(homepage, or whatever you call it in your routing file).

blocks|key|261638|text|这现在可以在twig模板中免费获得(在sf2版本2.0.14上测试)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|261639|{{+app.request.getBaseURL()+}}|code-block|syntax|javascript|261640|在更高的Symfony版本(在2.5上测试)中，尝试：|261641|{{+app.request.getSchemeAndHttpHost()+}}|261642|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

This is now available for free in twig templates (tested on sf2 version 2.0.14)

<pre><code>{{ app.request.getBaseURL() }}
</code></pre>

In later Symfony versions (tested on 2.5), try :

<pre><code>{{ app.request.getSchemeAndHttpHost() }}
</code></pre>

blocks|key|262964|text|您可以使用新的请求方法getSchemeAndHttpHost()|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|262965|{{+app.request.getSchemeAndHttpHost()+}}|code-block|syntax|javascript|262966|entityMap^0|B|M|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

You can use the new request method <code>getSchemeAndHttpHost()</code>:

<pre><code>{{ app.request.getSchemeAndHttpHost() }}
</code></pre>

blocks|key|2949180|text|从Symfony+v2.1到v4.1%2B有效|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2949181|如果您想要Symfony应用程序的基URL，您应该使用与getBaseUrl()连接在一起的getSchemeAndHttpHost()，类似于getUri()的工作方式，只是没有路由器路径和查询字符串。|offset|length|style|CODE|2949182|{{+app.request.schemeAndHttpHost+~+app.request.baseUrl+}}|code-block|syntax|javascript|2949183|例如，如果Symfony网站URL位于https://www.stackoverflow.com/app1/，则这两个方法返回以下值：|2949184|getSchemeAndHttpHost|BOLD|2949185|https://www.stackoverflow.com|2949186|getBaseUrl|2949187|/app1|2949188|注意：getBaseUrl()包括脚本文件名(即/app.php__)，如果它在您的URL中。|2949189|entityMap^0|0|S|C|1A|M|20|8|0|0|J|Z|0|0|K|0|0|0|A|0|0|3|C|O|8|0^^$0|@$1|2|3|4|5|6|7|11|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|12|8|@$D|13|E|14|F|G]|$D|15|E|16|F|G]|$D|17|E|18|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|19|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|1A|8|@$D|1B|E|1C|F|G]]|9|@]|A|$]]|$1|O|3|P|5|6|7|1D|8|@$D|1E|E|1F|F|Q]]|9|@]|A|$]]|$1|R|3|S|5|J|7|1G|8|@]|9|@]|A|$K|L]]|$1|T|3|U|5|6|7|1H|8|@$D|1I|E|1J|F|Q]]|9|@]|A|$]]|$1|V|3|W|5|J|7|1K|8|@]|9|@]|A|$K|L]]|$1|X|3|Y|5|6|7|1L|8|@$D|1M|E|1N|F|G]|$D|1O|E|1P|F|G]]|9|@]|A|$]]|$1|Z|3|-4|5|6|7|1Q|8|@]|9|@]|A|$]]]|10|$]]

Valid from Symfony v2.1 through v4.1+

If you want the base URL to a Symfony application, you should use <code>getSchemeAndHttpHost()</code> concatenated together with <code>getBaseUrl()</code>, similar to how <code>getUri()</code> works, except without the router path and query string.

<pre><code>{{ app.request.schemeAndHttpHost ~ app.request.baseUrl }}
</code></pre>

For example, if your Symfony website URL lives at <code>https://www.stackoverflow.com/app1/</code>, then these two methods return these values:

getSchemeAndHttpHost

<pre><code>https://www.stackoverflow.com
</code></pre>

getBaseUrl

<pre><code>/app1
</code></pre>

Note: <code>getBaseUrl()</code> includes the script filename (ie <code>/app.php</code>) if it's in your URL.

blocks|key|257514|text|基本url在Symfony\Component\Routing\RequestContext中定义。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|257515|它可以像这样从控制器中获取：|257516|$this->container->get('router')->getContext()->getBaseUrl()|code-block|syntax|javascript|257517|entityMap^0|6|14|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|R|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|S|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

Base url is defined inside <code>Symfony\Component\Routing\RequestContext</code>.

