blocks|key|2809056|text|您应该将"Default+Value“值设置为"1”-仅设置"Values“列表中的0项。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2809057|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

You should set your "Default Value" value as "1" - Just Item 0 from your "Values" list.

blocks|key|2809110|text|位置设置作为多值，是一个NSDictionary。因此，请执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2809111|NSDictionary+*location+=+[[NSUserDefaults+standardUserDefaults]+valueForKey:@"locationSettings"];+

NSString+*value+=+(NSString+*)location;+|code-block|syntax|javascript|2809112|将位置值强制转换为NSString，因为您知道要返回一个字符串。|2809113|然后，您可以将结果作为字符串进行处理。返回的"+value“变量是在value部分中写入的内容。在本例中，如果选择"London"，将以字符串的形式返回"1“值。|2809114|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Location settings as a multi value, is an NSDictionary. Therefore, do the following: 

<pre><code>NSDictionary *location = [[NSUserDefaults standardUserDefaults] valueForKey:@"locationSettings"]; 

NSString *value = (NSString *)location; 
</code></pre>

Cast the location value as a NSString because you know a string is to be returned.

You can then handle the result as a string. The "value" variable returned is whatever is written in the value section. In your case, if you select "London", you will get a value of "1" back in the form of a string.

blocks|key|189405|text|如果我对您的问题的理解是正确的，那么您就是在问如何才能获得用户所选值的位置字典中的键条目。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|189406|对于字典，没有这种一次性使用的方法。但是有一种方法可以通过操作allKeys来实现相同的结果，如下所示：|offset|length|style|CODE|189407|NSDictionary+*location+=+[[NSUserDefaults+standardUserDefaults]+valueForKey:@"locationSettings"];+
NSArray+*keys+=+[location+allKeys];
NSString+*locationIdentifier+=+[keys+objectForIndex:[location+valueForKey:@"LONDON"]];|code-block|syntax|javascript|189408|这将导致在locationIdentifier变量中存储"LONDON"字符串。所以最后一行，字符串的赋值，可能会改为简单的objectForIndex:0，但这是我以前没有尝试过的，所以我不确定。|189409|entityMap^0|0|V|7|0|0|5|I|S|8|1Q|G|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@$D|S|E|T|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|U|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|V|8|@$D|W|E|X|F|G]|$D|Y|E|Z|F|G]|$D|10|E|11|F|G]]|9|@]|A|$]]|$1|O|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|P|$]]

If my understanding of your question is correct, you are asking how you can get the Key entry of the location dictionary for the user's chosen value.

For dictionaries, there is no such single-use method.
But there is a way to achieve the same result via manipulating <code>allKeys</code> as below:

<pre><code>NSDictionary *location = [[NSUserDefaults standardUserDefaults] valueForKey:@"locationSettings"]; 
NSArray *keys = [location allKeys];
NSString *locationIdentifier = [keys objectForIndex:[location valueForKey:@"LONDON"]];
</code></pre>

This would result in the <code>"LONDON"</code> string being stored in the <code>locationIdentifier</code> variable.
So that last line, the assignment of the string, could possibly be changed to simply have <code>objectForIndex:0</code> instead, but that isn't something I've tried before so I'm not certain.

blocks|key|2809177|text|我遇到了类似的情况，并回答了一个问题，那就是它会帮助别人。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2809178|如果我正确理解了这个问题，当用户从设置中选择伦敦时，默认值将是1。当你读取locationSetting的设置包时，你得到的值是1，而不是伦敦，但你想在你的代码中使用“伦敦”而不是1。将缺省值设置为字典而不是字符串，这样就可以在该字典中同时包含标题和值。然后，您可以检索选定值的文本。|2809179|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

I ran into the similar situation and answering the question that it'll help someone.

If I understand the question correctly, when user selects London from the settings the default value will be 1. when you read the settings bundle for locationSetting you get the value 1 and not LONDON, but you want the "LONDON" in your code rather than 1. It is not possible with the current structure of your plist. make the default value a dictionary instead of string and then you can have both titles and values inside that dictionary. you can then retrieve the text of the selected value.

I have a multi value setting (location) defined in my settings bundle for an app. 
The Titles are defined as long titles, for example, "London" and the corresponding value part of the setting is defined as "1".

[EDIT]

To expand this question I will add more information about the multi value setting:

<img src="https://i.stack.imgur.com/EWgqj.png" alt="this is a screenshot of the multi value setting">

How do I retrieve the Title of LONDON at Item 0. As described above when I retrieve the objectForKey or valueForKey I get 1 always. I want to display the string "LONDON" from the title in a label in the app but use the value 1 in core data. Note: I have set the value in the settings before the app runs so it does return a value but the value is always 1 as the Title does not seem to be accessible.

How To Use Multi Value Title and Value From Settings Bundle

我在应用程序的设置包中定义了一个多值设置(位置)。标题被定义为长标题，例如“伦敦”，并且设置的相应值部分被定义为"1“。编辑为了展开这个问题，我将添加有关多值设置的更多信息：​​如何在项目0处检索伦敦的标题。如上所述，当我检索objectForKey或valueForKey时，我总是得到1。我希望在应用程序的标签中显示...

问如何使用设置包中的多值标题和值
EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问如何使用设置包中的多值标题和值EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问如何使用设置包中的多值标题和值
EN