blocks|key|4659554|text|对$resource对象使用的是isArray还是.query()？|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4659555|来自$resource文档：isArray+–+{boolean=}+–+If+true+then+the+returned+object+for+this+action+is+an+array.|4659556|更新：|4659557|如果您正确使用$resource，则可以选择以下选项：|4659558|1)让后端返回包含在对象中的数据，例如。{+data:+[]+}，而不仅仅是一个数组。|4659559|2)如果不可能，使用来自$resource.query()的回调，例如。|4659560|MyResource.query({+myParams:+'something'},+function(result)+{
++++//+Do+something+with+the+plain+result
});|code-block|syntax|javascript|4659561|entityMap^0|1|9|G|7|P|8|0|E|2C|0|0|7|9|0|K|C|0|C|H|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|13|8|@$9|14|A|15|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|16|8|@]|D|@]|E|$]]|$1|J|3|K|5|6|7|17|8|@$9|18|A|19|B|C]]|D|@]|E|$]]|$1|L|3|M|5|6|7|1A|8|@$9|1B|A|1C|B|C]]|D|@]|E|$]]|$1|N|3|O|5|6|7|1D|8|@$9|1E|A|1F|B|C]]|D|@]|E|$]]|$1|P|3|Q|5|R|7|1G|8|@]|D|@]|E|$S|T]]|$1|U|3|-4|5|6|7|1H|8|@]|D|@]|E|$]]]|V|$]]

Are you using <code>isArray</code> or <code>.query()</code> with your <code>$resource</code> object? 

From the $resource docs: <code>isArray – {boolean=} – If true then the returned object for this action is an array.</code>

UPDATE:

If you are using <code>$resource</code> correctly, some options you have are:

1) Have the backend return the data contained within an object, eg. <code>{ data: [] }</code> rather than just an array.

2) If that is not possible, use the callback from the <code>$resource.query()</code>, eg.

<pre><code>MyResource.query({ myParams: 'something'}, function(result) {
 // Do something with the plain result
});
</code></pre>

blocks|key|153200|text|我正在寻找同样的答案，但目前我只知道这个丑陋的技巧：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|153201|要编写这样的函数：|153202|function+cleanResponse(resp)+{
++++return+JSON.parse(angular.toJson(resp));
}|code-block|syntax|javascript|153203|并在每个查询中调用它(丑陋，是的)：|153204|function+getSmt()+{
++++Resource.get({},+function+(data)+{
++++++++$scope.some+=+cleanResponse(data);
++++},+function+(responce)+{
++++++++//handle+error
++++})
}|153205|如果有人能教我如何正确地做这件事，我会很高兴的|153206|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

I'm looking for the same answer, but at this moment I know only this ugly hack:

To write a func like this:

<pre><code>function cleanResponse(resp) {
 return JSON.parse(angular.toJson(resp));
}
</code></pre>

and call it in every single query (ugly, yep):

<pre><code>function getSmt() {
 Resource.get({}, function (data) {
 $scope.some = cleanResponse(data);
 }, function (responce) {
 //handle error
 })
}
</code></pre>

I'll be happy if someone would teach me how to do it correctly

blocks|key|4659618|text|我也面临着同样的问题。事实上，你只需要使用angular和angular-resource的相同版本，它就会像一个护身符一样工作。希望它能帮上忙！|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4659619|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

I'm facing the same issue. In fact, you simply have to use the same version of angular and angular-resource and it will work like a charm.
Hope it helps !

blocks|key|4659657|text|简而言之:+angular.fromJson(angular.toJson(resp))；这将删除所有“特定于角度的”函数等，并返回一个干净的数据对象。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4659658|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Short answer : angular.fromJson(angular.toJson(resp));
This will remove all "angular specific" functions etc and will return you a clean data object.

blocks|key|4659683|text|试着在你的服务中编写类似这样的代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4659684|yourApp.factory('Service',+['$resource',+function+($resource)+{
++++return+$resource('your/rest/api/path');
}]);|code-block|syntax|javascript|4659685|然后在你的控制器中有类似这样的东西：|4659686|yourApp.controller('Controller',+['$scope',+'Service',+function+($scope,+Service)+{
++++Service.get().then(function+(data)+{
++++++++$scope.myData+=+data;
++++});
});|4659687|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Try to code something like this in your service:

<pre><code>yourApp.factory('Service', ['$resource', function ($resource) {
 return $resource('your/rest/api/path');
}]);
</code></pre>

And then something like this in your controller:

<pre><code>yourApp.controller('Controller', ['$scope', 'Service', function ($scope, Service) {
 Service.get().then(function (data) {
 $scope.myData = data;
 });
});
</code></pre>

blocks|key|4659786|text|我对angular.toJson做了这个快速可重用的方法(带有前导$$的属性将被剥离)：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4659787|yourApp.factory('Service',+['$resource',+function+($resource)+{
++++return+$resource('your/rest/api/path');
}]);

