blocks|key|489274|text|$LOAD_PATH+<<+Dir.pwd
require+'sql_parser'|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|489275|正如@AndrewGrimm所指出的，出于安全原因，您应该使用以下代码：|unstyled|489276|$LOAD_PATH+<<+File.join(File.dirname(__FILE__))
require+'sql_parser'|489277|您的目录必须在当前加载路径中。加载路径存储在名为$LOAD_PATH的全局数组中。如果将当前目录附加到该目录，则可以使用require加载该目录中的任何文件。|offset|length|style|CODE|489278|使用Dir.pwd而不是锡人建议的pwd.chomp|489279|此外，我更喜欢这种方式而不是require_relative，除非你有一个非常小的项目，否则事情可能会变得丑陋。|489280|entityMap^0|0|0|0|O|A|0|H|3|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|V|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|W|8|@]|9|@]|A|$B|C]]|$1|I|3|J|5|F|7|X|8|@$K|Y|L|Z|M|N]]|9|@]|A|$]]|$1|O|3|P|5|F|7|10|8|@$K|11|L|12|M|N]]|9|@]|A|$]]|$1|Q|3|R|5|F|7|13|8|@]|9|@]|A|$]]|$1|S|3|-4|5|F|7|14|8|@]|9|@]|A|$]]]|T|$]]

<pre><code>$LOAD_PATH &lt;&lt; Dir.pwd
require 'sql_parser'
</code></pre>

As noted by @AndrewGrimm, due to security reasons, you should use this instead:

<pre><code>$LOAD_PATH &lt;&lt; File.join(File.dirname(__FILE__))
require 'sql_parser'
</code></pre>

Your directory has to be in the current load path. The load path is stored in a global array called <code>$LOAD_PATH</code>. If you append your current directory to it, then you can use require to load any files within the directory.

Using Dir.pwd instead of <code>pwd</code>.chomp as suggested by the Tin Man

Also I prefer this over require_relative unless you have a really small project otherwise things can get ugly.

blocks|key|705045|text|在Ruby1.9.x中，您可以使用require_relative方法。参见http://www.ruby-doc.org/core-1.9.3/Kernel.html#method-i-require_relative。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|705046|entityMap|0|LINK|mutability|MUTABLE|url|http://www.ruby-doc.org/core-1.9.3/Kernel.html#method-i-require_relative^0|H|G|12|20|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]]|D|@$9|Q|A|R|1|S]]|E|$]]|$1|F|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|G|$H|$5|I|J|K|E|$L|M]]]]

In ruby 1.9.x, you can use the method <code>require_relative</code>. See <a href="http://www.ruby-doc.org/core-1.9.3/Kernel.html#method-i-require_relative" rel="noreferrer">http://www.ruby-doc.org/core-1.9.3/Kernel.html#method-i-require_relative</a>.

blocks|key|489412|text|在1.9中，语法更改为require_relative，就像这个问题的其他答案所说的那样。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|489413|如果你使用Ruby1.8编写代码，我建议你以前瞻性的方式编写代码，并使用require_relative+gem，这样你就可以在Ruby1.8中使用这个关键字，并在迁移到1.9时少处理一件过渡性的事情|489414|entityMap|0|LINK|mutability|MUTABLE|url|https://rubygems.org/gems/require_relative^0|B|G|0|10|K|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|S|8|@]|D|@$9|T|A|U|1|V]]|E|$]]|$1|H|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|I|$J|$5|K|L|M|E|$N|O]]]]

On 1.9 the syntax changed to <code>require_relative</code>, as the other answers to this question said.

If you are writing in Ruby 1.8, I suggest writing your code in a forward looking manner, and using the <a href="https://rubygems.org/gems/require_relative" rel="nofollow">require_relative gem</a>, so you can use this keyword in your Ruby 1.8 and deal with one less transitional thing when you move to 1.9

blocks|key|489457|text|使用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|489458|$:.unshift+File.join(File.dirname(__FILE__))|code-block|syntax|javascript|489459|以确保您获得的路径是基于脚本所在的位置，而不是执行程序的位置。否则，您将丢弃通过从加载路径中删除"."而获得的安全性优势。|offset|length|style|CODE|489460|(是的，问题的标题谈到要求在运行脚本的目录中有一个文件，但问题的正文提到所需的文件与脚本在同一个文件夹中)|489461|entityMap^0|0|0|1C|3|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Use

<pre><code>$:.unshift File.join(File.dirname(__FILE__))
</code></pre>

to ensure that you're getting a path based on where the script is located, rather than where the program is being executed from. Otherwise, you're throwing away the security benefit gained by removing <code>"."</code> from the load path.

(Yes, the title of the question talks about requiring a file in the directory the script is being run from, but the body of the question mentions that the required file is in the same folder as the script in question)

blocks|key|705193|text|还有..。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|705194|require+"./myRubyFile“#注意，我们从myRubyFile.rb中排除了.rb|705195|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

also...

require "./myRubyFile" # notice we exclude the .rb from myRubyFile.rb

How do I require a file from the current folder?

I have a file called <code>sql_parser.rb</code> that contains a class. I want to include this in another file also in the same folder, so I used:

<pre><code>require 'sql_parser'
</code></pre>

That fails when I run from that folder:

<pre><code>LoadError: no such file to load -- sql_parser
</code></pre>

I tried using IRB in the folder where this file exists and requiring it from there, but had the same issue.

Ruby: how to "require" a file from the current working dir?

如何从当前文件夹中获取文件？我有一个名为sql_parser.rb的文件，其中包含一个类。我想把它包含在同一个文件夹中的另一个文件中，所以我使用：require 'sql_parser'当我从那个文件夹运行时，它失败了：LoadError: no such file to load -- sql_parser我尝试在这...

问Ruby:如何“请求”当前工作目录中的文件？
EN

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问Ruby:如何“请求”当前工作目录中的文件？
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