如何使用NSURLRequest在Http请求中发送json数据
如何使用NSURLRequest在Http请求中发送json数据
提问于 2010-12-16 10:30:10
我是objective-c的新手，到最近为止，我开始在请求/响应上投入大量的精力。我有一个可以调用url (通过http GET)并解析返回的json的工作示例。
这方面的工作示例如下
- (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response {
[responseData setLength:0];
}
- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data {
[responseData appendData:data];
}
- (void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error {
NSLog([NSString stringWithFormat:@"Connection failed: %@", [error description]]);
}
- (void)connectionDidFinishLoading:(NSURLConnection *)connection {
[connection release];
//do something with the json that comes back ... (the fun part)
}
- (void)viewDidLoad
{
[self searchForStuff:@"iPhone"];
}
-(void)searchForStuff:(NSString *)text
{
responseData = [[NSMutableData data] retain];
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:@"http://www.whatever.com/json"]];
[[NSURLConnection alloc] initWithRequest:request delegate:self];
}我的第一个问题是-这种方法会扩大规模吗？或者这不是异步的(这意味着我在应用程序等待响应时阻塞了UI线程)
我的第二个问题是--我该如何修改请求部分来做POST而不是GET呢？是像这样简单地修改HttpMethod吗？
[request setHTTPMethod:@"POST"];最后-如何将一组json数据作为简单字符串添加到这篇文章中(例如)
{
"magic":{
"real":true
},
"options":{
"happy":true,
"joy":true,
"joy2":true
},
"key":"123"
}提前谢谢你
回答 5
Stack Overflow用户
回答已采纳
发布于 2010-12-17 09:11:39
下面是我要做的(请注意，发送到我的服务器的JSON需要是一个字典，对于key =quest..{：问题字典{ => }} )：
NSArray *objects = [NSArray arrayWithObjects:[[NSUserDefaults standardUserDefaults]valueForKey:@"StoreNickName"],
[[UIDevice currentDevice] uniqueIdentifier], [dict objectForKey:@"user_question"], nil];
NSArray *keys = [NSArray arrayWithObjects:@"nick_name", @"UDID", @"user_question", nil];
NSDictionary *questionDict = [NSDictionary dictionaryWithObjects:objects forKeys:keys];
NSDictionary *jsonDict = [NSDictionary dictionaryWithObject:questionDict forKey:@"question"];
NSString *jsonRequest = [jsonDict JSONRepresentation];
NSLog(@"jsonRequest is %@", jsonRequest);
NSURL *url = [NSURL URLWithString:@"https://xxxxxxx.com/questions"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url
cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0];
NSData *requestData = [jsonRequest dataUsingEncoding:NSUTF8StringEncoding];
[request setHTTPMethod:@"POST"];
[request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setValue:[NSString stringWithFormat:@"%d", [requestData length]] forHTTPHeaderField:@"Content-Length"];
[request setHTTPBody: requestData];
NSURLConnection *connection = [[NSURLConnection alloc]initWithRequest:request delegate:self];
if (connection) {
receivedData = [[NSMutableData data] retain];
}然后，通过以下方式处理receivedData：
NSString *jsonString = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSDictionary *jsonDict = [jsonString JSONValue];
NSDictionary *question = [jsonDict objectForKey:@"question"];这不是100%清楚，需要重新阅读，但一切都应该在这里让你入门。据我所知，这是异步的。在进行这些调用时，我的UI未被锁定。希望这能有所帮助。
Stack Overflow用户
发布于 2015-02-11 23:03:26
我为此挣扎了一段时间。在服务器上运行PHP。此代码将发布一个json，并从服务器获取json回复。
NSURL *url = [NSURL URLWithString:@"http://example.co/index.php"];
NSMutableURLRequest *rq = [NSMutableURLRequest requestWithURL:url];
[rq setHTTPMethod:@"POST"];
NSString *post = [NSString stringWithFormat:@"command1=c1&command2=c2"];
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding];
[rq setHTTPBody:postData];
[rq setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
NSOperationQueue *queue = [[NSOperationQueue alloc] init];
[NSURLConnection sendAsynchronousRequest:rq queue:queue completionHandler:^(NSURLResponse *response, NSData *data, NSError *error)
{
if ([data length] > 0 && error == nil){
NSError *parseError = nil;
NSDictionary *dictionary = [NSJSONSerialization JSONObjectWithData:data options:0 error:&parseError];
NSLog(@"Server Response (we want to see a 200 return code) %@",response);
NSLog(@"dictionary %@",dictionary);
}
else if ([data length] == 0 && error == nil){
NSLog(@"no data returned");
//no data, but tried
}
else if (error != nil)
{
NSLog(@"there was a download error");
//couldn't download
}
}];Stack Overflow用户
发布于 2013-11-12 22:49:47
到目前为止，你们中的大多数人已经知道了这一点，但我发布了这篇文章，以防万一，你们中的一些人仍然在为iOS6+中的JSON而苦苦挣扎。
在iOS6和更高版本中，我们使用的NSJSONSerialization Class速度很快，并且不依赖于包含“外部”库。
NSDictionary *result = [NSJSONSerialization JSONObjectWithData:[resultStr dataUsingEncoding:NSUTF8StringEncoding] options:0 error:nil]; 这是iOS6和更高版本现在可以解析JSON efficiently.The的方式。SBJson的使用也是ARC之前的实现，如果您在ARC环境中工作，也会带来这些问题。
我希望这能帮到你!
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/4456966
复制相关文章
相似问题