blocks|key|514313|text|你可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|514314|replacements+=+[+["☺",+":)"],+["☹",+":("]+]
replacements.each+{%7Creplacement%7C+str.gsub!(replacement[0],+replacement[1])}|code-block|syntax|javascript|514315|可能有一种更有效的解决方案，但这至少使代码更简洁一些|514316|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You could do something like this:

<pre><code>replacements = [ ["☺", ":)"], ["☹", ":("] ]
replacements.each {|replacement| str.gsub!(replacement[0], replacement[1])}
</code></pre>

There may be a more efficient solution, but this at least makes the code a bit cleaner

blocks|key|514338|text|从Ruby1.9.2开始，String#gsub接受哈希作为第二个参数，用于替换为匹配的键。您可以使用正则表达式来匹配需要替换的子字符串，并传递要替换的值的哈希。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|514339|如下所示：|514340|'hello'.gsub(/[eo]/,+'e'+=>+3,+'o'+=>+'*')++++#=>+"h3ll*"
'(0)+123-123.123'.gsub(/[()-,.+]/,+'')++++#=>+"0123123123"|code-block|syntax|javascript|514341|在Ruby+1.8.7中，您可以使用块实现相同的功能：|514342|dict+=+{+'e'+=>+3,+'o'+=>+'*'+}
'hello'.gsub+/[eo]/+do+%7Cmatch%7C
+++dict[match.to_s]
+end+#=>+"h3ll*"|514343|entityMap^0|D|B|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|W|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|X|8|@]|D|@]|E|$]]|$1|O|3|P|5|J|7|Y|8|@]|D|@]|E|$K|L]]|$1|Q|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|R|$]]

Since Ruby 1.9.2, <code>String#gsub</code> accepts hash as a second parameter for replacement with matched keys. You can use a regular expression to match the substring that needs to be replaced and pass hash for values to be replaced.

Like this:

<pre><code>'hello'.gsub(/[eo]/, 'e' =&gt; 3, 'o' =&gt; '*') #=&gt; "h3ll*"
'(0) 123-123.123'.gsub(/[()-,. ]/, '') #=&gt; "0123123123"
</code></pre>

In Ruby 1.8.7, you would achieve the same with a block:

<pre><code>dict = { 'e' =&gt; 3, 'o' =&gt; '*' }
'hello'.gsub /[eo]/ do |match|
 dict[match.to_s]
 end #=&gt; "h3ll*"
</code></pre>

blocks|key|730801|text|设置映射表：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|730802|map+=+{'☺'+=>+':)',+'☹'+=>+':('+}|code-block|syntax|javascript|730803|然后构建一个正则表达式：|730804|re+=+Regexp.new(map.keys.map+{+%7Cx%7C+Regexp.escape(x)+}.join('%7C'))|730805|最后是gsub|offset|length|style|CODE|730806|s+=+str.gsub(re,+map)|730807|如果你被困在1.8版本中，那么：|730808|s+=+str.gsub(re)+{+%7Cm%7C+map[m]+}|730809|如果要替换的任何内容在正则表达式中具有特殊含义，则需要在其中包含Regexp.escape。或者，多亏了steenslag，你可以使用：|730810|re+=+Regexp.union(map.keys)|730811|我们将为您处理报价事宜。|730812|entityMap|0|LINK|mutability|MUTABLE|url|http://ruby-doc.org/core/String.html#method-i-gsub|1|http://ruby-doc.org/core/Regexp.html#method-c-escape^0|0|0|0|0|3|4|3|4|0|0|0|0|0|W|D|W|D|1|0|0|0^^$0|@$1|2|3|4|5|6|7|1C|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|1D|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|1E|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|1F|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|1G|8|@$M|1H|N|1I|O|P]]|9|@$M|1J|N|1K|1|1L]]|A|$]]|$1|Q|3|R|5|D|7|1M|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|1N|8|@]|9|@]|A|$]]|$1|U|3|V|5|D|7|1O|8|@]|9|@]|A|$E|F]]|$1|W|3|X|5|6|7|1P|8|@$M|1Q|N|1R|O|P]]|9|@$M|1S|N|1T|1|1U]]|A|$]]|$1|Y|3|Z|5|D|7|1V|8|@]|9|@]|A|$E|F]]|$1|10|3|11|5|6|7|1W|8|@]|9|@]|A|$]]|$1|12|3|-4|5|6|7|1X|8|@]|9|@]|A|$]]]|13|$14|$5|15|16|17|A|$18|19]]|1A|$5|15|16|17|A|$18|1B]]]]

