blocks|key|2655102|text|我在UIColor扩展中也遇到了这个问题，除了一些使用Objective-c的框架之外，我的应用程序完全是用var编写的，所以我可以毫不费力地将@nonobjc声明为swift|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2655103|extension+UIColor+{
+++@nonobjc+static+var+lol:+UIColor+{
++++++return+UIColor.red
+++}
}|code-block|syntax|javascript|2655104|来自苹果文档：|2655105|2655106|非code属性告诉编译器使声明在Objective-C代码中不可用...|blockquote|2655107|2655108|2655109|由于此代码对Objective-C不可用，因此警告消失。|2655110|entityMap^0|2|7|1I|3|20|8|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|14|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|15|8|@]|D|@]|E|$]]|$1|N|3|O|5|P|7|16|8|@]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|17|8|@]|D|@]|E|$]]|$1|R|3|-4|5|6|7|18|8|@]|D|@]|E|$]]|$1|S|3|T|5|6|7|19|8|@]|D|@]|E|$]]|$1|U|3|-4|5|6|7|1A|8|@]|D|@]|E|$]]]|V|$]]

I also had this issue in a <code>UIColor</code> extension, my app is entirely made with swift except for some frameworks that use Objective-c so I have no problem in declaring the <code>var</code> as <code>@nonobjc</code>:

<pre><code>extension UIColor {
 @nonobjc static var lol: UIColor {
 return UIColor.red
 }
}
</code></pre>

From the apple docs:

<blockquote>
 The nonobjc attribute tells the compiler to make the declaration unavailable in Objective-C code...
</blockquote>

Since this code is unavailable to Objective-C the warning disappears.

blocks|key|109707|text|在我的例子中，原因是在扩展中具有计算类型属性：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|109708|extension+NSParagraphStyle+{
++++class+var+defaultStyle:+NSParagraphStyle+{
++++++++return+...
++++}
}|code-block|syntax|javascript|109709|不确定这背后的确切原因，但为了消除警告，我必须将计算类型属性(class+var)转换为类型方法(class+func)：|offset|length|style|BOLD|CODE|109710|extension+NSParagraphStyle+{
++++class+func+defaultStyle()+->+NSParagraphStyle+{
++++++++return+...
++++}
}|109711|entityMap^0|0|0|V|9|1D|A|V|9|1D|A|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|S|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|T|8|@$I|U|J|V|K|L]|$I|W|J|X|K|L]|$I|Y|J|Z|K|M]|$I|10|J|11|K|M]]|9|@]|A|$]]|$1|N|3|O|5|D|7|12|8|@]|9|@]|A|$E|F]]|$1|P|3|-4|5|6|7|13|8|@]|9|@]|A|$]]]|Q|$]]

In my case, the reason was having computed type property in an extension:

<pre><code>extension NSParagraphStyle {
 class var defaultStyle: NSParagraphStyle {
 return ...
 }
}
</code></pre>

Not sure what the exact reason behind this is, but to get rid of the warning I had to convert the computed type property (<code>class var</code>) to a type method (<code>class func</code>):

<pre><code>extension NSParagraphStyle {
 class func defaultStyle() -&gt; NSParagraphStyle {
 return ...
 }
}
</code></pre>

blocks|key|2866190|text|在我的应用程序中添加了一个使用Objective-C的框架后，这个警告出现在我的项目中，否则它将完全使用Swift+3。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2866191|通过声明所有静态函数和静态变量+in+all+extensions+as+@nonobjc，这个警告消失了。|offset|length|style|BOLD|CODE|2866192|例如|2866193|extension+Notification.Name+{
++++@nonobjc+static+let+MyNotificationName+=+Notification.Name("NNSongFavoriteStatusDidChangeNotification")
}|code-block|syntax|javascript|2866194|或|2866195|extension+UIColor+{
++++@nonobjc+static+let+superGiantRed+=+UIColor(red:+180.0/255.0,+green:+40.0/255.0,+blue:+27.0/255.0,+alpha:+1.0)
}|2866196|entityMap^0|0|4|B|J|E|11|8|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|W|8|@$D|X|E|Y|F|G]|$D|Z|E|10|F|G]|$D|11|E|12|F|H]]|9|@]|A|$]]|$1|I|3|J|5|6|7|13|8|@]|9|@]|A|$]]|$1|K|3|L|5|M|7|14|8|@]|9|@]|A|$N|O]]|$1|P|3|Q|5|6|7|15|8|@]|9|@]|A|$]]|$1|R|3|S|5|M|7|16|8|@]|9|@]|A|$N|O]]|$1|T|3|-4|5|6|7|17|8|@]|9|@]|A|$]]]|U|$]]

This warning appeared in my project after adding a framework that used Objective-C in my application that otherwise used Swift 3 entirely.

By declaring all static functions and static variables in all extensions as <code>@nonobjc</code> this warning went away.

