blocks|key|563444|text|[textField+setKeyboardType:UIKeyboardTypeNumberPad];|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|563445|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>[textField setKeyboardType:UIKeyboardTypeNumberPad];
</code></pre>

blocks|key|563478|text|修改了Michael+Dautermann的回答：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|563479|-+(BOOL)textField:(UITextField+*)textField+shouldChangeCharactersInRange:(NSRange)range+replacementString:(NSString+*)string
{
++++if(string.length+>+0)
++++{
++++++++NSCharacterSet+*numbersOnly+=+[NSCharacterSet+characterSetWithCharactersInString:@"0123456789"];
++++++++NSCharacterSet+*characterSetFromTextField+=+[NSCharacterSet+characterSetWithCharactersInString:string];

++++++++BOOL+stringIsValid+=+[numbersOnly+isSupersetOfSet:characterSetFromTextField];
++++++++return+stringIsValid;
++++}
++++return+YES;
}|code-block|syntax|javascript|563480|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Modified Michael Dautermann's answer:

<pre><code>- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string
{
 if(string.length &gt; 0)
 {
 NSCharacterSet *numbersOnly = [NSCharacterSet characterSetWithCharactersInString:@"0123456789"];
 NSCharacterSet *characterSetFromTextField = [NSCharacterSet characterSetWithCharactersInString:string];

 BOOL stringIsValid = [numbersOnly isSupersetOfSet:characterSetFromTextField];
 return stringIsValid;
 }
 return YES;
}
</code></pre>

blocks|key|563586|text|以下是Swift的解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|563587|在viewDidLoad中设置代理：|563588|_yourTextField.delegate+=+self|code-block|syntax|javascript|563589|let+_acceptableCharacters+=+"0123456789."

func+textField(textField:+UITextField,+shouldChangeCharactersInRange+range:+NSRange,+replacementString+string:+String)+->+Bool+{

++++if+(string.characters.count+==+0)+{
++++++++return+true
++++}

++++if+(textField+==+self._yourTextField)+{
++++++++let+cs+=+NSCharacterSet(charactersInString:+self._acceptableCharacters)
++++++++let+filtered+=+string.componentsSeparatedByCharactersInSet(cs).filter+{++!$0.isEmpty+}
++++++++let+str+=+filtered.joinWithSeparator("")

++++++++return+(string+!=+str)
++++}

++++return+true
}|563590|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|O|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|F|7|P|8|@]|9|@]|A|$G|H]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Here is Swift solution:

In viewDidLoad set the delegate:


<pre><code>_yourTextField.delegate = self
</code></pre>

<pre><code>let _acceptableCharacters = "0123456789."

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -&gt; Bool {

 if (string.characters.count == 0) {
 return true
 }

 if (textField == self._yourTextField) {
 let cs = NSCharacterSet(charactersInString: self._acceptableCharacters)
 let filtered = string.componentsSeparatedByCharactersInSet(cs).filter { !$0.isEmpty }
 let str = filtered.joinWithSeparator("")

 return (string != str)
 }

 return true
}
</code></pre>

blocks|key|563465|text|这是检查字符串是否仅包含数值的函数|type|unstyled|depth|inlineStyleRanges|entityRanges|data|563466|%2B(BOOL)+checkforNumeric:(NSString*)+str
{
++++NSString+*strMatchstring=@"\\b([0-9%25_.%2B\\-]%2B)\\b";+
++++NSPredicate+*textpredicate=[NSPredicate+predicateWithFormat:@"SELF+MATCHES+%25@",+strMatchstring];

++++if(![textpredicate+evaluateWithObject:str])
++++{
++++++++//////NSLog(@"Invalid+email+address+found");
++++++++UIAlertView+*objAlert+=+[[UIAlertView+alloc]+initWithTitle:APP_NAME+message:@"please+enter+valid+text."+delegate:nil+cancelButtonTitle:nil+otherButtonTitles:@"Close",nil];
++++++++[objAlert+show];
++++++++[objAlert+release];
++++++++return+FALSE;
++++}
++++return+TRUE;
}|code-block|syntax|javascript|563467|在提交按钮上选中它。|563468|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

this is the function which checks for the String contains Numeric value only

<pre><code>+(BOOL) checkforNumeric:(NSString*) str
{
 NSString *strMatchstring=@"\\b([0-9%_.+\\-]+)\\b"; 
 NSPredicate *textpredicate=[NSPredicate predicateWithFormat:@"SELF MATCHES %@", strMatchstring];

 if(![textpredicate evaluateWithObject:str])
 {
 //////NSLog(@"Invalid email address found");
 UIAlertView *objAlert = [[UIAlertView alloc] initWithTitle:APP_NAME message:@"please enter valid text." delegate:nil cancelButtonTitle:nil otherButtonTitles:@"Close",nil];
 [objAlert show];
 [objAlert release];
 return FALSE;
 }
 return TRUE;
}
</code></pre>

check it on submit button.