Set up a mapping table:

<pre><code>map = {'☺' =&gt; ':)', '☹' =&gt; ':(' }
</code></pre>

Then build a regex:

<pre><code>re = Regexp.new(map.keys.map { |x| Regexp.escape(x) }.join('|'))
</code></pre>

And finally, <a href="http://ruby-doc.org/core/String.html#method-i-gsub" rel="noreferrer"><code>gsub</code></a>:

<pre><code>s = str.gsub(re, map)
</code></pre>

If you're stuck in 1.8 land, then:

<pre><code>s = str.gsub(re) { |m| map[m] }
</code></pre>

You need the <a href="http://ruby-doc.org/core/Regexp.html#method-c-escape" rel="noreferrer"><code>Regexp.escape</code></a> in there in case anything you want to replace has a special meaning within a regex. Or, thanks to steenslag, you could use:

<pre><code>re = Regexp.union(map.keys)
</code></pre>

and the quoting will be take care of for you.

blocks|key|514486|text|下面是另一种简单易读的方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|514487|str+=+'12+ene+2013'
map+=+{'ene'+=>+'jan',+'abr'=>'apr',+'dic'=>'dec'}
map.each+{%7Ck,v%7C+str.sub!(k,v)}
puts+str+#+'12+jan+2013'|code-block|syntax|javascript|514488|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Another simple way, and yet easy to read is the following:

<pre><code>str = '12 ene 2013'
map = {'ene' =&gt; 'jan', 'abr'=&gt;'apr', 'dic'=&gt;'dec'}
map.each {|k,v| str.sub!(k,v)}
puts str # '12 jan 2013'
</code></pre>

blocks|key|514515|text|虽然晚了，但如果您想用某个字符替换某些字符，可以使用正则表达式|type|unstyled|depth|inlineStyleRanges|entityRanges|data|514516|string_to_replace.gsub(/_%7C,%7C+/,+'-')|code-block|syntax|javascript|514517|在本例中，gsub将下划线(_)、逗号(，)或()替换为短划线(-)|514518|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Late to the party but if you wanted to replace certain chars with one, you could use a regex

<pre><code>string_to_replace.gsub(/_|,| /, '-')
</code></pre>

In this example, gsub is replacing underscores(_), commas (,) or ( ) with a dash (-)

blocks|key|514564|text|您还可以使用tr一次替换字符串中的多个字符。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|514565|例如，将"h“替换为"m”，将"l“替换为"t”|514566|"hello".tr("hl",+"mt")
+=>+"metto"|code-block|syntax|javascript|514567|看起来比gsub简单、整洁、更快(虽然差别不大)。|514568|puts+Benchmark.measure+{"hello".tr("hl",+"mt")+}
++0.000000+++0.000000+++0.000000+(++0.000007)

puts+Benchmark.measure{"hello".gsub(/[hl]/,+'h'+=>+'m',+'l'+=>+'t')+}
++0.000000+++0.000000+++0.000000+(++0.000021)|514569|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

You can also use tr to replace multiple characters in a string at once, 

Eg., replace "h" to "m" and "l" to "t"

<pre><code>"hello".tr("hl", "mt")
 =&gt; "metto"
</code></pre>

looks simple, neat and faster (not much difference though) than gsub 

<pre><code>puts Benchmark.measure {"hello".tr("hl", "mt") }
 0.000000 0.000000 0.000000 ( 0.000007)

puts Benchmark.measure{"hello".gsub(/[hl]/, 'h' =&gt; 'm', 'l' =&gt; 't') }
 0.000000 0.000000 0.000000 ( 0.000021)
</code></pre>

<pre><code>str = "Hello☺ World☹"
</code></pre>

Expected output is: 

<pre><code>"Hello:) World:("
</code></pre>

I can do this: <code>str.gsub("☺", ":)").gsub("☹", ":(")</code>

Is there any other way so that I can do this in a single function call?. Something like:

<pre><code>str.gsub(['s1', 's2'], ['r1', 'r2'])
</code></pre>

Ruby multiple string replacement

str = "Hello☺ World☹"预期输出为："Hello:) World:("我可以这样做：str.gsub("☺", ":)").gsub("☹", ":(")有没有其他方法可以让我在一次函数调用中完成这项工作？类似于：str.gsub(['s1', 's2'], ['r1', 'r2'])

问Ruby多字符串替换
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