blocks|key|3074833|text|从PHP5.3.0开始，您可以使用__DIR__实现此目的。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3074834|3074835|文件的目录。如果在include中使用，则返回包含文件的目录。这等效于dirname(__+FILE__)。|blockquote|3074836|3074837|3074838|参见PHP+Magic+constants。|3074839|C:\www>php+--version
PHP+5.5.6+(cli)+(built:+Nov+12+2013+11:33:44)
Copyright+(c)+1997-2013+The+PHP+Group
Zend+Engine+v2.5.0,+Copyright+(c)+1998-2013+Zend+Technologies

C:\www>php+-r+"echo+__DIR__;"
C:\www|code-block|syntax|javascript|3074840|entityMap|0|LINK|mutability|MUTABLE|url|http://www.php.net/manual/en/language.constants.predefined.php^0|H|7|0|0|0|0|0|2|J|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|13|8|@]|D|@]|E|$]]|$1|G|3|H|5|I|7|14|8|@]|D|@]|E|$]]|$1|J|3|-4|5|6|7|15|8|@]|D|@]|E|$]]|$1|K|3|-4|5|6|7|16|8|@]|D|@]|E|$]]|$1|L|3|M|5|6|7|17|8|@]|D|@$9|18|A|19|1|1A]]|E|$]]|$1|N|3|O|5|P|7|1B|8|@]|D|@]|E|$Q|R]]|$1|S|3|-4|5|6|7|1C|8|@]|D|@]|E|$]]]|T|$U|$5|V|W|X|E|$Y|Z]]]]

As of PHP 5.3.0 you can use <code>__DIR__</code> for this purpose.

<blockquote>
 The directory of the file. If used inside an include, the directory of
 the included file is returned. This is equivalent to
 dirname(__ FILE__).
</blockquote>

See <a href="http://www.php.net/manual/en/language.constants.predefined.php">PHP Magic constants</a>.

<pre><code>C:\www&gt;php --version
PHP 5.5.6 (cli) (built: Nov 12 2013 11:33:44)
Copyright (c) 1997-2013 The PHP Group
Zend Engine v2.5.0, Copyright (c) 1998-2013 Zend Technologies

C:\www&gt;php -r "echo __DIR__;"
C:\www
</code></pre>

blocks|key|3288033|text|如果我正确理解了您的问题，假设您的运行脚本是|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3288034|/relative/path/to/script/index.php|code-block|syntax|javascript|3288035|这将为您提供运行脚本相对于文档www的父目录：|3288036|$parent_dir+=+dirname(dirname($_SERVER['SCRIPT_NAME']))+.+'/';
//$parent_dir+will+be+'/relative/path/to/'|3288037|如果希望运行脚本的父目录相对于服务器根目录：|3288038|$parent_dir+=+dirname(dirname($_SERVER['SCRIPT_FILENAME']))+.+'/';
//$parent_dir+will+be+'/root/some/path/relative/path/to/'|3288039|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

If I properly understood your question, supposing your running script is 

<pre><code>/relative/path/to/script/index.php
</code></pre>

This would give you the parent directory of your running script relative to the document www:

<pre><code>$parent_dir = dirname(dirname($_SERVER['SCRIPT_NAME'])) . '/';
//$parent_dir will be '/relative/path/to/'
</code></pre>

If you want the parent directory of your running script relative to server root:

<pre><code>$parent_dir = dirname(dirname($_SERVER['SCRIPT_FILENAME'])) . '/';
//$parent_dir will be '/root/some/path/relative/path/to/'
</code></pre>

blocks|key|323195|text|来获取当前脚本的parentdir。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|323196|$parent_dir+=+dirname(__DIR__);|code-block|syntax|javascript|323197|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

To get the parentdir of the current script.

