blocks|key|3153346|text|0x04是4的十六进制(+0x只是16进制表示数字的常见前缀约定-因为许多人认为是十进制)，这将是第四个字节(因为他们说的是偏移量，他们可能将第一个字节算作字节0，所以偏移量0x04将是第五个字节)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3153347|我猜他们是说第四个和第五个字节加起来是28315，但是他们有没有说这是小端还是大端呢？|3153348|28315+(十进制)是十六进制表示法中的0x6E9B，如果它是小端，则可能在文件中的顺序为0x9B+0x6E。|3153349|注意:+Little-endian和big-endian是指字节写入的顺序。人类通常以大端的方式写十进制和十六进制，所以：|3153350|256将写为0x0100+(左边的数字是最大的刻度)|3153351|但这需要两个字节，小端系统将首先写入低字节:+0x00+0x01。Big-endian系统将首先写入高字节:+0x01+0x00。|3153352|通常，Intel系统是低端的，而其他系统有所不同。|3153353|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Q|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|R|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|S|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|T|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|U|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|V|8|@]|9|@]|A|$]]|$1|N|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|O|$]]

0x04 is hex for 4 (the 0x is just a common prefix convention for base 16 representation of numbers - since many people think in decimal), and that would be the fourth byte (since they are saying offset, they probably count the first byte as byte 0, so offset 0x04 would be the 5th byte).

I guess they are saying that the 4th and 5th byte together would be 28315, but did they say if this is little-endian or big-endian?

28315 (decimal) is 0x6E9B in hexadecimal notation, probably in the file in order 0x9B 0x6E if it's little-endian.

Note: Little-endian and big-endian refer to the order bytes are written. Humans typical write decimal notation and hexadecimal in a big-endian way, so:

256 would be written as 0x0100 (digits on the left are the biggest scale)

But that takes two bytes and little-endian systems will write the low byte first: 0x00 0x01. Big-endian systems will write the high-byte first: 0x01 0x00.

Typically Intel systems are little-endian and other systems vary.

blocks|key|362305|text|启动here。一旦你学会了如何读取十六进制值，你就能更好地实际解决你的问题。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|362306|entityMap|0|LINK|mutability|MUTABLE|url|http://en.wikipedia.org/wiki/Hexadecimal^0|2|4|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

Start <a href="http://en.wikipedia.org/wiki/Hexadecimal" rel="nofollow noreferrer">here</a>. Once you learn how to read hexadecimal values, you'll be in much better shape to actually solve your problem.

blocks|key|365603|text|十六进制的0x04是十进制的4。十六进制的0x10是十进制的16。calc.exe可以在十六进制和十进制之间进行转换。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|365604|偏移量4表示从文件开头开始的4个字节。偏移量0是文件中的第一个字节。|365605|entityMap^0|X|8|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|M|8|@]|D|@]|E|$]]|$1|H|3|-4|5|6|7|N|8|@]|D|@]|E|$]]]|I|$]]

0x04 in hex is 4 in decimal. 0x10 in hex is 16 in decimal. <code>calc.exe</code> can convert between hex and decimal for you.

Offset 4 means 4 bytes from the start of the file. Offset 0 is the first byte in the file.

blocks|key|362887|text|查看字节4和字节5，它们的值应为0x6E+0x9B+(或0x9B+0x6E)，具体取决于您的字节顺序。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|362888|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Look at bytes 4 and five they should have the values 0x6E 0x9B (or 0x9B 0x6E) depending on your endianess.

blocks|key|365688|text|把一个二进制文件想象成一个线性字节数组。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|365689|0x04将是数组中的第五个元素(以0为基数的数组)，0x05将是第六个元素。|365690|可以将0x04和0x05中的两个值或在一起以创建数字28,315。|365691|由于您正在读取的值是16位，您需要将一个值进行位移位，然后将它们进行OR运算，例如，如果您在c#中操作文件，您将使用以下内容：|365692|int+value+=+(ByteArray[4]+>>+8)+%7C+ByteArray[5]);|code-block|syntax|javascript|365693|希望这有助于解释十六进制地址是如何工作的。|365694|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|S|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|T|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|U|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Think of a binary file as a linear array of bytes.

0x04 would be the 5th (in a 0 based array) element in the array, and 0x05 would be the 6th.

The two values in 0x04 and 0x05 can be OR'ed together to create the number 28,315.

Since the value you are reading is 16 bit, you need to bitshift one value over and then OR them together, ie if you were manipulating the file in c#, you would use something like this:

<pre><code>int value = (ByteArray[4] &gt;&gt; 8) | ByteArray[5]);
</code></pre>

Hopefully this helps explain how hex addresses work.

I downloaded Hex Workshop, and I was told to read a .dbc file.

<blockquote>
 It should contain 28,315 if you read
 offset 0x04 and 0x05
</blockquote>

I am unsure how to do this? What does 0x04 mean?

Can someone explain hex offsets to me?

我下载了十六进制工作坊，然后我被告知要读一个.dbc文件。如果读取偏移量0x04和0x05，则应包含28,315我不知道该怎么做？0x04是什么意思？

问有人能给我解释一下十六进制的偏移量吗？
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