在包含字符串的ArrayList中查找索引
在包含字符串的ArrayList中查找索引
提问于 2013-02-20 14:26:50
通过使用Jsoup，我解析来自网站的超文本标记语言，用我需要从网站获取的内容填充ArrayList。所以现在我有了一个用字符串填充的ArrayList。我想在该列表中查找包含特定字符串的索引。例如，我知道在列表中的某个地方，在某些索引中，有字符串(字面) "Claude“，但我似乎无法编写任何代码来查找ArrayList中contains "Claude”的索引……下面是我尝试过但返回-1 (未找到)的结果：
ArrayList < String > list = new ArrayList < String > ();
String claude = "Claude";
Document doc = null;
try {
doc = Jsoup.connect("http://espn.go.com/nhl/team/stats/_/name/phi/philadelphia-flyers").get();
} catch (IOException e) {
e.printStackTrace();
}
for (Element table: doc.select("table.tablehead")) {
for (Element row: table.select("tr")) {
Elements tds = row.select("td");
if (tds.size() > 6) {
String a = tds.get(0).text() + tds.get(1).text() + tds.get(2).text() + tds.get(3).text() + tds.get(4).text() + tds.get(5).text() + tds.get(6).text();
list.add(a);
int claudesPos = list.indexOf(claude);
System.out.println(claudesPos);
}
}
}回答 2
Stack Overflow用户
回答已采纳
发布于 2013-02-21 01:15:47
你混淆了String.indexOf和List.indexOf。考虑以下列表：
list[0] = "Alpha Bravo Charlie"
list[1] = "Delta Echo Foxtrot"
list[2] = "Golf Hotel India"
list.indexOf("Foxtrot") => -1
list.indexOf("Golf Hotel India") => 2
list.get(1).indexOf("Foxtrot") => 11所以：
if (tds.size() > 6) {
// now the string a contains the text of all of the table cells joined together
String a = tds.get(0).text() + tds.get(1).text() + tds.get(2).text() +
tds.get(3).text() + tds.get(4).text() + tds.get(5).text() + tds.get(6).text();
// now the list contains the string
list.add(a);
// now you're looking in the list (which has all the table cells' items)
// for just the string "Claude", which doesn't exist
int claudesPos = list.indexOf(claude);
System.out.println(claudesPos);
// but this might give you the position of "Claude" within the string you built
System.out.println(a.indexOf(claude));
}
for (int i = 0; i < list.size(); i += 1) {
if (list.get(i).indexOf(claude) != -1) {
// list.get(i).contains(claude) works too
// and this will give you the index of the string containing Claude
// (but not the position within that string)
System.out.println(i);
}
}Stack Overflow用户
发布于 2013-02-20 16:59:41
First check whether it is an instance of String then get index
if (x instanceof String) {
...
}
for (int i = 0; i < list.size(); i++) {
if (list.get(i).getX() == someValue) { // Or use equals() if it actually returns an Object.
// Found at index i. Break or return if necessary.
}
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/14973566
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