It can be fetched from controller like this:

<pre><code>$this-&gt;container-&gt;get('router')-&gt;getContext()-&gt;getBaseUrl()
</code></pre>

blocks|key|257545|text|对于Symfony+2.3%2B，在控制器中获取基本url应该是|type|unstyled|depth|inlineStyleRanges|entityRanges|data|257546|$this->get('request')->getSchemeAndHttpHost();|code-block|syntax|javascript|257547|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

For Symfony 2.3+, to get the base url in a controller should be

<pre><code>$this-&gt;get('request')-&gt;getSchemeAndHttpHost();
</code></pre>

blocks|key|259849|text|+<base+href="{{+app.request.getSchemeAndHttpHost()+}}"/>|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|259850|或从控制器|unstyled|259851|$this->container->get('router')->getContext()->getSchemeAndHttpHost()|259852|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code> &lt;base href="{{ app.request.getSchemeAndHttpHost() }}"/&gt;
</code></pre>

or from controller

<pre><code>$this-&gt;container-&gt;get('router')-&gt;getContext()-&gt;getSchemeAndHttpHost()
</code></pre>

blocks|key|3163060|text|另外，对于js/css/image+urls，有一个方便的函数asset()|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3163061|<img+src="{{+asset('image/logo.png')+}}"/>|code-block|syntax|javascript|3163062|这将创建一个以/开头的绝对url。|offset|length|style|CODE|3163063|entityMap^0|0|0|7|1|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Also for js/css/image urls there's handy function asset()
<pre><code>&lt;img src=&quot;{{ asset('image/logo.png') }}&quot;/&gt;
</code></pre>
This creates an absolute url starting with <code>/</code>.

blocks|key|261765|text|对于当前Symfony版本(在撰写本答案时为Symfony+4.1)，请不要像在其他一些答案中那样直接访问服务容器。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|261766|相反(除非您不使用标准服务配置)，可以通过类型提示注入请求对象。|261767|<?php

namespace+App\Service;

use+Symfony\Component\HttpFoundation\RequestStack;

/**
+*+The+YourService+class+provides+a+method+for+retrieving+the+base+URL.
+*
+*+@package+App\Service
+*/
class+YourService
{

++++/**
+++++*+@var+string
+++++*/
++++protected+$baseUrl;

++++/**
+++++*+YourService+constructor.
+++++*
+++++*+@param+\Symfony\Component\HttpFoundation\RequestStack+$requestStack
+++++*/
++++public+function+__construct(RequestStack+$requestStack)
++++{
++++++++$this->baseUrl+=+$requestStack->getCurrentRequest()->getSchemeAndHttpHost();
++++}

++++/**
+++++*+Returns+the+current+base+URL.
+++++*
+++++*+@return+string
+++++*/
++++public+function+getBaseUrl():+string
++++{
++++++++return+$this->baseUrl;
++++}
}|code-block|syntax|javascript|261768|另请参阅关于how+to+retrieve+the+current+request+object的官方Symfony文档。|offset|length|261769|entityMap|0|LINK|mutability|MUTABLE|url|https://symfony.com/doc/current/service_container/request.html^0|0|0|0|6|16|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|W|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|X|8|@]|9|@$K|Y|L|Z|1|10]]|A|$]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

For current Symfony version (as of writing this answer it's Symfony 4.1) do not directly access the service container as done in some of the other answers.

Instead (unless you don't use the standard services configuration), inject the request object by type-hinting.

<pre><code>&lt;?php

namespace App\Service;

use Symfony\Component\HttpFoundation\RequestStack;

/**
 * The YourService class provides a method for retrieving the base URL.
 *
 * @package App\Service
 */
class YourService
{

 /**
 * @var string
 */
 protected $baseUrl;

 /**
 * YourService constructor.
 *
 * @param \Symfony\Component\HttpFoundation\RequestStack $requestStack
 */
 public function __construct(RequestStack $requestStack)
 {
 $this-&gt;baseUrl = $requestStack-&gt;getCurrentRequest()-&gt;getSchemeAndHttpHost();
 }

 /**
 * Returns the current base URL.
 *
 * @return string
 */
 public function getBaseUrl(): string
 {
 return $this-&gt;baseUrl;
 }
}
</code></pre>

See also official Symfony docs about <a href="https://symfony.com/doc/current/service_container/request.html" rel="nofollow noreferrer">how to retrieve the current request object</a>.

blocks|key|257509|text|您可以定义一个基本模板并在其中呈现“全局部分”，而不是将变量全局传递给模板。基本模板可以继承。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|257510|symfony文档中的渲染模板示例：|257511|<div+id="sidebar">
++{%25+render+"AcmeArticleBundle:Article:recentArticles"+with+{'max':+3}+%25}
</div>|code-block|syntax|javascript|257512|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Instead of passing variable to template globally, you can define a base template and render the 'global part' in it. The base template can be inherited.