blocks|key|563630|text|This+answer在Swift+3中抛出了一些错误，以下是有效的答案：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|563631|func+textField(_+textField:+UITextField,+shouldChangeCharactersIn+range:+NSRange,+replacementString+string:+String)+->+Bool+{
++++if+string.characters.count+==+0+{
++++++++return+true
++++}
++++do+{
++++++++if+textField+==+self.numberTextField+{

++++++++++++let+nString+=+textField.text+as+NSString?
++++++++++++let+newString+=+nString?.replacingCharacters(in:+range,+with:+string)
++++++++++++let+expression+=+"%5E([0-9]%2B)?(\\.([0-9]{1,2})?)?$"
++++++++++++let+regex+=+try+NSRegularExpression(pattern:+expression,+options:+.caseInsensitive)
++++++++++++let+numberOfMatches+=+regex.numberOfMatches(in:+newString!+as+String,+options:+[],+range:+NSRange(location:+0,+length:+(newString?.characters.count)!))

++++++++++++if+numberOfMatches+==+0+{
++++++++++++++++return+false
++++++++++++}
++++++++}
++++}
++++catch+let+error+{
++++}
++++return+true
}|code-block|syntax|javascript|563632|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/22403622/5620628^0|0|B|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

<a href="https://stackoverflow.com/a/22403622/5620628">This answer</a> threw some error in Swift 3, here's the working answer:

<pre><code>func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -&gt; Bool {
 if string.characters.count == 0 {
 return true
 }
 do {
 if textField == self.numberTextField {

 let nString = textField.text as NSString?
 let newString = nString?.replacingCharacters(in: range, with: string)
 let expression = "^([0-9]+)?(\\.([0-9]{1,2})?)?$"
 let regex = try NSRegularExpression(pattern: expression, options: .caseInsensitive)
 let numberOfMatches = regex.numberOfMatches(in: newString! as String, options: [], range: NSRange(location: 0, length: (newString?.characters.count)!))

 if numberOfMatches == 0 {
 return false
 }
 }
 }
 catch let error {
 }
 return true
}
</code></pre>

blocks|key|563525|text|我只是修改了Michael的答案，使其更容易实现。只需确保UITextfield的委派设置为自身即可。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|563526|yourTxtField.delegate+=+self;|code-block|syntax|javascript|563527|此外，将此代码复制并粘贴到您的主文件中。|563528|-+(BOOL)textField:(UITextField+*)textField+shouldChangeCharactersInRange:(NSRange)range+replacementString:(NSString+*)string++{

++++if+(textField+==+yourTxtField)+{
++++++++NSCharacterSet+*numbersOnly+=+[NSCharacterSet+characterSetWithCharactersInString:@"0123456789"];
++++++++NSCharacterSet+*characterSetFromTextField+=+[NSCharacterSet+characterSetWithCharactersInString:string];

++++++++BOOL+stringIsValid+=+[numbersOnly+isSupersetOfSet:characterSetFromTextField];
++++++++++++return+stringIsValid;
++++++++}else+{
++++++++++++return+YES;
++++++++}
++++}|563529|如果您想允许使用空格键，只需在CharactersInString末尾放一个空格，就像这样：|563530|@"0123456789"+->+@"0123456789+"|563531|此外：|563532|如果您想限制字符串的长度，只需将if-function替换为以下内容：|563533|if+(textField+==+yourTxtField)+{
++++++++NSUInteger+newLength+=+[textField.text+length]+%2B+[string+length]+-+range.length;
++++++++NSCharacterSet+*cs+=+[[NSCharacterSet+characterSetWithCharactersInString:@"1234567890"]+invertedSet];
++++++++NSString+*filtered+=+[[string+componentsSeparatedByCharactersInSet:cs]+componentsJoinedByString:@""];
++++++++return+(([string+isEqualToString:filtered])&&(newLength+<=+10));

