blocks|key|100499|text|假设您的JSON对象保存在文件"simple.json“中，您可以迭代属性-值对，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|100500|JSONParser+parser+=+new+JSONParser();

Object+obj+=+parser.parse(new+FileReader("simple.json"));

JSONObject+jsonObject+=+(JSONObject)+obj;

for(Iterator+iterator+=+jsonObject.keySet().iterator();+iterator.hasNext();)+{
++++String+key+=+(String)+iterator.next();
++++System.out.println(jsonObject.get(key));
}|code-block|syntax|javascript|100501|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Assuming your JSON object is saved in a file "simple.json", you can iterate over the attribute-value pairs as follows:

<pre><code>JSONParser parser = new JSONParser();

Object obj = parser.parse(new FileReader("simple.json"));

JSONObject jsonObject = (JSONObject) obj;

for(Iterator iterator = jsonObject.keySet().iterator(); iterator.hasNext();) {
 String key = (String) iterator.next();
 System.out.println(jsonObject.get(key));
}
</code></pre>

blocks|key|4606981|text|你可以这样做|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4606982|String+jsonstring+=+"{+\"child\":+{+\"something\":+\"value\",+\"something2\":+\"value\"+}+}";
JSONObject+resobj+=+new+JSONObject(jsonstring);
Iterator<?>+keys+=+resobj.keys().iterator();
while(keys.hasNext()+)+{
++++String+key+=+(String)keys.next();
++++if+(+resobj.get(key)+instanceof+JSONObject+)+{
++++++++JSONObject+xx+=+new+JSONObject(resobj.get(key).toString());
++++++++Log.d("res1",xx.getString("something"));
++++++++Log.d("res2",xx.getString("something2"));
++++}
}|code-block|syntax|javascript|4606983|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can do like this

<pre><code>String jsonstring = "{ \"child\": { \"something\": \"value\", \"something2\": \"value\" } }";
JSONObject resobj = new JSONObject(jsonstring);
Iterator&lt;?&gt; keys = resobj.keys().iterator();
while(keys.hasNext() ) {
 String key = (String)keys.next();
 if ( resobj.get(key) instanceof JSONObject ) {
 JSONObject xx = new JSONObject(resobj.get(key).toString());
 Log.d("res1",xx.getString("something"));
 Log.d("res2",xx.getString("something2"));
 }
}
</code></pre>

blocks|key|4606996|text|在Java+8中，我们可以使用lambdas|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4606997|void+handleJSONObject(JSONObject+jsonObject)+{
jsonObject.keys().forEachRemaining(key+->+{
++++Object+value+=+jsonObject.get(key);
++++logger.info("Key:+{0}\tValue:+{1}",+key,+value);
++}
}|code-block|syntax|javascript|4606998|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In Java 8 we can use lambdas 

<pre><code>void handleJSONObject(JSONObject jsonObject) {
jsonObject.keys().forEachRemaining(key -&gt; {
 Object value = jsonObject.get(key);
 logger.info("Key: {0}\tValue: {1}", key, value);
 }
}
</code></pre>

blocks|key|4607010|text|下面是遍历org.google.jso.JsonElemet+set并过滤出特定JsonElement+by+key的代码：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4607011|Predicate<Map.Entry<String,+JsonElement>>+keyPredicate+=+a+->+a.getKey().equalsIgnoreCase(jsonAttributeKey);
++++++++Predicate<Map.Entry<String,+JsonElement>>+valuePredicate+=+a+->+a.getValue()!=+null+&&+!a.getValue().isJsonNull();
++++++++return+responseJson.getAsJsonObject().entrySet().stream()
++++++++++++++++.filter(keyPredicate.and((valuePredicate)))
++++++++++++++++.findAny()
++++++++++++++++.orElseThrow(()+->+{
++++++++++++++++++++System.out.println(jsonAttributeKey+%2B"+tag+not+exist+in+the+json");
++++++++++++++++++++return+NGPExceptionFactory.getNGPException(errorCode);
++++++++++++++++})
++++++++++++++++.getValue();|code-block|syntax|javascript|4607012|entityMap^0|5|P|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Below is the code to iterate through <code>org.google.jso.JsonElemet</code> set and filter out the specific JsonElement by key:
<pre><code>Predicate&lt;Map.Entry&lt;String, JsonElement&gt;&gt; keyPredicate = a -&gt; a.getKey().equalsIgnoreCase(jsonAttributeKey);
 Predicate&lt;Map.Entry&lt;String, JsonElement&gt;&gt; valuePredicate = a -&gt; a.getValue()!= null &amp;&amp; !a.getValue().isJsonNull();
 return responseJson.getAsJsonObject().entrySet().stream()
 .filter(keyPredicate.and((valuePredicate)))
 .findAny()
 .orElseThrow(() -&gt; {
 System.out.println(jsonAttributeKey +&quot; tag not exist in the json&quot;);
 return NGPExceptionFactory.getNGPException(errorCode);
 })
 .getValue();
</code></pre>

I am trying to iterate over a json object using json simple. I have seen answers where you can do a <code>getJSONObject("child")</code> from 

<pre><code>{ "child": { "something": "value", "something2": "value" } }
</code></pre>

But what if I just have something

<pre><code>{
"k1":"v1",
"k2":"v2",
"k3":"v3"
} 
</code></pre>

And want to iterate over that <code>json</code> object. This:

<pre><code>Iterator iter = jObj.keys();
</code></pre>

Throws:

<pre><code>cannot find symbol
symbol : method keys()
location: class org.json.simple.JSONObject
</code></pre>

Iterate through JSONObject from root in json simple

JSON

Java

我正在尝试使用json simple遍历json对象。我已经看到了你可以在哪里做getJSONObject("child")的答案{ "child": { "something": "value", "something2": "value" } }但是如果我只有一些东西{"k1":"v1","k2":"v2","k3...

问在json simple中从根目录遍历JSONObject
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