blocks|key|3126585|text|var+date+=+new+Date("2012-01-18T16:03");

console.log(+(date.getMinutes()<10?'0':'')+%2B+date.getMinutes()+);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3126586|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>var date = new Date("2012-01-18T16:03");

console.log( (date.getMinutes()&lt;10?'0':'') + date.getMinutes() );
</code></pre>

blocks|key|3126686|text|这些答案都不是很好，甚至顶部的帖子也是如此。这就是跨浏览器和更干净的int/string转换。另外，我的建议是，不要在像date+=+Date(...)这样的代码中使用名为'date‘的变量，因为这些代码严重依赖于区分语言大小写(这是可行的，但当您使用具有不同规则的不同语言编写的服务器/浏览器代码时，这是有风险的)。所以假设javascript+Date在一个var+current_date中|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3126687|mins+=+('0'%2Bcurrent_date.getMinutes()).slice(-2);|code-block|syntax|javascript|3126688|这个技巧是将最右边的2个字符的(slice(-2))+"0“放在字符串值getMinutes()的前面。所以：|3126689|"0"%2B"12"+->+"012".slice(-2)+->+"12"|3126690|和|3126691|"0"%2B"1"+->+"01".slice(-2)+->+"01"|3126692|entityMap^0|1O|G|55|C|0|0|F|B|10|C|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|10|8|@$9|11|A|12|B|C]|$9|13|A|14|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|16|8|@]|D|@]|E|$]]|$1|Q|3|R|5|H|7|17|8|@]|D|@]|E|$I|J]]|$1|S|3|-4|5|6|7|18|8|@]|D|@]|E|$]]]|T|$]]

Yikes these answers aren't great, even the top post upticked. Here y'go, cross-browser and cleaner int/string conversion. Plus my advice is don't use a variable name 'date' with code like <code>date = Date(...)</code> where you're relying heavily on language case sensitivity (it works, but risky when you're working with server/browser code in different languages with different rules). So assuming the javascript Date in a var <code>current_date</code>:

<pre><code>mins = ('0'+current_date.getMinutes()).slice(-2);
</code></pre>

The technique is take the rightmost 2 characters <code>(slice(-2))</code> of "0" prepended onto the string value of <code>getMinutes()</code>. So:

<pre><code>"0"+"12" -&gt; "012".slice(-2) -&gt; "12"
</code></pre>

and

<pre><code>"0"+"1" -&gt; "01".slice(-2) -&gt; "01"
</code></pre>

blocks|key|242940|text|另一种简单的方法是用前导零填充分钟数，使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|242941|String(date.getMinutes()).padStart(2,+"0");|code-block|syntax|javascript|242942|含义:将字符串设置为两个字符，如果缺少字符，则在此位置设置0。|offset|length|style|CODE|242943|请参阅str.padStart(targetLength,+padString)上的文档|242944|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/padStart^0|0|0|T|1|0|3|11|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@$I|Z|J|10|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|11|8|@]|9|@$I|12|J|13|1|14]]|A|$]]|$1|O|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

Another short way is to fill the minutes with a leading zero using: 

<pre><code>String(date.getMinutes()).padStart(2, "0");
</code></pre>

Meaning: Make the string two chars long, if a char is missing then set <code>0</code> at this position. 

See docs at <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/padStart" rel="noreferrer">str.padStart(targetLength, padString)</a>

blocks|key|241701|text|用于将日期格式化为hh:mm:ss的优雅的ES6函数|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|241702|const+leadingZero+=+(num)+=>+`0${num}`.slice(-2);

const+formatTime+=+(date)+=>
++[date.getHours(),+date.getMinutes(),+date.getSeconds()]
++.map(leadingZero)
++.join(':');|code-block|syntax|javascript|241703|entityMap^0|9|8|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Elegant ES6 function to format a date into <code>hh:mm:ss</code>:

<pre><code>const leadingZero = (num) =&gt; `0${num}`.slice(-2);

const formatTime = (date) =&gt;
 [date.getHours(), date.getMinutes(), date.getSeconds()]
 .map(leadingZero)
 .join(':');
</code></pre>

blocks|key|3126662|text|我想提供一个更整洁的解决方案的问题，如果我may.The接受的答案是非常好的。但我会这样做的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3126663|Date.prototype.getFullMinutes+=+function+()+{
+++if+(this.getMinutes()+<+10)+{
+++++++return+'0'+%2B+this.getMinutes();
+++}
+++return+this.getMinutes();
};|code-block|syntax|javascript|3126664|现在如果你想用这个。|3126665|console.log(date.getFullMinutes());|3126666|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

I would like to provide a more neat solution to the problem if I may.The accepted answer is very good. But I would have done it like this.

