blocks|key|1608533|text|shell扩展了通配符，因此不能将其与os.path.isfile()一起使用|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|1608534|如果要使用通配符，可以使用popen+with+shell+=+True或os.system()|CODE|1608535|>>>+import+os
>>>+os.system('ls')
aliases.sh++++++++++
default_bashprofile+++++networkhelpers++++++++++projecthelper.old+++++++++++pythonhelpers+++++++++++virtualenvwrapper_bashrc
0
>>>+os.system('ls+*.old')
projecthelper.old
0|code-block|syntax|javascript|1608536|你也可以用glob模块得到同样的效果。|1608537|>>>+import+glob
>>>+glob.glob('*.old')
['projecthelper.old']
>>>+|1608538|entityMap^0|8|V|0|0|1C|D|N|11|B|0|0|0|J|0|0^^$0|@$1|2|3|4|5|6|7|T|8|@$9|U|A|V|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|H]|$9|11|A|12|B|H]]|D|@]|E|$]]|$1|I|3|J|5|K|7|13|8|@]|D|@]|E|$L|M]]|$1|N|3|O|5|6|7|14|8|@$9|15|A|16|B|C]]|D|@]|E|$]]|$1|P|3|Q|5|K|7|17|8|@]|D|@]|E|$L|M]]|$1|R|3|-4|5|6|7|18|8|@]|D|@]|E|$]]]|S|$]]

Wildcards are expanded by shell and hence you can not use it with os.path.isfile()

If you want to use wildcards, you could use <code>popen with shell = True</code> or <code>os.system()</code> 

<pre><code>&gt;&gt;&gt; import os
&gt;&gt;&gt; os.system('ls')
aliases.sh 
default_bashprofile networkhelpers projecthelper.old pythonhelpers virtualenvwrapper_bashrc
0
&gt;&gt;&gt; os.system('ls *.old')
projecthelper.old
0
</code></pre>

You could get the same effect with glob module too.

<pre><code>&gt;&gt;&gt; import glob
&gt;&gt;&gt; glob.glob('*.old')
['projecthelper.old']
&gt;&gt;&gt; 
</code></pre>

blocks|key|4086406|text|glob就是您所需要的。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4086407|>>>+import+glob
>>>+glob.glob('*.rar')+++#+all+rar+files+within+the+directory,+in+this+case+the+current+working+one|code-block|syntax|javascript|4086408|如果路径是现有的常规文件，则os.path.isfile()返回True。因此，它用于检查文件是否已经存在并且不支持通配符。glob就是这样。|style|CODE|4086409|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.python.org/library/glob.html^0|0|4|0|0|0|E|G|W|4|1Q|4|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|Z|8|@$A|10|B|11|K|L]|$A|12|B|13|K|L]|$A|14|B|15|K|L]]|9|@]|C|$]]|$1|M|3|-4|5|6|7|16|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]]]

<a href="http://docs.python.org/library/glob.html" rel="noreferrer">glob</a> is what you need.

<pre><code>&gt;&gt;&gt; import glob
&gt;&gt;&gt; glob.glob('*.rar') # all rar files within the directory, in this case the current working one
</code></pre>

<code>os.path.isfile()</code> returns <code>True</code> if a path is an existing regular file. So that is used for checking whether a file already exists and doesn't support wildcards. <code>glob</code> does.

blocks|key|4086411|text|import+os
[x+for+x+in+os.listdir("your_directory")+if+len(x)+>=+4+and++x[-4:]+==+".rar"]|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4086412|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import os
[x for x in os.listdir("your_directory") if len(x) &gt;= 4 and x[-4:] == ".rar"]
</code></pre>

blocks|key|4086444|text|如果不使用os.path.isfile()，您将不知道glob()返回的结果是文件还是子目录，因此尝试如下所示：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4086445|import+fnmatch
import+os

def+find_files(base,+pattern):
++++'''Return+list+of+files+matching+pattern+in+base+folder.'''
++++return+[n+for+n+in+fnmatch.filter(os.listdir(base),+pattern)+if
++++++++os.path.isfile(os.path.join(base,+n))]

rar_files+=+find_files('somedir',+'*.rar')|code-block|syntax|javascript|4086446|如果愿意，您还可以只过滤glob()返回的结果，这样做的好处是可以做一些与unicode相关的额外工作。如果重要的话，请检查glob.py中的源代码。|4086447|[n+for+n+in+glob(pattern)+if+os.path.isfile(n)]|4086448|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.python.org/library/os.path.html#os.path.isfile|1|http://docs.python.org/library/glob.html^0|5|G|R|6|5|G|0|R|6|1|0|0|C|6|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@$9|13|A|14|1|15]|$9|16|A|17|1|18]]|E|$]]|$1|F|3|G|5|H|7|19|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1A|8|@$9|1B|A|1C|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|1D|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|1E|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]|W|$5|R|S|T|E|$U|X]]]]

