blocks|key|933958|text|要获取第一个字符(不一定是字母)，请在字符串中使用索引：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|933959|char+c+=+employee.FirstName[0];|code-block|syntax|javascript|933960|您可能还希望首先检查字符串是否是非空和非空的，并去掉前导空格，并且第一个字符实际上是一个字母：|933961|if+(employee+!=+null+&&+employee.FirstName+!=+null)+{
++++string+name+=+employee.FirstName.TrimStart();
++++if+(name.Length+>+0)+{
++++++++char+firstChar+=+name[0];
++++++++if+(char.IsLetter(firstChar))+{
++++++++++++employee.Login+=+firstChar.ToString();
++++++++}
++++}
}|933962|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

To get the first character (not necessarily a letter) use an index into the string:

<pre><code>char c = employee.FirstName[0];
</code></pre>

You may also want to first check that the string is non-null and non-empty and strip leading whitespace, and that the first character is actually a letter:

<pre><code>if (employee != null &amp;&amp; employee.FirstName != null) {
 string name = employee.FirstName.TrimStart();
 if (name.Length &gt; 0) {
 char firstChar = name[0];
 if (char.IsLetter(firstChar)) {
 employee.Login = firstChar.ToString();
 }
 }
}
</code></pre>

blocks|key|3403705|text|就像这样简单：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3403706|if+(!string.IsNullOrEmpty(Employee.FirstName))
{
++++string+firstLetter+=+Employee.FirstName.SubString(0,+1);
}|code-block|syntax|javascript|3403707|这样，您就可以获得字符串形式的第一个字母和字符：|3403708|if+(!string.IsNullOrEmpty(Employee.FirstName))
{
++++char+firstLetter+=+Employee.FirstName[0];
}|3403709|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Just as simple as:

<pre><code>if (!string.IsNullOrEmpty(Employee.FirstName))
{
 string firstLetter = Employee.FirstName.SubString(0, 1);
}
</code></pre>

With that you get the first letter as a string and with this the character:

<pre><code>if (!string.IsNullOrEmpty(Employee.FirstName))
{
 char firstLetter = Employee.FirstName[0];
}
</code></pre>

blocks|key|3403754|text|char+firstCharOfFirstName+=+someEmployee.FirstName[0];|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3403755|如果FirstName字段可以包含前导空格，则可以执行以下操作：|unstyled|3403756|char+firstCharOfFirstName+=+someEmployee.FirstName.Trim()[0];|3403757|(正如其他答案提到的那样，最好检查空字符串和null字符串)|offset|length|style|CODE|3403758|entityMap^0|0|0|0|M|4|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|R|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$B|C]]|$1|I|3|J|5|F|7|T|8|@$K|U|L|V|M|N]]|9|@]|A|$]]|$1|O|3|-4|5|F|7|W|8|@]|9|@]|A|$]]]|P|$]]

<pre><code>char firstCharOfFirstName = someEmployee.FirstName[0];
</code></pre>

If the FirstName field can have leading whitespace you can do:

<pre><code>char firstCharOfFirstName = someEmployee.FirstName.Trim()[0];
</code></pre>

(As the other answers mention it's good to check for empty string and <code>null</code> string)

blocks|key|5017367|text|如果名字可能为空，则在获取第一个字母时必须进行检查：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5017368|FirstName.Substring(0,+Math.Min(FirstName.Length,+1))|code-block|syntax|javascript|5017369|如果FirstName字符串为空，这将为您提供一个空字符串，否则将第一个字符作为字符串，以便您可以将其与姓氏连接起来。|offset|length|style|CODE|5017370|entityMap^0|0|0|2|9|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

If the first name might be empty, you would have to check that when getting the first letter:

<pre><code>FirstName.Substring(0, Math.Min(FirstName.Length, 1))
</code></pre>

This will give you an empty string if the <code>FirstName</code> string is empty, otherwise the first character as a string, so that you can concatenate it with the last name.

blocks|key|5302121|text|请记住，如果满足以下条件，SubString()或FirstName将抛出ArgumentOutOfRangeException或IndexOutOfRangeException|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5302122|FirstName+==+string.Empty|code-block|syntax|javascript|5302123|所以，这段代码至少可以避免异常：|5302124|if(str2+!=+null)
{
++++char+result+=+(str2.Length+>+0)
++++++++?+str2[0]
++++++++:+(char)0;
}|5302125|不要忘记，如果字符串为空，此代码将返回错误结果！|5302126|entityMap^0|11|R|1T|O|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|10|8|@]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|R|$]]

Bear in mind, SubString() or FirstName[0] will throw a <code>ArgumentOutOfRangeException</code> or <code>IndexOutOfRangeException</code> if 

<pre><code>FirstName == string.Empty
</code></pre>

So, this code will at least avoid exception:

<pre><code>if(str2 != null)
{
 char result = (str2.Length &gt; 0)
 ? str2[0]
 : (char)0;
}
</code></pre>

Don't forget this code will return a false result if the string is empty!

I'm working with an entity (Employee) that has 3 fields: FirstName, LastName, &amp; Login

I want to grab the lastname and the first letter of the firstname field and write this to the login field. How do I grab the first letter of the firstname?

Thanks for any help.

How do you grab the first letter in a string?

我正在使用一个实体(Employee)，它有3个字段: FirstName、LastName和Login我想获取firstname字段的姓氏和第一个字母，并将其写入登录字段。如何抓取名字的第一个字母？谢谢你的帮助。

问如何抓取字符串中的第一个字母？
EN

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问如何抓取字符串中的第一个字母？EN