<pre><code>$parent_dir = dirname(__DIR__);
</code></pre>

blocks|key|3074742|text|很笨拙，但这就行了：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3074743|substr($_SERVER['SCRIPT_NAME'],+0,+strpos($_SERVER['SCRIPT_NAME'],basename($_SERVER['SCRIPT_NAME'])))|code-block|syntax|javascript|3074744|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Fugly, but this will do it:

<pre><code>substr($_SERVER['SCRIPT_NAME'], 0, strpos($_SERVER['SCRIPT_NAME'],basename($_SERVER['SCRIPT_NAME'])))
</code></pre>

blocks|key|323865|text|我希望这能对你有所帮助。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|323866|echo+getcwd().' ';+//+getcwd()+will+return+current+working+directory
echo+dirname(getcwd(),1).' ';
echo+dirname(getcwd(),2).' ';
echo+dirname(getcwd(),3).' ';|code-block|syntax|javascript|323867|输出：|323868|C:\wamp64\www\public_html\step
C:\wamp64\www\public_html
C:\wamp64\www
C:\wamp64|323869|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

I Hope this will help you.

<pre><code>echo getcwd().'&lt;br&gt;'; // getcwd() will return current working directory
echo dirname(getcwd(),1).'&lt;br&gt;';
echo dirname(getcwd(),2).'&lt;br&gt;';
echo dirname(getcwd(),3).'&lt;br&gt;';
</code></pre>

Output : 

<pre><code>C:\wamp64\www\public_html\step
C:\wamp64\www\public_html
C:\wamp64\www
C:\wamp64
</code></pre>

blocks|key|3074633|text|$dir+=+dirname($file)+.+DIRECTORY_SEPARATOR;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3074634|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$dir = dirname($file) . DIRECTORY_SEPARATOR;
</code></pre>

blocks|key|325839|text|下面是我使用的，因为我没有运行>+5.2|type|unstyled|depth|inlineStyleRanges|entityRanges|data|325840|function+getCurrentOrParentDirectory($type='current')
{
++++if+($type+==+'current')+{
++++++++$path+=+dirname(__FILE__);++
++++}+else+{
++++++++$path+=+dirname(dirname(__FILE__));
++++}
++++$position+=+strrpos($path,+'/')+%2B+1;
++++return+substr($path,+$position);
}|code-block|syntax|javascript|325841|将@mike+b建议的双目录名作为父目录，只需使用一次该语法即可找到当前目录。|325842|注意:此函数仅返回名称，之后必须添加斜杠。|offset|length|style|BOLD|325843|entityMap^0|0|0|0|0|L|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|T|8|@$K|U|L|V|M|N]]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Here is what I use since I am not running > 5.2

<pre><code>function getCurrentOrParentDirectory($type='current')
{
 if ($type == 'current') {
 $path = dirname(__FILE__); 
 } else {
 $path = dirname(dirname(__FILE__));
 }
 $position = strrpos($path, '/') + 1;
 return substr($path, $position);
}
</code></pre>

Double dirname with file as suggested by @mike b for the parent directory, and current directory is found by just using that syntax once.

Note this function only returns the NAME, slashes have to be added afterwards.

blocks|key|323799|text|尝尝这个。可以在windows或linux服务器上运行..|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|323800|str_replace('\'，'/'，dirname(dirname(__FILE__)|323801|entityMap^0|5|O|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|M|8|@]|D|@]|E|$]]|$1|H|3|-4|5|6|7|N|8|@]|D|@]|E|$]]]|I|$]]

Try this. Works on both windows or linux server..

str_replace('\\','/',dirname(dirname(__FILE__)))

blocks|key|3074879|text|这是我使用的一个函数。只创建了一次，所以我总是有这样的功能：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3074880|function+getDir(){
++++$directory+=+dirname(__FILE__);
++++$directory+=+explode("/",$directory);
++++$findTarget+=+0;
++++$targetPath+=+"";
++++foreach($directory+as+$dir){
++++++++if($findTarget+==+1){
++++++++++++$targetPath+=+"".$targetPath."/".$dir."";
++++++++}
++++++++if($dir+==+"public_html"){
++++++++++++$findTarget+=+1;
++++++++}
++++}
++++return+"http://www.".$_SERVER['SERVER_NAME']."".$targetPath."";
}|code-block|syntax|javascript|3074881|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This is a function that I use. Created it once so I always have this functionality:

