blocks|key|759239|text|使用stringi包中的此函数|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|759240|>+x+<-+'hello+stackoverflow'
>+stri_sub(x,2)
[1]+"ello+stackoverflow"|code-block|syntax|javascript|759241|entityMap^0|2|7|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Use this function from <code>stringi</code> package

<pre><code>&gt; x &lt;- 'hello stackoverflow'
&gt; stri_sub(x,2)
[1] "ello stackoverflow"
</code></pre>

blocks|key|542711|text|删除前几个字符：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|542712|x+<-+'hello+stackoverflow'
substring(x,+2,+nchar(x))|code-block|syntax|javascript|542713|想法是选择从2开始的所有字符到x中的字符数。当单词或短语中的字符数不相等时，这一点很重要。|542714|与前面的答案一样，选择第一个字母很简单：|542715|substring(x,1,1)|542716|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|S|8|@]|9|@]|A|$E|F]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

removing first characters: 

<pre><code>x &lt;- 'hello stackoverflow'
substring(x, 2, nchar(x))
</code></pre>

Idea is select all characters starting from 2 to number of characters in x. This is important when you have unequal number of characters in word or phrase. 

Selecting the first letter is trivial as previous answers:

<pre><code>substring(x,1,1)
</code></pre>

blocks|key|542779|text|substring绝对是最好的，但这里有一个strsplit替代方案，因为我还没有见过一个。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|542780|>+x+<-+'hello+stackoverflow'
>+strsplit(x,+'')[[1]][1]
##+[1]+"h"|code-block|syntax|javascript|542781|或等同于|542782|>+unlist(strsplit(x,+''))[1]
##+[1]+"h"|542783|你可以用paste把剩下的字符串重新组合在一起。|542784|>+paste0(strsplit(x,+'')[[1]][-1],+collapse+=+'')
##+[1]+"ello+stackoverflow"|542785|entityMap^0|0|9|M|8|0|0|0|0|4|5|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|10|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|12|8|@$9|13|A|14|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|S|3|-4|5|6|7|16|8|@]|D|@]|E|$]]]|T|$]]

<code>substring</code> is definitely best, but here's one <code>strsplit</code> alternative, since I haven't seen one yet.

<pre><code>&gt; x &lt;- 'hello stackoverflow'
&gt; strsplit(x, '')[[1]][1]
## [1] "h"
</code></pre>

or equivalently

<pre><code>&gt; unlist(strsplit(x, ''))[1]
## [1] "h"
</code></pre>

And you can <code>paste</code> the rest of the string back together.

<pre><code>&gt; paste0(strsplit(x, '')[[1]][-1], collapse = '')
## [1] "ello stackoverflow"
</code></pre>

blocks|key|542819|text|还有来自stringr包的str_sub|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|542820|x+<-+'hello+stackoverflow'
str_sub(x,+2)+#+or
str_sub(x,+2,+str_length(x))
[1]+"ello+stackoverflow"|code-block|syntax|javascript|542821|entityMap^0|D|7|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

There is also <code>str_sub</code> from the stringr package

<pre><code>x &lt;- 'hello stackoverflow'
str_sub(x, 2) # or
str_sub(x, 2, str_length(x))
[1] "ello stackoverflow"
</code></pre>

blocks|key|759450|text|使用sub函数的另一种方式。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|759451|+sub('(%5E.).*',+'\\1',+'hello+stackoverflow')
+[1]+"h"

+sub('(%5E.)(.*)',+'\\2',+'hello+stackoverflow')
+[1]+"ello+stackoverflow"|code-block|syntax|javascript|759452|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Another way using the sub function.
<pre><code> sub('(^.).*', '\\1', 'hello stackoverflow')
 [1] &quot;h&quot;

 sub('(^.)(.*)', '\\2', 'hello stackoverflow')
 [1] &quot;ello stackoverflow&quot;
</code></pre>

I would like to do some 2-dimensional walks using strings of characters by assigning different values to each character. I was planning to 'pop' the first character of a string, use it, and repeat for the rest of the string.

How can I achieve something like this?

<pre><code>x &lt;- 'hello stackoverflow'
</code></pre>

I'd like to be able to do something like this:

<pre><code>a &lt;- x.pop[1]

print(a)

'h'
print(x)

'ello stackoverflow'
</code></pre>

Getting and removing the first character of a string

我想使用字符串通过为每个字符分配不同的值来进行一些二维漫游。我打算“弹出”字符串的第一个字符，使用它，然后对字符串的其余部分重复此操作。我怎么才能实现这样的事情呢？x <- 'hello stackoverflow'我希望能够做这样的事情：a <- x.pop[1]print(a)'h'print(x)'ello st...

问获取和删除字符串的第一个字符
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