blocks|key|1162683|text|var+dayOfWeek+=+yourDateObject.getDay();
var+isWeekend+=+(dayOfWeek+===+6)+%7C%7C+(dayOfWeek++===+0);+//+6+=+Saturday,+0+=+Sunday|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1162684|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>var dayOfWeek = yourDateObject.getDay();
var isWeekend = (dayOfWeek === 6) || (dayOfWeek === 0); // 6 = Saturday, 0 = Sunday
</code></pre>

blocks|key|1162686|text|var+isWeekend+=+yourDateObject.getDay()%256==0;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1162687|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>var isWeekend = yourDateObject.getDay()%6==0;
</code></pre>

blocks|key|1162711|text|只需在模前加1即可|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1162712|var+isWeekend+=+(yourDateObject.getDay()+%2B+1)+%25+7+==+0;|code-block|syntax|javascript|1162713|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Simply add 1 before modulo

<pre><code>var isWeekend = (yourDateObject.getDay() + 1) % 7 == 0;
</code></pre>

blocks|key|948656|text|简短而甜蜜。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|948657|var+isWeekend+=+([0,6].indexOf(new+Date().getDay())+!=+-1);|offset|length|style|CODE|948658|entityMap^0|0|0|1N|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@$D|L|E|M|F|G]]|9|@]|A|$]]|$1|H|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|I|$]]

Short and sweet.

<code>var isWeekend = ([0,6].indexOf(new Date().getDay()) != -1);</code>

blocks|key|1162734|text|var+d+=+new+Date();
var+n+=+d.getDay();
+if(+n+==+6+)
console.log("Its+weekend!!");
else
console.log("Its+not+weekend");|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1162735|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>var d = new Date();
var n = d.getDay();
 if( n == 6 )
console.log("Its weekend!!");
else
console.log("Its not weekend");
</code></pre>

blocks|key|948703|text|我尝试了正确的答案，它对某些地区有效，但并不适用于所有地区：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|948704|在momentjs+Docs：weekday中，返回的数字取决于区域设置Docs，因此initialWeekDay+=0%7C+Sunday+=6|offset|length|948705|因此，我更改了逻辑以检查实际的周日(‘DayString’)|948706|const+weekday+=+momentObject.format('dddd');+//+Monday+...+Sunday
const+isWeekend+=+weekday+===+'Sunday'+%7C%7C+weekday+===+'Saturday';|code-block|syntax|javascript|948707|这样你就可以独立于语言环境了。|948708|entityMap|0|LINK|mutability|MUTABLE|url|https://momentjs.com/docs/#/get-set/weekday/^0|0|F|7|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@]|9|@$D|Y|E|Z|1|10]]|A|$]]|$1|F|3|G|5|6|7|11|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|12|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|13|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

I tried the Correct answer and it worked for certain locales but not for all:

In momentjs Docs: <a href="https://momentjs.com/docs/#/get-set/weekday/" rel="noreferrer">weekday</a>
The number returned depends on the locale initialWeekDay, so Monday = 0 | Sunday = 6

So I change the logic to check for the actual DayString('Sunday')

<pre><code>const weekday = momentObject.format('dddd'); // Monday ... Sunday
const isWeekend = weekday === 'Sunday' || weekday === 'Saturday';
</code></pre>

This way you are Locale independent.

blocks|key|948724|text|在当前版本中，您应该使用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|948725|++++var+day+=+yourDateObject.day();
++++var+isWeekend+=+(day+===+6)+%7C%7C+(day+===+0);++++//+6+=+Saturday,+0+=+Sunday|code-block|syntax|javascript|948726|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In the current version, you should use 

<pre><code> var day = yourDateObject.day();
 var isWeekend = (day === 6) || (day === 0); // 6 = Saturday, 0 = Sunday
</code></pre>

blocks|key|948748|text|在Date对象上使用.getDay()方法来获取日期。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|948749|检查是6(星期六)还是0(星期日)|948750|var+givenDate+=+new+Date('2020-07-11');
var+day+=+givenDate.getDay();
var+isWeekend+=+(day+===+6)+%7C%7C+(day+===+0)+?+'It's+weekend':+'It's+working+day';
++++
console.log(isWeekend);|code-block|syntax|javascript|948751|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Use .getDay() method on the Date object to get the day.
Check if it is 6 (Saturday) or 0 (Sunday)
<pre class="lang-js prettyprint-override"><code>var givenDate = new Date('2020-07-11');
var day = givenDate.getDay();
var isWeekend = (day === 6) || (day === 0) ? 'It's weekend': 'It's working day';
 
console.log(isWeekend);
</code></pre>

if i have a date coming into a function, how can i tell if its a weekend day?

how to determine if date is weekend in javascript

如果我在函数中有一个日期，我如何判断它是否是周末？

问如何在javascript中确定日期是否为周末
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