<pre><code>function getDir(){
 $directory = dirname(__FILE__);
 $directory = explode("/",$directory);
 $findTarget = 0;
 $targetPath = "";
 foreach($directory as $dir){
 if($findTarget == 1){
 $targetPath = "".$targetPath."/".$dir."";
 }
 if($dir == "public_html"){
 $findTarget = 1;
 }
 }
 return "http://www.".$_SERVER['SERVER_NAME']."".$targetPath."";
}
</code></pre>

blocks|key|325983|text|这也是一种可能的解决方案|type|unstyled|depth|inlineStyleRanges|entityRanges|data|325984|$relative+=+'/relative/path/to/script/';
$absolute+=+__DIR__.+'/../'+.$relative;|code-block|syntax|javascript|325985|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This is also a possible solution

<pre><code>$relative = '/relative/path/to/script/';
$absolute = __DIR__. '/../' .$relative;
</code></pre>

blocks|key|3288276|text|我希望这能有所帮助。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3288277|function+get_directory(){
++++$s+=+empty($_SERVER["HTTPS"])+?+''+:+($_SERVER["HTTPS"]+==+"on")+?+"s"+:+"";
++++$protocol+=+substr(strtolower($_SERVER["SERVER_PROTOCOL"]),+0,+strpos(strtolower($_SERVER["SERVER_PROTOCOL"]),+"/"))+.+$s;
++++$port+=+($_SERVER["SERVER_PORT"]+==+"80")+?+""+:+(":".$_SERVER["SERVER_PORT"]);
return+$protocol+.+"://"+.+$_SERVER['SERVER_NAME']+.+dirname($_SERVER['PHP_SELF']);
}
define("ROOT_PATH",+get_directory()."/"+);
echo+ROOT_PATH;|code-block|syntax|javascript|3288278|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I hope this will help

<pre><code>function get_directory(){
 $s = empty($_SERVER["HTTPS"]) ? '' : ($_SERVER["HTTPS"] == "on") ? "s" : "";
 $protocol = substr(strtolower($_SERVER["SERVER_PROTOCOL"]), 0, strpos(strtolower($_SERVER["SERVER_PROTOCOL"]), "/")) . $s;
 $port = ($_SERVER["SERVER_PORT"] == "80") ? "" : (":".$_SERVER["SERVER_PORT"]);
return $protocol . "://" . $_SERVER['SERVER_NAME'] . dirname($_SERVER['PHP_SELF']);
}
define("ROOT_PATH", get_directory()."/" );
echo ROOT_PATH;
</code></pre>

blocks|key|3288020|text|我自己拿到的，有点笨拙，但它是有效的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3288021|substr(dirname($_SERVER['SCRIPT_NAME']),+0,+strrpos(dirname($_SERVER['SCRIPT_NAME']),+'/')+%2B+1)|code-block|syntax|javascript|3288022|所以如果我有/path/to/folder/index.php，结果是/path/to/。|offset|length|style|CODE|3288023|entityMap^0|0|0|6|P|Z|9|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|N|$]]

Got it myself, it's a bit kludgy but it works:

<pre><code>substr(dirname($_SERVER['SCRIPT_NAME']), 0, strrpos(dirname($_SERVER['SCRIPT_NAME']), '/') + 1)
</code></pre>

So if I have <code>/path/to/folder/index.php</code>, this results in <code>/path/to/</code>.

In PHP, what would be the cleanest way to get the parent directory of the current running script relative to the www root? Assume I have:

<pre><code>$_SERVER['SCRIPT_NAME'] == '/relative/path/to/script/index.php'
</code></pre>

Or just:

<pre><code>$something_else == '/relative/path/to/script/'
</code></pre>

And I need to get <code>/relative/path/to/</code> with slashes properly inserted. What would you suggest? A one liner is preferred.

EDIT

I need to get a path relative to the www root, <code>dirname(__FILE__)</code> gives me an absolute path in the filesystem so that won't work. <code>$_SERVER['SCRIPT_NAME']</code> on the other hand 'starts' at the www root.

Get parent directory of running script

文件系统

服务器

在PHP中，获取当前运行的脚本相对于根目录的www父目录的最干净的方法是什么？假设我有：$_SERVER['SCRIPT_NAME'] == '/relative/path/to/script/index.php'或者只是：$something_else == '/relative/path/to/script/'我需要正确插入带斜杠的/relative/path/to/。你有什么建议？单层衬垫是

问获取运行脚本的父目录
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