makeHttpRequest中的换行符
makeHttpRequest中的换行符
提问于 2015-05-29 13:19:19
我收到一个java.lang.IllegalStateException: Target host must not be null, or set in parameters错误。做makeHttpRequest的时候是换行符吗，还是我走错了路？代码：
String url = "http://www.<myDomain>.co.za/insertTeamResultwithCode.php?Code="+code+
"&Section="+section+
"&Gender="+gender+
"&WinningTeam="+newResult.getWinningTeam()+
"&LosingTeam="+newResult.getLosingTeam()+
"&FixtureD="+newResult.getDate()+
"&FixtureT="+newResult.getTime()+
"&Venue="+newResult.getVenue()+
"&Court="+newResult.getCourt()+
"&Texts="+newResult.getText();
try
{
String encodedUrl = URLEncoder.encode(url, "UTF-8");
JSONParser jParser = new JSONParser();
JSONObject json = jParser.makeHttpRequest(encodedUrl, "GET", isSuccessfull);
try
{
boolean success = (json.getBoolean("isValid"));
DisplayToast(success);
}
catch (JSONException d)
{
d.printStackTrace();
}
}
catch (UnsupportedEncodingException e)
{
e.printStackTrace();
}和logcat错误：
05-29 06:55:49.230: E/AndroidRuntime(25416): java.lang.IllegalStateException: Target host must not be null, or set in parameters. scheme=null, host=null, path=http://www.<myDomain>.co.za/insertTeamResultwithCode.php?Code=masjiensquash2015&Section=A&Gender=Men&WinningTeam=KZN&LosingTeam=WP&FixtureD=2015-05-29&FixtureT=09:00:00&Venue=Potch+CC&Court=1&Texts=mufasa+(KZN)+beat+scar+(WP)+3-0
05-29 06:55:49.230: E/AndroidRuntime(25416): (11-8,+11-6,+11-4)
05-29 06:55:49.230: E/AndroidRuntime(25416): optimus+(KZN)+beat+megatron+(WP)+3-0
05-29 06:55:49.230: E/AndroidRuntime(25416): (11-6,+11-3,+11-8)
05-29 06:55:49.230: E/AndroidRuntime(25416): Chuck+(KZN)+beat+Larry+(WP)+3-0
05-29 06:55:49.230: E/AndroidRuntime(25416): (11-5,+11-4,+11-4)
05-29 06:55:49.230: E/AndroidRuntime(25416): Tiger+(KZN)+beat+Rory+(WP)+3-0
05-29 06:55:49.230: E/AndroidRuntime(25416): (11-6,+11-3,+11-6)
05-29 06:55:49.230: E/AndroidRuntime(25416): Zandre+(KZN)+beat+Anzelle+(WP)+3-0
05-29 06:55:49.230: E/AndroidRuntime(25416): (11-5,+11-6,+11-2)回答 1
Stack Overflow用户
发布于 2015-05-29 13:38:56
您不应该对完整的URL进行编码，因为它还将对主机部分进行编码，如下所示：
http%3A%2F%2Fwww.%3CmyDomain%3E.co.za%2FinsertTeamResultwithCode.php这将失败，因为它不能解析这个url。
您应该只对传递到此URL的参数进行编码。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/30521648
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