blocks|key|230856|text|我认为JavaScriptSerializer不会创建动态对象。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|230857|因此，您应该首先定义类：|230858|class+MyObj+{
++++public+int+arg1+{get;set;}
++++public+int+arg2+{get;set;}
}|code-block|syntax|javascript|230859|并将其反序列化，而不是object|offset|length|style|CODE|230860|serializer.Deserialize<MyObj>(str);|230861|不是testet，请尝试。|230862|entityMap^0|0|0|0|B|6|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|W|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|X|8|@$K|Y|L|Z|M|N]]|9|@]|A|$]]|$1|O|3|P|5|F|7|10|8|@]|9|@]|A|$G|H]]|$1|Q|3|R|5|6|7|11|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

I think the JavaScriptSerializer does not create a dynamic object.

So you should define the class first:

<pre><code>class MyObj {
 public int arg1 {get;set;}
 public int arg2 {get;set;}
}
</code></pre>

And deserialize that instead of <code>object</code>:

<pre><code>serializer.Deserialize&lt;MyObj&gt;(str);
</code></pre>

Not testet, please try.

blocks|key|227097|text|我相信你正在寻找这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|227098|string+str+=+"{\"Arg1\":\"Arg1Value\",\"Arg2\":\"Arg2Value\"}";
JavaScriptSerializer+serializer1+=+new+JavaScriptSerializer();
object+obje+=+serializer1.Deserialize(str,+obj1.GetType());|code-block|syntax|javascript|227099|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I believe you are looking for this:

<pre><code>string str = "{\"Arg1\":\"Arg1Value\",\"Arg2\":\"Arg2Value\"}";
JavaScriptSerializer serializer1 = new JavaScriptSerializer();
object obje = serializer1.Deserialize(str, obj1.GetType());
</code></pre>

blocks|key|232243|text|同样的问题也发生在我身上。因此，如果服务以JSON字符串的形式返回响应，则必须首先反序列化该字符串，然后才能正确地反序列化其中的对象类型：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|232244|string+json=+string.Empty;
using+(var+streamReader+=+new+StreamReader(response.GetResponseStream(),+true))
++++++++{
++++++++++++json=+new+JavaScriptSerializer().Deserialize<string>(streamReader.ReadToEnd());

++++++++}
//To+deserialize+to+your+object+type...
MyType+myType;
using+(var+memoryStream+=+new+MemoryStream())
+++++++++{
++++++++++++byte[]+jsonBytes+=+Encoding.UTF8.GetBytes(@json);
++++++++++++memoryStream.Write(jsonBytes,+0,+jsonBytes.Length);
++++++++++++memoryStream.Seek(0,+SeekOrigin.Begin);
++++++++++++using+(var+jsonReader+=+JsonReaderWriterFactory.CreateJsonReader(memoryStream,+Encoding.UTF8,++++++++++XmlDictionaryReaderQuotas.Max,+null))
++++++++++++{
++++++++++++++++var+serializer+=+new+DataContractJsonSerializer(typeof(MyType));
++++++++++++++++myType+=+(MyType)serializer.ReadObject(jsonReader);

++++++++++++}
++++++++}|code-block|syntax|javascript|232245|4肯定会成功的.;)|232246|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Same problem happened to me. So if the service returns the response as a JSON string you have to deserialize the string first, then you will be able to deserialize the object type from it properly:

<pre><code>string json= string.Empty;
using (var streamReader = new StreamReader(response.GetResponseStream(), true))
 {
 json= new JavaScriptSerializer().Deserialize&lt;string&gt;(streamReader.ReadToEnd());

 }
//To deserialize to your object type...
MyType myType;
using (var memoryStream = new MemoryStream())
 {
 byte[] jsonBytes = Encoding.UTF8.GetBytes(@json);
 memoryStream.Write(jsonBytes, 0, jsonBytes.Length);
 memoryStream.Seek(0, SeekOrigin.Begin);
 using (var jsonReader = JsonReaderWriterFactory.CreateJsonReader(memoryStream, Encoding.UTF8, XmlDictionaryReaderQuotas.Max, null))
 {
 var serializer = new DataContractJsonSerializer(typeof(MyType));
 myType = (MyType)serializer.ReadObject(jsonReader);