Example of rendering template From the symfony Documentation:

<pre><code>&lt;div id="sidebar"&gt;
 {% render "AcmeArticleBundle:Article:recentArticles" with {'max': 3} %}
&lt;/div&gt;
</code></pre>

blocks|key|2949352|text|在Symfony+5中，在控制器方法的常见情况下，使用注入的请求对象：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2949353|public+function+controllerFunction(Request+$request,+LoggerInterface+$logger)
++...
++$scheme+=+$request->getSchemeAndHttpHost();
++$logger->info('Domain+is:+'+.+$scheme);
++...
++//prepare+to+render
++$retarray+=+array(
++++...
++++'scheme'+=>+$scheme,
++++...
++++);
++return+$this->render('Template.html.twig',+$retarray);
}|code-block|syntax|javascript|2949354|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In Symfony 5 and in the common situation of a controller method use the injected Request object:
<pre><code>public function controllerFunction(Request $request, LoggerInterface $logger)
 ...
 $scheme = $request-&gt;getSchemeAndHttpHost();
 $logger-&gt;info('Domain is: ' . $scheme);
 ...
 //prepare to render
 $retarray = array(
 ...
 'scheme' =&gt; $scheme,
 ...
 );
 return $this-&gt;render('Template.html.twig', $retarray);
}
</code></pre>

blocks|key|259856|text|{{+dump(app.request.server.get('DOCUMENT_ROOT'))+}}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|259857|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>{{ dump(app.request.server.get('DOCUMENT_ROOT')) }}
</code></pre>

blocks|key|3163135|text|在涉及多域应用程序的一种情况下，app.request.getHttpHost帮了我大忙。它返回类似example.com或subdomain.example.com的内容(如果端口不是标准端口，则返回example.com:8000+)。这是在Symfony+3.4中。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3163136|entityMap^0|G|N|1E|B|1Q|L|2T|G|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]|$9|M|A|N|B|C]|$9|O|A|P|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|G|$]]

In one situation involving a multi-domain application, <code>app.request.getHttpHost</code> helped me out. It returns something like <code>example.com</code> or <code>subdomain.example.com</code> (or <code>example.com:8000</code> when the port is not standard). This was in Symfony 3.4.

blocks|key|2949339|text|我尝试了这里的所有选项，但它们对我都不起作用。最终，我使用以下命令使其正常工作|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2949340|2949341|+{{+site.url+}}|blockquote|2949342|2949343|2949344|希望这能帮助那些还在苦苦挣扎的人。|2949345|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|M|8|@]|9|@]|A|$]]|$1|C|3|D|5|E|7|N|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|O|8|@]|9|@]|A|$]]|$1|G|3|-4|5|6|7|P|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|Q|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|R|8|@]|9|@]|A|$]]]|K|$]]

I tried all the options here but they didnt work for me.
Eventually I got it working using 

<blockquote>
 {{ site.url }} 
</blockquote>

Hope this helps someone who is still struggling.

I'm making the switch from CodeIgniter to Symfony 2. 
Can someone please give me an example of how to: 

<ul>
<li>Get the base url (the url without the route specific parts)</li>
<li>Globally pass this variable to the twig bundle so I can use it in every template.</li>
</ul>

Getting the base url of the website and globally passing it to twig in Symfony 2

路由器

容器

路由

我正在从CodeIgniter切换到Symfony 2。谁能给我举个例子，说明如何：将此变量传递给包，这样我就可以在每个模板中使用它。

问获取网站的基本url并将其全局传递给Symfony 2中的twig。
EN

回答 14

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问获取网站的基本url并将其全局传递给Symfony 2中的twig。EN

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问获取网站的基本url并将其全局传递给Symfony 2中的twig。
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