blocks|key|1169330|text|获取上个月的日期很简单|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1169331|echo+date("Y-n-j",+strtotime("first+day+of+previous+month"));
echo+date("Y-n-j",+strtotime("last+day+of+previous+month"));|code-block|syntax|javascript|1169332|11月3日返回|1169333|2014-10-1
2014-10-31|1169334|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

It's simple to get last month date

<pre><code>echo date("Y-n-j", strtotime("first day of previous month"));
echo date("Y-n-j", strtotime("last day of previous month"));
</code></pre>

at November 3 returns

<pre><code>2014-10-1
2014-10-31
</code></pre>

blocks|key|1169268|text|echo+strtotime("-1+month");|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1169269|这将准确地输出上个月的时间戳。之后，您不需要重置任何内容。如果你想在那之后使用英文格式，你可以使用date()来格式化时间戳，例如：|unstyled|offset|length|1169270|echo+date("Y-m-d+H:i:s",strtotime("-1+month"));|1169271|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/date^0|0|1D|6|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|T|8|@]|9|@$G|U|H|V|1|W]]|A|$]]|$1|I|3|J|5|6|7|X|8|@]|9|@]|A|$B|C]]|$1|K|3|-4|5|F|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

<pre><code>echo strtotime("-1 month");
</code></pre>

That will output the timestamp for last month exactly. You don't need to reset anything afterwards. If you want it in an English format after that, you can use <a href="http://php.net/date" rel="noreferrer">date()</a> to format the timestamp, ie:

<pre><code>echo date("Y-m-d H:i:s",strtotime("-1 month"));
</code></pre>

blocks|key|1384371|text|$prevmonth+=+date('M+Y',+strtotime("last+month"));|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1384372|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$prevmonth = date('M Y', strtotime("last month"));
</code></pre>

blocks|key|1169349|text|当前几个月比当前短时，我发现这个错误。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1169350|echo+date("Y-m-d+H:i:s",strtotime("-1+month"));|code-block|syntax|javascript|1169351|在3月30日尝试一下，你会得到2012-03-01而不是2012-02...|1169352|想出更好的解决方案...|1169353|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Found this one wrong when the previous months is shorter than current.

<pre><code>echo date("Y-m-d H:i:s",strtotime("-1 month"));
</code></pre>

Try on March the 30th and you will get 2012-03-01 instead of 2012-02...

Working out on better solution...

blocks|key|1169361|text|echo+date('Y',strtotime("-1+year"));++++++++//last+year 
echo+date('d',strtotime("-1+day"));+++++//last+day 
echo+date('m',strtotime("-1+month"));+++++++//last+month |type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1169362|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>echo date('Y',strtotime("-1 year")); //last year&lt;br&gt;
echo date('d',strtotime("-1 day")); //last day&lt;br&gt;
echo date('m',strtotime("-1 month")); //last month&lt;br&gt;
</code></pre>

blocks|key|1384510|text|如果您只想获取上个月的数据，那么您可以使用如下方法|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1384511|$prevmonth+=+date('M+Y',+strtotime('-1+months'));|code-block|syntax|javascript|1384512|如果您希望获得与上个月相同的日期，则可以使用如下所示。|1384513|$prevmonth+=+date('M+Y+d',+strtotime('-1+months'));|1384514|如果你想得到上个月的最后一个日期，那么你可以像下面这样使用...|1384515|$prevmonth+=+date('M+Y+t',+strtotime('-1+months'));|1384516|如果你想获得上个月的第一个日期，那么你可以像下面这样使用...|1384517|$prevmonth+=+date('M+Y+1',+strtotime('-1+months'));|1384518|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|Y|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|10|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

if you want to get just previous month, then you can use as like following

<pre><code>$prevmonth = date('M Y', strtotime('-1 months'));
</code></pre>

if you want to get same days of previous month, Then you can use as like following ..

<pre><code>$prevmonth = date('M Y d', strtotime('-1 months'));
</code></pre>

if you want to get last date of previous month , Then you can use as like following ...

<pre><code>$prevmonth = date('M Y t', strtotime('-1 months'));
</code></pre>

if you want to get first date of previous month , Then you can use as like following ...