 }
 }
</code></pre>

4 Sure it will work.... ;)

blocks|key|230882|text|这可能很有用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|230883|var+serializer+=+new+JavaScriptSerializer();
dynamic+jsonObject+=+serializer.Deserialize<dynamic>(json);|code-block|syntax|javascript|230884|其中"+JSON“是包含JSON值的字符串。然后，为了从jsonObject中检索值，您可以使用|230885|myProperty+=+Convert.MyPropertyType(jsonObject["myProperty"]);|230886|将MyPropertyType更改为正确的类型(ToInt32、ToString、ToBoolean等)。|230887|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

This may be useful:

<pre><code>var serializer = new JavaScriptSerializer();
dynamic jsonObject = serializer.Deserialize&lt;dynamic&gt;(json);
</code></pre>

Where "json" is the string that contains the JSON values. Then to retrieve the values from the jsonObject you may use

<pre><code>myProperty = Convert.MyPropertyType(jsonObject["myProperty"]);
</code></pre>

Changing MyPropertyType to the proper type (ToInt32, ToString, ToBoolean, etc).

blocks|key|3101929|text|使用以下代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3101930|var+result=JsonConvert.DeserializeObject<List<yourObj>>(jsonString);|code-block|syntax|javascript|3101931|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Use this code:

<pre><code>var result=JsonConvert.DeserializeObject&lt;List&lt;yourObj&gt;&gt;(jsonString);
</code></pre>

blocks|key|3101940|text|解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3101941|+public+Response+Get(string+jsonData)+{
+++++var+json+=+JsonConvert.DeserializeObject<modelname>(jsonData);
+++++var+data+=+StoredProcedure.procedureName(json.Parameter,+json.Parameter,+json.Parameter,+json.Parameter);
+++++return+data;
+}|code-block|syntax|javascript|3101942|型号：|3101943|+public+class+modelname+{
+++++public+long+parameter{+get;+set;+}
+++++public+int+parameter{+get;+set;+}
+++++public+int+parameter{+get;+set;+}
+++++public+string+parameter{+get;+set;+}
+}|3101944|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

solution :

<pre><code> public Response Get(string jsonData) {
 var json = JsonConvert.DeserializeObject&lt;modelname&gt;(jsonData);
 var data = StoredProcedure.procedureName(json.Parameter, json.Parameter, json.Parameter, json.Parameter);
 return data;
 }
</code></pre>

model:

<pre><code> public class modelname {
 public long parameter{ get; set; }
 public int parameter{ get; set; }
 public int parameter{ get; set; }
 public string parameter{ get; set; }
 }
</code></pre>

My Application is in Asp.Net MVC3 coded in C#.
This is what my requirement is. I want an object which is in the following format.This object should be achieved when I deserialize the Json string.

<pre><code>var obj1 = new { arg1=1,arg2=2 };
</code></pre>

<img src="https://i.stack.imgur.com/dbIZR.jpg" alt="enter image description here">

After using the below code:

<pre><code>string str = "{\"Arg1\":\"Arg1Value\",\"Arg2\":\"Arg2Value\"}";
JavaScriptSerializer serializer1 = new JavaScriptSerializer();
object obje = serializer1.Deserialize&lt;object&gt;(str);
</code></pre>

The object what i get i.e obje does not acts as obj1

<img src="https://i.stack.imgur.com/2g2RH.jpg" alt="enter image description here">

Here, in this example my JSON string is static, but actually JSON string is going to be dynamically generated runtime, so i won't be able get Arg1 and Arg2 all the time.

Deserialize JSON string to c# object

JSON

我的应用程序是用Asp.Net MVC3编写的，用C#编写。这就是我的要求。当我反序列化Json字符串时，我想要一个在下面的format.This对象中的对象。var obj1 = new { arg1=1,arg2=2 };​​使用以下代码后：string str = "{\"Arg1\":\"Arg1Value\"...

问将JSON字符串反序列化为c#对象
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