<pre><code>Date.prototype.getFullMinutes = function () {
 if (this.getMinutes() &lt; 10) {
 return '0' + this.getMinutes();
 }
 return this.getMinutes();
};
</code></pre>

Now if you want to use this.

<pre><code>console.log(date.getFullMinutes());
</code></pre>

blocks|key|244297|text|我建议：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|244298|var+minutes+=+data.getMinutes();
minutes+=+minutes+>+9+?+minutes+:+'0'+%2B+minutes;|code-block|syntax|javascript|244299|它减少了一个函数调用。考虑性能总是很好的。它也很短；|244300|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I suggest:

<pre><code>var minutes = data.getMinutes();
minutes = minutes &gt; 9 ? minutes : '0' + minutes;
</code></pre>

it is one function call fewer. It is always good to think about performance.
It is short as well;

blocks|key|3126796|text|使用ECMAScript国际化应用编程接口more+info|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3126797|​|3126798|const+date_string+=+"2012-01-18T16:03";
const+date+=+new+Date(date_string);
const+twoDigitMinutes+=+date.toLocaleString("en-us",+{year:+'numeric',+month:+'numeric',+day:+'numeric',+hour:+'2-digit',+minute:+'2-digit',+second:+"2-digit"});

console.log(twoDigitMinutes);|code-block|syntax|javascript|3126799|3126800|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date/toLocaleString^0|L|9|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|T|8|@]|9|@$A|U|B|V|1|W]]|C|$]]|$1|D|3|E|5|6|7|X|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|Y|8|@]|9|@]|C|$I|J]]|$1|K|3|E|5|6|7|Z|8|@]|9|@]|C|$]]|$1|L|3|-4|5|6|7|10|8|@]|9|@]|C|$]]]|M|$N|$5|O|P|Q|C|$R|S]]]]

Using ECMAScript Internationalization API, <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date/toLocaleString" rel="nofollow noreferrer">more info</a>:
<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const date_string = "2012-01-18T16:03";
const date = new Date(date_string);
const twoDigitMinutes = date.toLocaleString("en-us", {year: 'numeric', month: 'numeric', day: 'numeric', hour: '2-digit', minute: '2-digit', second: "2-digit"});

console.log(twoDigitMinutes);</code></pre>
</div>
</div>

blocks|key|2912418|text|另一种选择：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2912419|var+dateTime+=+new+Date();
var+minutesTwoDigitsWithLeadingZero+=+("0"+%2B+dateTime.getMinutes()).substr(-2);|code-block|syntax|javascript|2912420|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Another option:

<pre><code>var dateTime = new Date();
var minutesTwoDigitsWithLeadingZero = ("0" + dateTime.getMinutes()).substr(-2);
</code></pre>

blocks|key|3126582|text|你应该检查它是否小于10...不寻找它的长度，因为这是一个数字而不是一个字符串|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3126583|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

you should check if it is less than 10... not looking for the length of it , because this is a number and not a string

blocks|key|241601|text|我假设您需要字符串形式的值。你可以使用下面的代码。它总是以字符串形式返回两位数的分钟数。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|241602|​|241603|const+date_string+=+"2012-01-18T16:03";
const+date+=+new+Date(date_string);
let+min+=+date.getMinutes();

if+(min+<+10)+{+//+or+min+=+min+<+10+?+'0'+%2B+min+:+min;
+++min+=+'0'+%2B+min;
}+else+{
+++min+=+min+%2B+'';
}

console.log(min);|code-block|syntax|javascript|241604|241605|希望这能有所帮助。|241606|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|P|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|Q|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|R|8|@]|9|@]|A|$]]|$1|L|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|M|$]]

I assume you would need the value as string. You could use the code below.
It will always return give you the two digit minutes as string.
<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const date_string = "2012-01-18T16:03";
const date = new Date(date_string);
let min = date.getMinutes();

if (min &lt; 10) { // or min = min &lt; 10 ? '0' + min : min;
 min = '0' + min;
} else {
 min = min + '';
}

console.log(min);</code></pre>
</div>
</div>

Hope this helps.

blocks|key|244268|text|未定义.length，因为getMinutes返回的是数字，而不是字符串。numbers没有length属性。你可以这样做|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|244269|var+m+=+""+%2B+date.getMinutes();|244270|要使其成为字符串，请先，然后检查长度(您可能希望检查length+===+1，而不是0)。|BOLD|244271|entityMap^0|3|7|D|A|1A|6|0|0|V|0|B|Y|Q|C|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|T|8|@$9|U|A|V|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|W|8|@$9|X|A|Y|B|J]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|K|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|L|$]]