<pre><code>$prevmonth = date('M Y 1', strtotime('-1 months'));
</code></pre>

blocks|key|1169400|text|public+function+getLastMonth()+{
++++$now+=+new+DateTime();
++++$lastMonth+=+$now->sub(new+DateInterval('P1M'));
++++return+$lastMonth->format('Ym');
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1169401|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>public function getLastMonth() {
 $now = new DateTime();
 $lastMonth = $now-&gt;sub(new DateInterval('P1M'));
 return $lastMonth-&gt;format('Ym');
}
</code></pre>

blocks|key|1169418|text|使用此简短代码可获取任意给定日期的前一个月：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1169419|$tgl+=+'25+january+2012';

$prevmonth+=+date("M+Y",mktime(0,0,0,date("m",+strtotime($tgl))-1,1,date("Y",+strtotime($tgl))));
echo+$prevmonth;|code-block|syntax|javascript|1169420|结果是2011年12月。在日数比上个月短的月份上工作。|1169421|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Use this short code to get previous month for any given date:

<pre><code>$tgl = '25 january 2012';

$prevmonth = date("M Y",mktime(0,0,0,date("m", strtotime($tgl))-1,1,date("Y", strtotime($tgl))));
echo $prevmonth;
</code></pre>

The result is December 2011.
Works on a month with shorter day with previous month.

blocks|key|1384574|text|$lastMonth+=+date('M+Y',+strtotime("-1+month"));
var_dump($lastMonth);
$lastMonth+=+date('M+Y',+mktime(0,+0,+0,+date('m')+-+1,+1,+date('Y')));
var_dump($lastMonth);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1384575|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$lastMonth = date('M Y', strtotime("-1 month"));
var_dump($lastMonth);
$lastMonth = date('M Y', mktime(0, 0, 0, date('m') - 1, 1, date('Y')));
var_dump($lastMonth);
</code></pre>

blocks|key|1384358|text|哦，我想出来了，请忽略，除非你有我在这种情况下遇到的相同问题：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1384359|$prevmonth+=+date("M+Y",mktime(0,0,0,date("m")-1,1,date("Y")));|code-block|syntax|javascript|1384360|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Oh I figured this out, please ignore unless you have the same problem i did in which case:

<pre><code>$prevmonth = date("M Y",mktime(0,0,0,date("m")-1,1,date("Y")));
</code></pre>

blocks|key|1169312|text|您可以使用strtotime，它在这种情况下非常好用：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1169313|$timestamp+=+strtotime('-1+month');
var_dump(date('Y-m',+$timestamp));|code-block|syntax|javascript|1169314|将会给你带来：|1169315|string+'2009-11'+(length=7)|1169316|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/strtotime^0|5|9|5|9|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@$9|Z|A|10|1|11]]|E|$]]|$1|F|3|G|5|H|7|12|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|13|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|14|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|15|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]]]

You can use <a href="http://php.net/strtotime" rel="nofollow noreferrer"><code>strtotime</code></a>, which is great in this kind of situations :

<pre><code>$timestamp = strtotime('-1 month');
var_dump(date('Y-m', $timestamp));
</code></pre>

Will get you :

<pre><code>string '2009-11' (length=7)
</code></pre>

blocks|key|1384438|text|$time+=+mktime(0,+0,+0,+date("m"),date("d")-date("t"),+date("Y"));
$lastMonth+=+date("d-m-Y",+$time);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1384439|或|unstyled|1384440|$lastMonth+=+date("m-Y",+mktime()+-+31*3600*24);|1384441|在30.03.2012上工作|1384442|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$B|C]]|$1|I|3|J|5|F|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>$time = mktime(0, 0, 0, date("m"),date("d")-date("t"), date("Y"));
$lastMonth = date("d-m-Y", $time);
</code></pre>

OR

<pre><code>$lastMonth = date("m-Y", mktime() - 31*3600*24);
</code></pre>

works on 30.03.2012

blocks|key|1169515|text|我找到的最好的解决方案是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1169516|function+subtracMonth($currentMonth,+$monthsToSubtract){
++++++++$finalMonth+=+$currentMonth;
++++++++for($i=0;$i<$monthsToSubtract;$i%2B%2B)+{
++++++++++++$finalMonth--;
++++++++++++if+($finalMonth=='0'){
++++++++++++++++$finalMonth+=+'12';
++++++++++++}

++++++++}
++++++++return+$finalMonth;

++++}|code-block|syntax|javascript|1169517|因此，如果我们在3(3月份)，我们想要减去5个月，这将是|1169518|subtractMonth(3,5);|offset|length|style|CODE|1169519|这将得到10(10月份)。如果还需要年份，可以这样做：|1169520|function+subtracMonth($currentMonth,+$monthsToSubtract){
++++$finalMonth+=+$currentMonth;
++++$totalYearsToSubtract+=+0;
++++for($i=0;$i<$monthsToSubtract;$i%2B%2B)+{
++++++++$finalMonth--;
++++++++if+($finalMonth=='0'){
++++++++++++$finalMonth+=+'12';
++++++++++++$totalYearsToSubtract%2B%2B;
++++++++}