For example

<pre><code>extension Notification.Name {
 @nonobjc static let MyNotificationName = Notification.Name("NNSongFavoriteStatusDidChangeNotification")
}
</code></pre>

or

<pre><code>extension UIColor {
 @nonobjc static let superGiantRed = UIColor(red: 180.0/255.0, green: 40.0/255.0, blue: 27.0/255.0, alpha: 1.0)
}
</code></pre>

blocks|key|2866099|text|谷歌分析+pod|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|2866100|在Build+Settings+->+Other+Linker+Flags中，如果您有-ObjC+on+Linker标志，则会出现此警告。我不知道为什么，也不知道如何解决，但也可能是你的问题。|2866101|entityMap^0|0|4|0|1|10|17|5|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|R|8|@]|D|@]|E|$]]]|I|$]]

Google Analytics pod 

In Build Settings -> Other Linker Flags if you have the -ObjC on -l"GoogleAnalytics" flag this warning will appear. I don`t know why or how to resolve, but can be your problem too.

blocks|key|2866221|text|在我的例子中，它是一个类变量。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2866222|public+extension+NSObject+{
++++public+class+var+nameOfClass:+String{
++++++++return+NSStringFromClass(self).components(separatedBy:+".").last!
++++}|code-block|syntax|javascript|2866223|添加@nonobjc会有所帮助。|2866224|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

In my case it was a class variable.

<pre><code>public extension NSObject {
 public class var nameOfClass: String{
 return NSStringFromClass(self).components(separatedBy: ".").last!
 }
</code></pre>

Adding @nonobjc helped.

blocks|key|2655016|text|对我来说，问题是我在使用Xcode+8构建的Swift+3应用程序中使用的第三方框架来自使用Xcode+7构建的供应商。因为该框架是编译后的二进制文件，所以我唯一的选择就是向供应商索要一个使用最新版本的Xcode构建的新框架。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2655017|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

For me the issue was that I was using a third-party framework from a vendor built with Xcode 7 in my Swift 3 application built with Xcode 8. Because the framework was a compiled binary, the only option I had was to ask my vendor for a new framework built with the latest version of Xcode.

blocks|key|109856|text|当我将"class+var“改为"class+func”时，我能够解决我的问题：|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|109857|是这样的：|109858|class+var+applicationVersionNumber:+String+{
++++if+let+version+=+Bundle.main.infoDictionary?["CFBundleShortVersionString"]+as?+String+{
++++++++return+version
++++}
++++return+"Version+Number+Not+Available"
}|code-block|syntax|javascript|109859|已经变成：|109860|class+func+applicationVersionNumber()+->+String+{
++++if+let+version+=+Bundle.main.infoDictionary?["CFBundleShortVersionString"]+as?+String+{
++++++++return+version
++++}
++++return+"Version+Number+Not+Available"
}|109861|来源：|109862|entityMap^0|4|9|H|A|0|0|5|0|0|0|5|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Z|8|@$9|10|A|11|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|12|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|13|8|@$9|14|A|15|B|C]]|D|@]|E|$]]|$1|O|3|P|5|J|7|16|8|@]|D|@]|E|$K|L]]|$1|Q|3|R|5|6|7|17|8|@]|D|@]|E|$]]|$1|S|3|-4|5|6|7|18|8|@]|D|@]|E|$]]]|T|$]]

I was able to solve my problem when I changed the "class var" to "class func":

There was:

<pre><code>class var applicationVersionNumber: String {
 if let version = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String {
 return version
 }
 return "Version Number Not Available"
}
</code></pre>

Has become:

<pre><code>class func applicationVersionNumber() -&gt; String {
 if let version = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String {
 return version
 }
 return "Version Number Not Available"
}
</code></pre>

Source: <a href="https://forums.developer.apple.com/message/146579#146579" rel="nofollow noreferrer">https://forums.developer.apple.com/message/146579#146579</a>

blocks|key|112453|text|您可以将整个扩展标记为@nonobjc，而不是将每个成员单独标记为@nonobjc|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|112454|@nonobjc+extension+UIStoryboard+{
++static+let+main+=+UIStoryboard(name:+"Main",+bundle:+nil)
++static+let+welcome+=+UIStoryboard(name:+"Main",+bundle:+nil)
}|code-block|syntax|javascript|112455|entityMap^0|B|8|X|8|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

Rather than marking each member as <code>@nonobjc</code> individually, you can instead mark the entire extension as <code>@nonobjc</code>:

<pre><code>@nonobjc extension UIStoryboard {
 static let main = UIStoryboard(name: "Main", bundle: nil)
 static let welcome = UIStoryboard(name: "Main", bundle: nil)
}
</code></pre>

I'm using Xcode 8 and Swift 3.0. What does this error message mean?

<blockquote>
 ld: warning: Some object files have incompatible Objective-C category definitions. Some category metadata may be lost. All files containing Objective-C categories should be built using the same compiler.
</blockquote>

Xcode 8 Objective-C category warning

Objective-C

编译器

Swift

Xcode

我使用的是Xcode8和Swift 3.0。此错误消息是什么意思？ % ld:警告:某些对象文件具有不兼容的Objective-C类别定义。某些类别元数据可能会丢失。所有包含Objective-C类别的文件都应该使用相同的编译器构建。

问Xcode 8 Objective-C类别警告
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回答 8

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