<code>.length</code> is undefined because <code>getMinutes</code> is returning a number, not a string. numbers don't have a <code>length</code> property. You could do

<code>var m = "" + date.getMinutes();</code>

to make it a string, then check the length (you would want to check for <code>length === 1</code>, not 0).

blocks|key|3126709|text|我在这里看不到任何ES6答案，所以我将使用StandardJS格式添加一个|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3126710|//+ES6+String+formatting+example
const+time+=+new+Date()
const+tempMinutes+=+new+Date.getMinutes()
const+minutes+=+(tempMinutes+<+10)+?+`0${tempMinutes}`+:+tempMinutes|code-block|syntax|javascript|3126711|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I dont see any ES6 answers on here so I will add one using StandardJS formatting

<pre><code>// ES6 String formatting example
const time = new Date()
const tempMinutes = new Date.getMinutes()
const minutes = (tempMinutes &lt; 10) ? `0${tempMinutes}` : tempMinutes
</code></pre>

blocks|key|2912651|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2912652|const+date_string+=+"2012-01-18T16:03";
const+date+=+new+Date(date_string);
const+dd+=+date.getDate();
const+MM+=+date.getMonth();
const+mm+=+date.getMinutes();
const+HH+=+date.getHours();

//+Year
const+year+=+date.getFullYear();

//+Month
const+month+=+("0"+%2B+(MM+%2B+1)).slice(-2);+//+first+month+start+from+0,+so+add+%2B1

//+Day
const+day+=+("0"+%2B+dd).slice(-2);

//+Hour
const+hour+=+("0"+%2B+HH).slice(-2);

//+Minutes
const+minutes+=+("0"+%2B+mm).slice(-2);

//+Seconds
const+seconds+=+("0"+%2B+mm).slice(-2);

console.log(year,+month,+day,+hour,+minutes,+seconds);|code-block|syntax|javascript|2912653|2912654|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|K|8|@]|9|@]|A|$E|F]]|$1|G|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|M|8|@]|9|@]|A|$]]]|I|$]]

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const date_string = "2012-01-18T16:03";
const date = new Date(date_string);
const dd = date.getDate();
const MM = date.getMonth();
const mm = date.getMinutes();
const HH = date.getHours();

// Year
const year = date.getFullYear();

// Month
const month = ("0" + (MM + 1)).slice(-2); // first month start from 0, so add +1

// Day
const day = ("0" + dd).slice(-2);

// Hour
const hour = ("0" + HH).slice(-2);

// Minutes
const minutes = ("0" + mm).slice(-2);

// Seconds
const seconds = ("0" + mm).slice(-2);

console.log(year, month, day, hour, minutes, seconds);</code></pre>
</div>
</div>

blocks|key|242946|text|这个怎么样？它对我很有效！:)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|242947|var+d+=+new+Date();
var+minutes+=+d.getMinutes().toString().replace(/%5E(\d)$/,+'0$1');|code-block|syntax|javascript|242948|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

how about this? it works for me! :)

<pre><code>var d = new Date();
var minutes = d.getMinutes().toString().replace(/^(\d)$/, '0$1');
</code></pre>

blocks|key|2912361|text|我通常使用这段代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2912362|var+start+=+new+Date(timestamp),
++++startMinutes+=+start.getMinutes()+<+10+?+'0'+%2B+start.getMinutes()+:+start.getMinutes();|code-block|syntax|javascript|2912363|它非常类似于@ogur接受的答案，但在不需要0的情况下不会连接空字符串。我不确定它是不是更好。这只是另一种方式！|2912364|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I usually use this piece of code :

<pre><code>var start = new Date(timestamp),
 startMinutes = start.getMinutes() &lt; 10 ? '0' + start.getMinutes() : start.getMinutes();
</code></pre>

It is quite similar to the @ogur accepted answer but does not concatenate an empty string in the case that 0 is not needed. Not sure it is better. Just an other way to do it !

blocks|key|3126638|text|$(".min").append(+(date.getMinutes()<10?'0':'')+%2B+date.getMinutes()+);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3126639|JS新手所以这是非常有帮助的大多数人看这个问题也是新的所以这就是我如何让它在名为“class=”min的div中显示的|unstyled|3126640|希望这能帮助到某个人|3126641|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>$(".min").append( (date.getMinutes()&lt;10?'0':'') + date.getMinutes() );
</code></pre>

new to JS so this was very helpful
the most ppl looking at this prob new too
so this is how i got it to show in the div called "class="min"

hope it helps someone

blocks|key|3126775|text|另一种选择是获得两位数的分钟或小时。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3126776|var+date+=+new+Date("2012-01-18T16:03");

var+minutes+=+date.toTimeString().slice(3,+5);+
var+hours+++=+date.toTimeString().slice(0,+2);+|code-block|syntax|javascript|3126777|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Another option to get two digit minutes or hours. 

