blocks|key|1170121|text|因为编译的Groovy类与Java类兼容，所以您应该能够使用任何Java库将JSON转换为POJO(或POGO)。Jackson是一个相当流行的选择，您可以使用它来转换JSON，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1170122|String+json+=+'{
++"name"+:+{+"first"+:+"Joe",+"last"+:+"Sixpack"+},
++"gender"+:+"MALE",
++"verified"+:+false,
++"userImage"+:+"Rm9vYmFyIQ=="
}'|code-block|syntax|javascript|1170123|使用以下命令映射到地图：|1170124|Map<String,Object>+userData+=+mapper.readValue(json,+Map.class)|1170125|或者，如果您想要将JSON转换为Groovy用户类：|1170126|User+userData+=+mapper.readValue(json,+User.class)|1170127|这将把Groovy类中的属性映射到JSON中的键。|1170128|entityMap|0|LINK|mutability|MUTABLE|url|http://jackson.codehaus.org/^0|1L|7|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@$A|11|B|12|1|13]]|C|$]]|$1|D|3|E|5|F|7|14|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|15|8|@]|9|@]|C|$]]|$1|K|3|L|5|F|7|16|8|@]|9|@]|C|$G|H]]|$1|M|3|N|5|6|7|17|8|@]|9|@]|C|$]]|$1|O|3|P|5|F|7|18|8|@]|9|@]|C|$G|H]]|$1|Q|3|R|5|6|7|19|8|@]|9|@]|C|$]]|$1|S|3|-4|5|6|7|1A|8|@]|9|@]|C|$]]]|T|$U|$5|V|W|X|C|$Y|Z]]]]

Because compiled Groovy classes are compatible with Java classes, you should be able to use any Java library for converting JSON to POJOs (or POGOs). <a href="http://jackson.codehaus.org/" rel="noreferrer">Jackson</a> is a fairly popular choice which you can use to convert JSON like this:

<pre><code>String json = '{
 "name" : { "first" : "Joe", "last" : "Sixpack" },
 "gender" : "MALE",
 "verified" : false,
 "userImage" : "Rm9vYmFyIQ=="
}'
</code></pre>

to a Map using:

<pre><code>Map&lt;String,Object&gt; userData = mapper.readValue(json, Map.class)
</code></pre>

Or if you want to convert the JSON to a Groovy User class:

<pre><code>User userData = mapper.readValue(json, User.class)
</code></pre>

This will map properties in the Groovy class to keys in the JSON.

blocks|key|1385337|text|我在HTTPBuilder中使用JSON-lib，但我使用JSONSlurper类将字符串解析为JSON实例：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1385338|JSON+jsonMapObject+=+new+JsonSlurper().parse(+"{integer:1,+bool:+true}"+);|code-block|syntax|javascript|1385339|为了从Object转到JSON，我这样做：|1385340|//from+a+map:
new+JSONObject().putAll(+[one:'1',+two:'two']).toString()
//from+an+object:
JSONObject.fromObject(+somePOGO+).toString()|1385341|entityMap|0|LINK|mutability|MUTABLE|url|http://groovy.codehaus.org/modules/http-builder/^0|2|B|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|Z|8|@]|9|@]|C|$]]|$1|K|3|L|5|F|7|10|8|@]|9|@]|C|$G|H]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]]]

I use JSON-lib in <a href="http://groovy.codehaus.org/modules/http-builder/" rel="nofollow noreferrer">HTTPBuilder</a>, but I use the JSONSlurper class to parse a string to a JSON instance:

<pre><code>JSON jsonMapObject = new JsonSlurper().parse( "{integer:1, bool: true}" );
</code></pre>

To go from Object to JSON, I do this:

<pre><code>//from a map:
new JSONObject().putAll( [one:'1', two:'two']).toString()
//from an object:
JSONObject.fromObject( somePOGO ).toString()
</code></pre>

blocks|key|1385379|text|致那些在使用json-lib和GJson.enhanceClasses()时遇到麻烦的人。请尝试使用GJson.enhanceString()。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1385380|GJson.enhanceString()
def+o+=+"{\"x\":+20.0}"+as+JSONObject|code-block|syntax|javascript|1385381|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

To the people having trouble with json-lib and GJson.enhanceClasses(). Try GJson.enhanceString() instead.

<pre><code>GJson.enhanceString()
def o = "{\"x\": 20.0}" as JSONObject
</code></pre>

blocks|key|1170267|text|如果您使用的是Groovy1.8或更高版本，在JsonSlurper中有一个构建，您可以这样使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1170268|import+groovy.json.JsonSlurper

//Attention:+you+have+to+use+double+quotes+inside+the+json+string
def+jsonObj+=+new+JsonSlurper().parseText(+'{+"name":"Peter",+"age":+23}'+)

assert+jsonObj.name+==+"Peter"
assert+jsonObj.age+==+23
//this+won't+work,+because+it's+not+defined
assert+jsonObj.gender+==+null|code-block|syntax|javascript|1170269|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you are on Groovy 1.8 or later, there is a build in JsonSlurper you can use this way:

<pre><code>import groovy.json.JsonSlurper

//Attention: you have to use double quotes inside the json string
def jsonObj = new JsonSlurper().parseText( '{ "name":"Peter", "age": 23}' )

assert jsonObj.name == "Peter"
assert jsonObj.age == 23
//this won't work, because it's not defined
assert jsonObj.gender == null
</code></pre>

I found many things about converting Groovy to JSON, but oddly enough, not the other way.

What is the (best) JSON to Groovy parser around there ?

JSON to Groovy parser

JSON

Java

我发现了许多关于将Groovy转换为JSON的事情，但奇怪的是，不是以另一种方式。什么是(最好的) JSON到Groovy的解析器？

问JSON到Groovy解析器
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