blocks|key|4085466|text|你可以使用java的JSON库(GSON，Jettison等)。之后，将数据添加到Map对象(嵌套结构)中，并使用库中的实用程序方法将其转换为JSON。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4085467|使用Jettison查找示例|4085468|+++JSONObject+json+=+new+JSONObject();

+++JSONObject+jsonKey+=+new+JSONObject();
+++jsonKey.put("AppID",+19);
+++jsonKey.put("Username",+"usrname");
+++jsonKey.put("Password",+"passwd");


+++String[]+deviceList+=+{"value1",+"value2"};

+++json.put("key",+jsonKey);
+++json.put("deviceList",+deviceList);

+++String+finalJson+=+json.toString();|code-block|syntax|javascript|4085469|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can use a JSON library for java (GSON, Jettison etc). After that add you data in a Map object (nested structure) and use the utility methods in the library to convert it to JSON.

Find example using Jettison

<pre><code> JSONObject json = new JSONObject();

 JSONObject jsonKey = new JSONObject();
 jsonKey.put("AppID", 19);
 jsonKey.put("Username", "usrname");
 jsonKey.put("Password", "passwd");


 String[] deviceList = {"value1", "value2"};

 json.put("key", jsonKey);
 json.put("deviceList", deviceList);

 String finalJson = json.toString();
</code></pre>

blocks|key|304998|text|你可以试试google的gson+=)我认为这是相当简单快速的->+https://code.google.com/p/google-gson/|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|304999|entityMap|0|LINK|mutability|MUTABLE|url|https://code.google.com/p/google-gson/^0|Y|12|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

You Could try gson from google =) I think it is pretty easy and fast -> <a href="https://code.google.com/p/google-gson/" rel="nofollow">https://code.google.com/p/google-gson/</a>

blocks|key|2665889|text|您在评论中说，每个字段都有一个单独的字符串。我建议使用以下方式构建一个包含所有所需字段的class+(由于aps似乎是一个单独的实体，请为它创建一个单独的类)：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2665890|public+class+MyClass+{
++++private+String+key;
++++private+List<String>+deviceList;
++++private+Aps+aps;
}

public+class+Aps+{
++++private+String+alert;
++++private+String+sound;
++++private+long+badge;
++++private+List<String>+dictionaryArray;
++++private+boolean+production;
}|code-block|syntax|javascript|2665891|有几个库可以帮助您将Java对象转换为JSON，Jackson's+ObjectMapper+class就是其中之一。您可以下载from+their+website库，或者如果您在项目中使用Maven，您可以找到对mvnrepository.com的依赖。|2665892|使用ObjectMapper|2665893|ObjectMapper+objectMapper+=+new+ObjectMapper();
MyClass+myClass+=+new+MyClass();
//+..+populate+the+fields
String+jsonString+=+objectMapper.writeValueAsString(myClass);|2665894|您必须将其包含在try-catch块中。仅此而已：jsonString现在保存转换为JSON字符串的字段。|2665895|2665896|编辑：而不是杰克逊你可以使用Google+GSON，它的工作方式大致相同。|BOLD|2665897|entityMap|0|LINK|mutability|MUTABLE|url|http://jackson.codehaus.org/1.7.9/javadoc/org/codehaus/jackson/map/ObjectMapper.html|1|http://jackson.codehaus.org/|2|http://mvnrepository.com/|3|https://code.google.com/p/google-gson/^0|18|5|1H|3|0|0|2N|5|O|S|0|1S|I|1|2Z|H|2|0|2|C|0|0|8|9|P|A|0|0|0|3|E|B|3|0^^$0|@$1|2|3|4|5|6|7|1A|8|@$9|1B|A|1C|B|C]|$9|1D|A|1E|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|1F|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1G|8|@$9|1H|A|1I|B|C]]|D|@$9|1J|A|1K|1|1L]|$9|1M|A|1N|1|1O]|$9|1P|A|1Q|1|1R]]|E|$]]|$1|M|3|N|5|6|7|1S|8|@$9|1T|A|1U|B|C]]|D|@]|E|$]]|$1|O|3|P|5|H|7|1V|8|@]|D|@]|E|$I|J]]|$1|Q|3|R|5|6|7|1W|8|@$9|1X|A|1Y|B|C]|$9|1Z|A|20|B|C]]|D|@]|E|$]]|$1|S|3|-4|5|6|7|21|8|@]|D|@]|E|$]]|$1|T|3|U|5|6|7|22|8|@$9|23|A|24|B|V]]|D|@$9|25|A|26|1|27]]|E|$]]|$1|W|3|-4|5|6|7|28|8|@]|D|@]|E|$]]]|X|$Y|$5|Z|10|11|E|$12|13]]|14|$5|Z|10|11|E|$12|15]]|16|$5|Z|10|11|E|$12|17]]|18|$5|Z|10|11|E|$12|19]]]]