<pre><code>var date = new Date("2012-01-18T16:03");

var minutes = date.toTimeString().slice(3, 5); 
var hours = date.toTimeString().slice(0, 2); 
</code></pre>

blocks|key|2912640|text|您可以使用moment.js：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2912641|2912642|+moment(date).format('mm')|blockquote|style|CODE|2912643|2912644|2912645|示例：moment('2019-10-29T21:08').format('mm')+==>+08|2912646|希望这能帮助到某个人|2912647|链路github|BOLD|2912648|https://github.com/moment/moment/|2912649|entityMap|0|LINK|mutability|MUTABLE|url|https://momentjs.com/|1^0|5|9|0|0|0|1|P|0|0|0|3|1A|0|0|0|8|0|0|X|1|0^^$0|@$1|2|3|4|5|6|7|13|8|@]|9|@$A|14|B|15|1|16]]|C|$]]|$1|D|3|-4|5|6|7|17|8|@]|9|@]|C|$]]|$1|E|3|F|5|G|7|18|8|@$A|19|B|1A|H|I]]|9|@]|C|$]]|$1|J|3|-4|5|6|7|1B|8|@]|9|@]|C|$]]|$1|K|3|-4|5|6|7|1C|8|@]|9|@]|C|$]]|$1|L|3|M|5|6|7|1D|8|@$A|1E|B|1F|H|I]]|9|@]|C|$]]|$1|N|3|O|5|6|7|1G|8|@]|9|@]|C|$]]|$1|P|3|Q|5|6|7|1H|8|@$A|1I|B|1J|H|R]]|9|@]|C|$]]|$1|S|3|T|5|6|7|1K|8|@]|9|@$A|1L|B|1M|1|1N]]|C|$]]|$1|U|3|-4|5|6|7|1O|8|@]|9|@]|C|$]]]|V|$W|$5|X|Y|Z|C|$10|11]]|12|$5|X|Y|Z|C|$10|T]]]]

You can use <a href="https://momentjs.com/" rel="nofollow noreferrer">moment.js</a> :
<blockquote>
<code>moment(date).format('mm')</code>
</blockquote>
example : <code>moment('2019-10-29T21:08').format('mm') ==&gt; 08</code>
hope it helps someone
Link github: 
<a href="https://github.com/moment/moment/" rel="nofollow noreferrer">https://github.com/moment/moment/</a>

blocks|key|242925|text|对于两位数分钟，请使用：new+Date().toLocaleFormat("%25M")|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|242926|entityMap^0|C|V|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

For two digit minutes use:
<code>new Date().toLocaleFormat("%M")</code>

blocks|key|3126755|text|如果您在项目中使用AngularJS，只需注入$filter并像下面这样使用它：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3126756|$filter('date')(value,+'HH:mm')|code-block|syntax|javascript|3126757|您还可以在模板中格式化输出，有关filters+here的更多信息。|offset|length|3126758|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.angularjs.org/api/ng/filter/filter^0|0|0|O|4|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

If you're using AngularJS in your project, just inject $filter and use it like here:

<pre><code>$filter('date')(value, 'HH:mm')
</code></pre>

You can also format the output in the template, more on filters <a href="https://docs.angularjs.org/api/ng/filter/filter" rel="nofollow noreferrer">here</a>.

<pre><code>var date = "2012-01-18T16:03";
var date = new Date(date);

console.log(date.getMinutes());
console.log(date.getMinutes().length)
</code></pre>

This returns 3. 

<ol>
<li>How do I make it return '03'? </li>
<li>Why does <code>.length</code> return undefinded? </li>
</ol>

I tried this, but it did not work: 

If <code>strlen == 1</code> then <code>num = ('0' + num);</code>

getMinutes() 0-9 - How to display two digit numbers?

服务器

var date = "2012-01-18T16:03";var date = new Date(date);console.log(date.getMinutes());console.log(date.getMinutes().length)这将返回3。如何使其返回'03'？为什么.length返回未定义？我试过了，但不起作用：如果为strlen == 1，则为num = ('0' + nu

问getMinutes() 0-9 -如何显示两位数？
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