++++}
++++//Get+$currentYear
++++//Calculate+$finalYear+=+$currentYear+-+$totalYearsToSubtract+
++++//Put+resulting+$finalMonth+and+$finalYear+into+an+object+as+attributes
++++//Return+the+object

}|1169521|entityMap^0|0|0|0|0|J|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|X|8|@$K|Y|L|Z|M|N]]|9|@]|A|$]]|$1|O|3|P|5|6|7|10|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

The best solution I have found is this:
<pre><code>function subtracMonth($currentMonth, $monthsToSubtract){
 $finalMonth = $currentMonth;
 for($i=0;$i&lt;$monthsToSubtract;$i++) {
 $finalMonth--;
 if ($finalMonth=='0'){
 $finalMonth = '12';
 }

 }
 return $finalMonth;

 }
</code></pre>
So if we are in 3(March) and we want to subtract 5 months that would be
<code>subtractMonth(3,5);</code>
which would give 10(October). If the year is also desired, one could do this:
<pre><code>function subtracMonth($currentMonth, $monthsToSubtract){
 $finalMonth = $currentMonth;
 $totalYearsToSubtract = 0;
 for($i=0;$i&lt;$monthsToSubtract;$i++) {
 $finalMonth--;
 if ($finalMonth=='0'){
 $finalMonth = '12';
 $totalYearsToSubtract++;
 }

 }
 //Get $currentYear
 //Calculate $finalYear = $currentYear - $totalYearsToSubtract 
 //Put resulting $finalMonth and $finalYear into an object as attributes
 //Return the object

}
</code></pre>

blocks|key|1169395|text|它对我来说很有效：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1169396|今天是:+31/03/2012|1169397|echo+date("Y-m-d",+strtotime(date('m',+mktime()+-+31*3600*24).'/01/'.date('Y').'+00:00:00'));+//+2012-02-01
echo++date("Y-m-d",+mktime()+-+31*3600*24);+//+2012-02-29|code-block|syntax|javascript|1169398|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

It works for me: 

Today is: 31/03/2012

<pre><code>echo date("Y-m-d", strtotime(date('m', mktime() - 31*3600*24).'/01/'.date('Y').' 00:00:00')); // 2012-02-01
echo date("Y-m-d", mktime() - 31*3600*24); // 2012-02-29
</code></pre>

blocks|key|1169459|text|如果你想获得上个月的第一个日期，那么你可以像下面这样使用...+$prevmonth+=+date('M+Y+1',+strtotime('-1+months'));+what？第一个日期将始终为1+:D|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1169460|entityMap^0|W|1F|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

If you want to get first date of previous month , Then you can use as like following ... <code>$prevmonth = date('M Y 1', strtotime('-1 months'));</code> what? first date will always be 1 :D

blocks|key|1169485|text|这个问题很老了，但不管怎样，还是要问这个问题。如果您只想获取上个月的数据，那么日期并不重要，您可以使用以下命令：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1169486|$date+=+'2014-01-03';

$dateTime+=+new+DateTime($date);

$lastMonth+=+$dateTime->modify('-'+.+$dateTime->format('d')+.+'+days')->format('F+Y');

echo+$lastMonth;+//+'December+2013'|code-block|syntax|javascript|1169487|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This question is quite old but here goes anyway. If you're trying to get just the previous month and the day does not matter you can use this:

<pre><code>$date = '2014-01-03';

$dateTime = new DateTime($date);

$lastMonth = $dateTime-&gt;modify('-' . $dateTime-&gt;format('d') . ' days')-&gt;format('F Y');

echo $lastMonth; // 'December 2013'
</code></pre>

I want to get last month's date. I wrote this out:

<pre><code>$prevmonth = date('M Y');
</code></pre>

Which gives me the current month/year. I can't tell if I should use <code>strtotime</code>, <code>mktime</code>. Something to the timestamp? Do I need to add something afterwards to reset so that the date isn't set to last month throughout everything for all timestamps on my site? I'm trying to RTM but it's hard for me to figure this out.

Getting last month's date in php

我想要上个月的日期。我写下了这个：$prevmonth = date('M Y');这给了我当前的月份/年份。我不知道我是否应该使用strtotime，mktime。时间戳有什么问题吗？我是否需要在之后添加一些内容来重置，这样我的站点上的所有时间戳的日期都不会被设置为上个月？我正在尝试RTM，但对我来说很难弄清楚。

问获取上个月的日期
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