我们不能在python生成器函数中产生多个值吗?
例如,
In [677]: def gen():
.....: for i in range(5):
.....: yield i, i+1
.....:
In [680]: k1, k2 = gen()
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
<ipython-input-680-b21f6543a7e9> in <module>()
----> 1 k1, k2 = a()
ValueError: too many values to unpack
它的工作原理如下:
In [678]: b = a()
In [679]: list(b)
Out[679]: [(0, 1), (1, 2), (2, 3), (3, 4), (4, 5)]
即使我这样做,结果也是一样的:
In [692]: def a():
for i in range(5):
yield i
yield i+1
谢谢。
发布于 2013-05-31 19:31:01
从您给出的示例判断,您的函数gen
返回一个生成器,而不是您所期望的值。如果在生成器上迭代,将产生成对的值:
In [2]: def gen():
...: for i in range(5):
...: yield i, i+1
...:
In [3]: for k1, k2 in gen():
...: print k1, k2
...:
0 1
1 2
2 3
3 4
4 5
https://stackoverflow.com/questions/16856251
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