You said in a comment that you have a separate String for each of the fields. I would suggest building a <code>class</code> containing all your desired fields, in the following manner (as <code>aps</code> appears to be a separate entity, create a separate class for it):

<pre><code>public class MyClass {
 private String key;
 private List&lt;String&gt; deviceList;
 private Aps aps;
}

public class Aps {
 private String alert;
 private String sound;
 private long badge;
 private List&lt;String&gt; dictionaryArray;
 private boolean production;
}
</code></pre>

There are several libraries to help you convert your Java objects into JSONs, and one of them is <a href="http://jackson.codehaus.org/1.7.9/javadoc/org/codehaus/jackson/map/ObjectMapper.html" rel="nofollow">Jackson's ObjectMapper class</a>. You can download the library <a href="http://jackson.codehaus.org/" rel="nofollow">from their website</a> or if you are using <code>Maven</code> in your project you can find the dependency on <a href="http://mvnrepository.com" rel="nofollow">mvnrepository.com</a>.

Using the <code>ObjectMapper</code>:

<pre><code>ObjectMapper objectMapper = new ObjectMapper();
MyClass myClass = new MyClass();
// .. populate the fields
String jsonString = objectMapper.writeValueAsString(myClass);
</code></pre>

You will have to surround that in a <code>try-catch</code> block. And that's about it: <code>jsonString</code> now holds your fields converted to a JSON String.

<hr>

Edit: instead of Jackson you could use <a href="https://code.google.com/p/google-gson/" rel="nofollow">Google GSON</a>, that works in about the same manner.

blocks|key|745896|text|package+com.stackoverflow.q1688099;

import+java.util.List;
import+com.google.gson.Gson;

public+class+Test+{

++++public+static+void+main(String...+args)+throws+Exception+{
++++++++String+json+=+
++++++++++++"{"
++++++++++++++++%2B+"'title':+'Computing+and+Information+systems',"
++++++++++++++++%2B+"'id'+:+1,"
++++++++++++++++%2B+"'children'+:+'true',"
++++++++++++++++%2B+"'groups'+:+[{"
++++++++++++++++++++%2B+"'title'+:+'Level+one+CIS',"
++++++++++++++++++++%2B+"'id'+:+2,"
++++++++++++++++++++%2B+"'children'+:+'true',"
++++++++++++++++++++%2B+"'groups'+:+[{"
++++++++++++++++++++++++%2B+"'title'+:+'Intro+To+Computing+and+Internet',"
++++++++++++++++++++++++%2B+"'id'+:+3,"
++++++++++++++++++++++++%2B+"'children':+'false',"
++++++++++++++++++++++++%2B+"'groups':[]"
++++++++++++++++++++%2B+"}]"+
++++++++++++++++%2B+"}]"
++++++++++++%2B+"}";

++++++++//+Now+do+the+magic.
++++++++Data+data+=+new+Gson().fromJson(json,+Data.class);

++++++++//+Show+it.
++++++++System.out.println(data);
++++}

}

class+Data+{
++++private+String+title;
++++private+Long+id;
++++private+Boolean+children;
++++private+List<Data>+groups;

++++public+String+getTitle()+{+return+title;+}
++++public+Long+getId()+{+return+id;+}
++++public+Boolean+getChildren()+{+return+children;+}
++++public+List<Data>+getGroups()+{+return+groups;+}