+yourApp.factory('commonServices',+function+()+{+
+++++++++return+{
++++++++++++++++toJson+:+function(response){
++++++++++++++++++++return+JSON.parse(angular.toJson(response));
+++++++++++++++++++++//*or*+
++++++++++++++++++++//return+angular.toJson(response);
++++++++++++++++}
++++});|code-block|syntax|javascript|4659788|然后在你的控制器中有类似这样的东西：|4659789|+yourApp.controller('Controller',+['$scope',+'Service','commonServices',++
function+($scope,+Service,+commonServices)+{
++++++++++++Service.get().then(function+(data)+{
++++++++++++++++$scope.myData+=+commonServices.toJson(data);
++++++++++++});
++++++++});|4659790|更简单的方法是在控制器中添加angular.toJson|4659791|+yourApp.controller('Controller',+['$scope',+'Service',++
function+($scope,+Service,+commonServices)+{
++++++++++++Service.get().then(function+(data)+{
++++++++++++++++$scope.myData+=+angular.toJson(data);
++++++++++++});
++++++++});|4659792|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.angularjs.org/api/ng/function/angular.toJson|1^0|2|E|0|0|0|0|0|E|E|1|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@]|9|@$A|10|B|11|1|12]]|C|$]]|$1|D|3|E|5|F|7|13|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|14|8|@]|9|@]|C|$]]|$1|K|3|L|5|F|7|15|8|@]|9|@]|C|$G|H]]|$1|M|3|N|5|6|7|16|8|@]|9|@$A|17|B|18|1|19]]|C|$]]|$1|O|3|P|5|F|7|1A|8|@]|9|@]|C|$G|H]]|$1|Q|3|-4|5|6|7|1B|8|@]|9|@]|C|$]]]|R|$S|$5|T|U|V|C|$W|X]]|Y|$5|T|U|V|C|$W|X]]]]

I did this quick reusable method for <a href="https://docs.angularjs.org/api/ng/function/angular.toJson" rel="nofollow">angular.toJson</a> (Properties with leading $$ will be stripped):

<pre><code>yourApp.factory('Service', ['$resource', function ($resource) {
 return $resource('your/rest/api/path');
}]);

 yourApp.factory('commonServices', function () { 
 return {
 toJson : function(response){
 return JSON.parse(angular.toJson(response));
 //*or* 
 //return angular.toJson(response);
 }
 });
</code></pre>

And then something like this in your controller:

<pre><code> yourApp.controller('Controller', ['$scope', 'Service','commonServices', 
function ($scope, Service, commonServices) {
 Service.get().then(function (data) {
 $scope.myData = commonServices.toJson(data);
 });
 });
</code></pre>

the more simple way is to add <a href="https://docs.angularjs.org/api/ng/function/angular.toJson" rel="nofollow">angular.toJson</a> in the controller 

<pre><code> yourApp.controller('Controller', ['$scope', 'Service', 
function ($scope, Service, commonServices) {
 Service.get().then(function (data) {
 $scope.myData = angular.toJson(data);
 });
 });
</code></pre>

blocks|key|4659875|text|我的项目中的示例|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4659876|Diary.getSharedWithMe(function(data)+{
++++++++delete+data.$promise;
++++++++delete+data.$resolved;
++++++++_self.sharedDiariesWithMe+=+data;
++++},+function(error)+{
++++++++console.log(error)
++++});|code-block|syntax|javascript|4659877|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Example from my project

<pre><code>Diary.getSharedWithMe(function(data) {
 delete data.$promise;
 delete data.$resolved;
 _self.sharedDiariesWithMe = data;
 }, function(error) {
 console.log(error)
 });
</code></pre>

blocks|key|4660041|text|从this+answer上看，yourResource.toJSON()看起来是现成的。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4660042|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/22548161/why-does-angular-resource-add-extra-objects-promise-resolve-to-my-data#answer-29020361^0|F|L|1|B|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]]|D|@$9|Q|A|R|1|S]]|E|$]]|$1|F|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|G|$H|$5|I|J|K|E|$L|M]]]]

From <a href="https://stackoverflow.com/questions/22548161/why-does-angular-resource-add-extra-objects-promise-resolve-to-my-data#answer-29020361">this answer</a>, it looks that <code>yourResource.toJSON()</code> is readily available.

blocks|key|153737|text|请简单地这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|153738|jsonObject.$promise+=未定义；jsonObject.$resolved+=未定义；|153739|$promise和$resolved不会被删除，但您可以执行您想要的操作。|153740|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

Please simply do this:

jsonObject.$promise = undefined;
jsonObject.$resolved = undefined;

$promise and $resolved will not be removed but you will be able to do what you want.

I'm using $resource in angular to get json object and its structure is defined below

<pre><code>[
 {
 "id": 0,
 "name": "Type1"
 },
 {
 "id": 1,
 "name": "Type 2"
 }
]
</code></pre>

after fetching the data .. console.log(jsonObject) gives me

<pre><code>[Resource, Resource, $promise: Object, $resolved: true]
</code></pre>

How can I remove $promise &amp; $resolved from the resulting object ?
I tried angular.fromJson(json) but still I see that these objects still exist.

How to remove $promise and $resolved from json object

JSON

我在angular中使用$resource来获取json对象，其结构定义如下[    {        "id": 0,        "name": "Type1"    },    {        "id": 1,        "name": "Type 2"    }]获取数据后..console.log(j...

问如何从json对象中删除$promise和$resolved
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