这个错误会随机出现在我们的MVC应用程序中。有时做同样的事情,有时它不会,有时它会。有没有人知道这是否与任何可能是简单修复的东西有关,或者这是否是你们中的许多人所见过的常见的东西?
System.InvalidOperationException: This request has been blocked because sensitive information could be disclosed to third party web sites when this is used in a GET request. To allow GET requests, set JsonRequestBehavior to AllowGet.
at System.Web.Mvc.JsonResult.ExecuteResult(ControllerContext context)
at System.Web.Mvc.ControllerActionInvoker.InvokeActionResult(ControllerContext controllerContext, ActionResult actionResult)
at System.Web.Mvc.ControllerActionInvoker.<>c__DisplayClass14.b__11()
at System.Web.Mvc.ControllerActionInvoker.InvokeActionResultFilter(IResultFilter filter, ResultExecutingContext preContext, Func`1 continuation)
at System.Web.Mvc.ControllerActionInvoker.<>c__DisplayClass14.<>c__DisplayClass16.b__13()
at System.Web.Mvc.ControllerActionInvoker.InvokeActionResultFilter(IResultFilter filter, ResultExecutingContext preContext, Func`1 continuation)
at System.Web.Mvc.ControllerActionInvoker.<>c__DisplayClass14.<>c__DisplayClass16.b__13()
at System.Web.Mvc.ControllerActionInvoker.InvokeActionResultFilter(IResultFilter filter, ResultExecutingContext preContext, Func`1 continuation)
at System.Web.Mvc.ControllerActionInvoker.<>c__DisplayClass14.<>c__DisplayClass16.b__13()
at System.Web.Mvc.ControllerActionInvoker.InvokeActionResultWithFilters(ControllerContext controllerContext, IList`1 filters, ActionResult actionResult)
at System.Web.Mvc.ControllerActionInvoker.InvokeAction(ControllerContext controllerContext, String actionName)
at System.Web.Mvc.Controller.ExecuteCore()
at System.Web.Mvc.ControllerBase.Execute(RequestContext requestContext)
at System.Web.Mvc.ControllerBase.System.Web.Mvc.IController.Execute(RequestContext requestContext)
at System.Web.Mvc.MvcHandler.<>c__DisplayClass8.b__4()
at System.Web.Mvc.Async.AsyncResultWrapper.<>c__DisplayClass1.b__0()
at System.Web.Mvc.Async.AsyncResultWrapper.<>c__DisplayClass8`1.b__7(IAsyncResult _)
at System.Web.Mvc.Async.AsyncResultWrapper.WrappedAsyncResult`1.End()
at System.Web.Mvc.MvcHandler.EndProcessRequest(IAsyncResult asyncResult)
at System.Web.Mvc.MvcHandler.System.Web.IHttpAsyncHandler.EndProcessRequest(IAsyncResult result)
at System.Web.HttpApplication.CallHandlerExecutionStep.System.Web.HttpApplication.IExecutionStep.Execute()
at System.Web.HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously)
发布于 2011-01-06 23:18:23
您的问题的答案在堆栈跟踪中。"JsonRequestBehavior to AllowGet“
因此,在您的控制器中使用它作为:
return Json(data, JsonRequestBehavior.AllowGet)
发布于 2011-06-22 20:52:05
在绕过这些安全控制之前,您应该先阅读http://haacked.com/archive/2009/06/24/json-hijacking.aspx/。
如果你只暴露你的JSON数据来响应Http POST,那么你就不容易受到这种攻击。
您可以简单地使用HttpPost注释您的JSON操作,然后在客户端执行如下操作
$.post('/blag/JSON', function (data) {
//do something with my json data object here
});
发布于 2011-01-06 23:19:46
似乎您有时会调用每个HTTP GET的控制器操作。为了能够返回JSON结果,您应该使用如下代码
return Json(data, JsonRequestBehavior.AllowGet);
https://stackoverflow.com/questions/4616410
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