++++public+void+setTitle(String+title)+{+this.title+=+title;+}
++++public+void+setId(Long+id)+{+this.id+=+id;+}
++++public+void+setChildren(Boolean+children)+{+this.children+=+children;+}
++++public+void+setGroups(List<Data>+groups)+{+this.groups+=+groups;+}

++++public+String+toString()+{
++++++++return+String.format("title:%25s,id:%25d,children:%25s,groups:%25s",+title,+id,+children,+groups);
++++}
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|745897|查看此link|unstyled|offset|length|745898|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/1688099/converting-json-to-java/1688182#1688182^0|0|3|4|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|R|8|@]|9|@$G|S|H|T|1|U]]|A|$]]|$1|I|3|-4|5|F|7|V|8|@]|9|@]|A|$]]]|J|$K|$5|L|M|N|A|$O|P]]]]

<pre><code>package com.stackoverflow.q1688099;

import java.util.List;
import com.google.gson.Gson;

public class Test {

 public static void main(String... args) throws Exception {
 String json = 
 "{"
 + "'title': 'Computing and Information systems',"
 + "'id' : 1,"
 + "'children' : 'true',"
 + "'groups' : [{"
 + "'title' : 'Level one CIS',"
 + "'id' : 2,"
 + "'children' : 'true',"
 + "'groups' : [{"
 + "'title' : 'Intro To Computing and Internet',"
 + "'id' : 3,"
 + "'children': 'false',"
 + "'groups':[]"
 + "}]" 
 + "}]"
 + "}";

 // Now do the magic.
 Data data = new Gson().fromJson(json, Data.class);

 // Show it.
 System.out.println(data);
 }

}

class Data {
 private String title;
 private Long id;
 private Boolean children;
 private List&lt;Data&gt; groups;

 public String getTitle() { return title; }
 public Long getId() { return id; }
 public Boolean getChildren() { return children; }
 public List&lt;Data&gt; getGroups() { return groups; }

 public void setTitle(String title) { this.title = title; }
 public void setId(Long id) { this.id = id; }
 public void setChildren(Boolean children) { this.children = children; }
 public void setGroups(List&lt;Data&gt; groups) { this.groups = groups; }

 public String toString() {
 return String.format("title:%s,id:%d,children:%s,groups:%s", title, id, children, groups);
 }
}
</code></pre>

check out this <a href="https://stackoverflow.com/questions/1688099/converting-json-to-java/1688182#1688182">link</a>

I'm new to JSON so please excuse my ignorance. I need to get a JSON Object like this:

<pre><code>jsonString =
{
 "Key": {"AppID":"19","Username":"sompoRoot","Password":"11223344"},
 "deviceList": ["43ab48a0eb9f950d9c2498f8c2cfa1e5b8a62687479cfad849bbc455b88e67b6",
 "43ab48a0eb9f950d9c2498f8c2cfa1e5b8a62687479cfad849bbc455b88e67b6"],
 "aps": {"alert":"merhaba dunya","sound":"default","badge":"10",
 "dictionaryArray":["a","b"],
 "production":"false"} 
}
</code></pre>

I will get AppID, UserName and Password from database. deviceList is something like that :43ab48a0eb9f950d9c2498f8c2cfa1e5b8a62687479cfad849bbc455b88e67b6, 43ab48a0eb9f950d9c2498f8c2cfa1e5b8a62687479cfad849bbc455b88e67b6... and I will get alert, sound, badge dictionaryArray and production from text input. I got and convert String these parameter. I search from internet but I think it is more complex, how can I get like that JSON, Thank you.

How to get a JSON object from String in Java?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我是JSON的新手，所以请原谅我的无知。我需要像这样获得一个JSON对象：jsonString ={    "Key": {"AppID":"19","Username":"sompoRoot","Password":"11223344"},    "deviceList": ["43ab48a0eb9f950d9c2...

问在Java中如何从字符串中获取JSON对象？
EN

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问在Java中如何从字符串中获取JSON对象？EN