++++}|563534|在我的例子中，末尾的"10“表示字符限制。|563535|干杯！:)|563536|entityMap^0|T|B|0|0|0|0|F|I|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@$9|15|A|16|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|17|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|18|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|19|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|1A|8|@$9|1B|A|1C|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|H|7|1D|8|@]|D|@]|E|$I|J]]|$1|S|3|T|5|6|7|1E|8|@]|D|@]|E|$]]|$1|U|3|V|5|6|7|1F|8|@]|D|@]|E|$]]|$1|W|3|X|5|H|7|1G|8|@]|D|@]|E|$I|J]]|$1|Y|3|Z|5|6|7|1H|8|@]|D|@]|E|$]]|$1|10|3|11|5|6|7|1I|8|@]|D|@]|E|$]]|$1|12|3|-4|5|6|7|1J|8|@]|D|@]|E|$]]]|13|$]]

I just modified the answer of Michael and made it a little bit easier to implement. Just make sure that the delegate of your <code>UITextfield</code> is set to itself.

<pre><code>yourTxtField.delegate = self;
</code></pre>

Furthermore copy &amp; paste this code into your main file. 

<pre><code>- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string {

 if (textField == yourTxtField) {
 NSCharacterSet *numbersOnly = [NSCharacterSet characterSetWithCharactersInString:@"0123456789"];
 NSCharacterSet *characterSetFromTextField = [NSCharacterSet characterSetWithCharactersInString:string];

 BOOL stringIsValid = [numbersOnly isSupersetOfSet:characterSetFromTextField];
 return stringIsValid;
 }else {
 return YES;
 }
 }
</code></pre>

If you want to allow the use of the spacebar just put in a blank space at the end of the <code>CharactersInString</code>, just like so:

<pre><code>@"0123456789" -&gt; @"0123456789 "
</code></pre>

<h2>Additionally:</h2>

If you want to restrict the length of the string just replace the if-function with following:

<pre><code>if (textField == yourTxtField) {
 NSUInteger newLength = [textField.text length] + [string length] - range.length;
 NSCharacterSet *cs = [[NSCharacterSet characterSetWithCharactersInString:@"1234567890"] invertedSet];
 NSString *filtered = [[string componentsSeparatedByCharactersInSet:cs] componentsJoinedByString:@""];
 return (([string isEqualToString:filtered])&amp;&amp;(newLength &lt;= 10));

 }
</code></pre>

In my case the "10" at the end represents the limit of characters. 

Cheers! :)

blocks|key|347576|text|Swift+4.2+port+of+the+best+answer由@almas+adlibek提供|type|unstyled|depth|inlineStyleRanges|entityRanges|data|347577|一组配置变量：|347578|private+let+kMaxTextLength+=+8
private+let+kZeroDotted+=+"0."
private+let+kZero+=+"0"
private+let+kDoubleDot+=+".."
private+let+kDot+=+"."
private+let+kPeriod+=+","|code-block|syntax|javascript|347579|现在Swift+4转换了部分代码。|347580|+func+textField(_+textField:+UITextField,+shouldChangeCharactersIn+range:+NSRange,+replacementString+string:+String)+->+Bool+{

++++guard+let+oldText+=+textField.text,+let+swiftRange+=+Range(range,+in:+oldText)+else+{
++++++++return+true
++++}

++++let+newText+=+oldText.replacingCharacters(in:+swiftRange,+with:+string)

++++var+currentText+=++textField.text?.trimmingCharacters(in:+CharacterSet.whitespacesAndNewlines)

++++//+Change+the+","+(appears+in+other+locale+keyboards,+such+as+russian)+key+ot+"."
++++currentText+=+currentText?.replacingOccurrences(of:+kPeriod,+with:+kDot)

++++//+Check+the+statements+of+decimal+value.
++++if+(newText+==+kDot)+{
++++++++textField.text+=+kZeroDotted;
++++++++return+false
++++}

++++if+(newText.range(of:+kDoubleDot)+!=+nil)+{
++++++++textField.text+=+newText.replacingOccurrences(of:+kDoubleDot,+with:+kDot);
++++++++return+false
++++}

++++//+If+second+dot+is+typed,+ignore+it.
++++let+dots+=+newText.components(separatedBy:+kDot)
++++if(dots.count+>+2)+{
++++++++textField.text+=+currentText;
++++++++return+false
++++}