Without using <a href="http://docs.python.org/library/os.path.html#os.path.isfile" rel="noreferrer"><code>os.path.isfile()</code></a> you won't know whether the results returned by <a href="http://docs.python.org/library/glob.html" rel="noreferrer"><code>glob()</code></a> are files or subdirectories, so try something like this instead:

<pre><code>import fnmatch
import os

def find_files(base, pattern):
 '''Return list of files matching pattern in base folder.'''
 return [n for n in fnmatch.filter(os.listdir(base), pattern) if
 os.path.isfile(os.path.join(base, n))]

rar_files = find_files('somedir', '*.rar')
</code></pre>

You could also just filter the results returned by <code>glob()</code> if you like, and that has the advantage of doing a few extra things relating to unicode and the like. Check the source in glob.py if it matters.

<pre><code>[n for n in glob(pattern) if os.path.isfile(n)]
</code></pre>

blocks|key|5504395|text|在这里，iglob比glob更好，因为您实际上并不需要rar文件的完整列表，而只是想检查是否存在一个rar文件。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5504396|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

iglob is better than glob here since you do not actually want the full list of rar files, but just want to check that one rar exists

blocks|key|4086534|text|如果您只关心是否至少存在一个文件，而不想要文件列表：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4086535|import+glob
import+os

def+check_for_files(filepath):
++++for+filepath_object+in+glob.glob(filepath):
++++++++if+os.path.isfile(filepath_object):
++++++++++++return+True

++++return+False|code-block|syntax|javascript|4086536|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you just care about whether at least one file exists and you don't want a list of the files:

<pre><code>import glob
import os

def check_for_files(filepath):
 for filepath_object in glob.glob(filepath):
 if os.path.isfile(filepath_object):
 return True

 return False
</code></pre>

blocks|key|5504512|text|要基于扩展显示完整路径和过滤器，请执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5504513|import+os
onlyfiles+=+[f+for+f+in+os.listdir(file)+if+len(f)+>=+5+and++f[-5:]+==+".json"+and+isfile(join(file,+f))]|code-block|syntax|javascript|5504514|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

to display full path and filter based on extension,

<pre><code>import os
onlyfiles = [f for f in os.listdir(file) if len(f) &gt;= 5 and f[-5:] == ".json" and isfile(join(file, f))]
</code></pre>

blocks|key|5504560|text|只是使用子进程完成工作的另一种方法。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5504561|import+subprocess

try:
++++++++q+=+subprocess.check_output('ls')
++++++++if+".rar"+in+q:
+++++++++++++print+"Rar+exists"
except+subprocess.CalledProcessError+as+e:
++++++++print+e.output|code-block|syntax|javascript|5504562|参考：https://docs.python.org/2/library/subprocess.html#subprocess.check_output|offset|length|5504563|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/2/library/subprocess.html#subprocess.check_output^0|0|0|3|21|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

Just another method to get the job done using subprocess.

<pre><code>import subprocess

try:
 q = subprocess.check_output('ls')
 if ".rar" in q:
 print "Rar exists"
except subprocess.CalledProcessError as e:
 print e.output
</code></pre>

Reference : <a href="https://docs.python.org/2/library/subprocess.html#subprocess.check_output" rel="nofollow noreferrer">https://docs.python.org/2/library/subprocess.html#subprocess.check_output</a>

I'd like to check if there are any <code>.rar</code> files in a directory. It doesn’t need to be recursive.
Using wildcard with <code>os.path.isfile()</code> was my best guess, but it doesn't work. What can I do then?

Use wildcard with os.path.isfile()

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想检查一下目录中是否有.rar文件。它不需要是递归的。在os.path.isfile()中使用通配符是我最好的猜测，但它不起作用。那我能做什么呢？

问在os.path.isfile()中使用通配符
EN

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问在os.path.isfile()中使用通配符EN