我有一个包含一个人的生日的Map
作为GregorianCalendar
。
例如:
{
motherEmailID=null,
coreType=Ticket,
_NULL=null,
additionalFaclitiesProvided=[],
dateOfBirth=java.util.GregorianCalendar[
time=585340200000,
areFieldsSet=false,
areAllFieldsSet=false,
lenient=true,
zone=sun.util.calendar.ZoneInfo[id="GMT",
offset=0,
dstSavings=0,
useDaylight=false,
transitions=0,
lastRule=null],
firstDayOfWeek=1,
minimalDaysInFirstWeek=1,
ERA=1,
YEAR=1988,
MONTH=6,
WEEK_OF_YEAR=30,
WEEK_OF_MONTH=4,
DAY_OF_MONTH=20,
DAY_OF_YEAR=202,
DAY_OF_WEEK=4,
DAY_OF_WEEK_IN_MONTH=3,
AM_PM=0,
HOUR=0,
HOUR_OF_DAY=0,
MINUTE=0,
SECOND=0,
MILLISECOND=0,
ZONE_OFFSET=19800000,
DST_OFFSET=0],
targetEnd=null,
year_semester=null
}
我需要一个Date
,但在我的数据库中它只有Calendar
格式。数据库中列的数据类型为DateTime
。如何获取Date
格式的生日?
发布于 2014-01-29 23:41:37
复制并运行示例。
只需更改模式即可测试不同的开关条件。
对于封装,只需将两个方法设置为私有。格式化日期不是您的工作,因为方法现在返回日期,它取决于调用者使用他想要的任何格式。
import java.util.Date;
import java.util.GregorianCalendar;
public class RandomDateOfBirthGenerator {
private static GregorianCalendar gc = new GregorianCalendar();
public static enum Mode {
SENIOR, ADULT, YOUTH, CHILD
}
public static Date generateRandomDateOfBirth(Mode mode) {
int year = 0;
switch(mode){
case SENIOR:
year = randBetween(1900, 1940);
break;
case ADULT:
year = randBetween(1941, 1995);
break;
case YOUTH:
year = randBetween(1995, 2002);
break;
case CHILD:
year = randBetween(2002, 2014);
break;
}
gc.set(gc.YEAR, year);
int dayOfYear = randBetween(1, gc.getActualMaximum(gc.DAY_OF_YEAR));
gc.set(gc.DAY_OF_YEAR, dayOfYear);
return gc.getTime();
}
private static int randBetween(int start, int end) {
return start + (int) Math.round(Math.random() * (end - start));
}
public static void main(String[] args) {
System.out.println(generateRandomDateOfBirth(Mode.CHILD));
}
}
https://stackoverflow.com/questions/3574811
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