++++//+If+first+character+is+zero+and+second+character+is+>+0,+replace+first+with+second.+05+=>+5;
++++if(newText.count+==+2)+{
++++++++if(newText[0...0]+==+kZero+&&+newText+!=+kZeroDotted)+{
++++++++++++textField.text+=+newText[1...1]
++++++++++++return+false
++++++++}
++++}

++++//+Check+the+max+characters+typed.
++++let+oldLength+=+textField.text?.count+??+0
++++let+replacementLength+=+string.count
++++let+rangeLength+=+range.length

++++let+newLength+=+oldLength+-+rangeLength+%2B+replacementLength;
++++let+returnKey+=+string.rangeOfCharacter(from:+CharacterSet.newlines)+!=+nil

++++return+newLength+<=+kMaxTextLength+%7C%7C+returnKey;
}|347581|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Swift 4.2 port of the best answer here by @almas-adlibek

A bunch of configuration variables:

<pre><code>private let kMaxTextLength = 8
private let kZeroDotted = "0."
private let kZero = "0"
private let kDoubleDot = ".."
private let kDot = "."
private let kPeriod = ","
</code></pre>

Now the Swift 4 converted part of the code.

<pre><code> func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -&gt; Bool {

 guard let oldText = textField.text, let swiftRange = Range(range, in: oldText) else {
 return true
 }

 let newText = oldText.replacingCharacters(in: swiftRange, with: string)

 var currentText = textField.text?.trimmingCharacters(in: CharacterSet.whitespacesAndNewlines)

 // Change the "," (appears in other locale keyboards, such as russian) key ot "."
 currentText = currentText?.replacingOccurrences(of: kPeriod, with: kDot)

 // Check the statements of decimal value.
 if (newText == kDot) {
 textField.text = kZeroDotted;
 return false
 }

 if (newText.range(of: kDoubleDot) != nil) {
 textField.text = newText.replacingOccurrences(of: kDoubleDot, with: kDot);
 return false
 }

 // If second dot is typed, ignore it.
 let dots = newText.components(separatedBy: kDot)
 if(dots.count &gt; 2) {
 textField.text = currentText;
 return false
 }

 // If first character is zero and second character is &gt; 0, replace first with second. 05 =&gt; 5;
 if(newText.count == 2) {
 if(newText[0...0] == kZero &amp;&amp; newText != kZeroDotted) {
 textField.text = newText[1...1]
 return false
 }
 }

 // Check the max characters typed.
 let oldLength = textField.text?.count ?? 0
 let replacementLength = string.count
 let rangeLength = range.length

 let newLength = oldLength - rangeLength + replacementLength;
 let returnKey = string.rangeOfCharacter(from: CharacterSet.newlines) != nil

 return newLength &lt;= kMaxTextLength || returnKey;
}
</code></pre>

blocks|key|347509|text|在文本字段中只输入数值的另一种选择是选择相应文本字段的键盘类型属性。附上截图以供参考。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|347510|📷|atomic|offset|length|347511|​|347512|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/b309200052f44101e5964c3e62f946c9.png|imageAlt^0|0|0|1|0|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|S|8|@]|9|@$E|T|F|U|1|V]]|A|$]]|$1|G|3|H|5|6|7|W|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|X|8|@]|9|@]|A|$]]]|J|$K|$5|L|M|N|A|$O|P|Q|-4]]]]

Another option of entering only numeric values into your text field is by selecting the keyboard type attribute of the corresponding textfield. Attaching the screenshot for reference.<a href="https://i.stack.imgur.com/oaZlb.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/oaZlb.png" alt="Number Pad Selection"></a>

I have UITexfields i want that it should accept only number other shows alert that enter a numeric value.
I want that motionSicknessTextFiled should only accept number 

<pre><code>NSString*dogswithMotionSickness=motionSicknessTextField.text;
NSString*valueOne=cereniaTextField.text;
NSString*valueTwo=prescriptionTextField.text;
NSString*valueThree=otherMeansTextField.text;
NSString*valueFour=overtheCounterTextField.text;
</code></pre>

UITextField Should accept number only values

Swift

我有UITexfields，我希望它应该只接受数字其他显示警报，输入一个数字值。我希望motionSicknessTextFiled应该只接受数字NSString*dogswithMotionSickness=motionSicknessTextField.text;NSString*valueOne=cereniaTextField.text;NSString*valueTwo=prescrip

问UITextField应仅接受数字值
EN

回答 8

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问UITextField应仅接受数字值EN

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问UITextField应仅接受数字值
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