blocks|key|2222597|text|您可以简单地使用Integer.toBinaryString(int)。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2222598|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/6/docs/api/java/lang/Integer.html#toBinaryString%2528int%2529^0|8|R|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

You can simply use <a href="http://docs.oracle.com/javase/6/docs/api/java/lang/Integer.html#toBinaryString%28int%29" rel="nofollow">Integer.toBinaryString(int)</a>.

blocks|key|2222617|text|我认为错误在这一行上：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2222618|System.out.println(value+%2B+""+%2B+intArray);|code-block|syntax|javascript|2222619|您不能像这样打印整数数组:您应该将其转换为字符串，或者编写一个逐位打印数组的循环：|2222620|for+(int+i+:+inrArray)+{
++++System.out.print(intArray[i]);
}
System.out.println();|2222621|您也不需要传入输出数组:您可以在函数内部创建它。|2222622|public+static+int[]+decimalToBinary(int+value)+{
++++int+count+=+1;
++++int+tmp+=+value;
++++while+(tmp+!=+0)+{
++++++++tmp+/=+2;
++++++++count%2B%2B;
++++}
++++int[]+intArray+=+new+int[count];
++++//+Do+the+conversion+here...
++++return+intArray;
}|2222623|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

I think the error is on this line:

<pre><code>System.out.println(value + "" + intArray);
</code></pre>

You cannot print an array of integers like this: you should either convert it to string, or write a loop that prints the array digit by digit:

<pre><code>for (int i : inrArray) {
 System.out.print(intArray[i]);
}
System.out.println();
</code></pre>

You do not need to pass in the output array as well: you can create it inside the function.

<pre><code>public static int[] decimalToBinary(int value) {
 int count = 1;
 int tmp = value;
 while (tmp != 0) {
 tmp /= 2;
 count++;
 }
 int[] intArray = new int[count];
 // Do the conversion here...
 return intArray;
}
</code></pre>

blocks|key|1949024|text|System.out.println(value+%2B+"“%2B+intArray)；'intArray‘是一个数组的地址，所以，如果你想得到实际的二进制文件，你可以使用Arrays.toString(intArray)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1949025|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

System.out.println(value + "" + intArray); 
the 'intArray' is a arrays's address, so, if you want to get actual binary you can use Arrays.toString(intArray)

blocks|key|1207675|text|实际上，这是使用BigInteger在java中获取二进制数的一种非常简单的方法。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1207676|public+String+dectoBin(int+num){
++++String+s+=+""%2Bnum;
++++BigInteger+bi+=+new+BigInteger(s);
++++String+bin+=+bi.toString(2);
++++return+bin
}|code-block|syntax|javascript|1207677|BigInteger.toString(2)返回存储在圆括号内指定的数字基数上的数字。是绕过这个问题的一个非常简单的方法。|offset|length|style|CODE|1207678|entityMap^0|0|0|0|M|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Actually the is a very simple way to get binary numbers in java using BigInteger

<pre><code>public String dectoBin(int num){
 String s = ""+num;
 BigInteger bi = new BigInteger(s);
 String bin = bi.toString(2);
 return bin
}
</code></pre>

<code>BigInteger.toString(2)</code> returns the number stored on the numerical base specified inside the parenthesis. Is a very easy way to get arround this problems.

blocks|key|309829|text|作为dasblinkenlight，您需要逐项打印数组。如果你想要一个更好的选择，你可以使用mod+2的递归打印(模2给你1或0)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|309830|/**+print+directly*/
public+static+void+decimalToBinary(int+value)+{

++++if(value+>+1){
+++++++++System.out.print(decimalToBinary(value/2)+%2B+""+%2B+(value%252));+
++++++++/**recursion+with+implicit+cast+to+string*/
++++}+else+{
++++++++System.out.print(+(value==0)?"":"1");
+++}
}|code-block|syntax|javascript|309831|它可以与任何Base一起使用|309832|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

As dasblinkenlight you need to print the array item by item. If you want a nice alternative, you can use a recursive printing of value mod 2 (modulo 2 gives you 1 or 0)

<pre><code>/** print directly*/
public static void decimalToBinary(int value) {

 if(value &gt; 1){
 System.out.print(decimalToBinary(value/2) + "" + (value%2)); 
 /**recursion with implicit cast to string*/
 } else {
 System.out.print( (value==0)?"":"1");
 }
}
</code></pre>

It works with any Base

blocks|key|309866|text|实际上要打印数组，因为数组中的所有插槽都初始化为0，所以您需要检测第一个插槽从哪里开始，所以。你需要更换|type|unstyled|depth|inlineStyleRanges|entityRanges|data|309867|System.out.println(value+%2B+""+%2B+intArray);|code-block|syntax|javascript|309868|就像这样；|309869|System.out.println(vale+%2B+"+");
boolean+sw+=+false;
for(int+i=0;i<intArray.length;i%2B%2B){
++++if(!sw)
++++++++sw+=+(intArray[i]==1);//This+will+detect+when+the+first+1+appears
++++if(sw)
++++++++System.out.println(intArray[1]);+//This+will+print+when+the+sw+changes+to+true+everything+that+comes+after
}|309870|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Well actually to print the array, because all the slots in the array are initialized at 0 you need to detect where the first one begins, so.
you need to replace

<pre><code>System.out.println(value + "" + intArray);
</code></pre>

with something like this;

<pre><code>System.out.println(vale + " ");
boolean sw = false;
for(int i=0;i&lt;intArray.length;i++){
 if(!sw)
 sw = (intArray[i]==1);//This will detect when the first 1 appears
 if(sw)
 System.out.println(intArray[1]); //This will print when the sw changes to true everything that comes after
}
</code></pre>

blocks|key|1208501|text|这是一个转换十进制数的程序。转换成二进制文件。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1208502|import+java.util.Scanner;

public+class+decimalToBinary+{

++++static+int+howManyTerms+(int+n)+{
++++++++int+term+=+0;

++++++++while+(n+!=+0)+{
++++++++++++term+%2B%2B;
++++++++++++n+/=+2;
++++++++}

++++++++return+term;
++++}

++++static+String+revArrayofBin2Str+(int[]+Array)+{
++++++++String+ret+=+"";
++++++++for+(int+i+=+Array.length-1;+i+>=+0;+i--)
++++++++++++ret+%2B=+Integer.toString(Array[i]);

++++++++return+ret;
++++}

++++public+static+void+main+(String[]+args)+{

++++++++Scanner+sc=new+Scanner+(System.in);

++++++++System.out.print+("Enter+any+no.:+");
++++++++int+num+=+sc.nextInt();
++++++++int[]+bin+=+new+int[howManyTerms+(num)];

++++++++int+dup+=+num,+el+=+-1;

++++++++while+(dup+!=+0)+{
++++++++++++int+rem+=+dup+%25+2;
++++++++++++bin+[%2B%2Bel]+=+rem;
++++++++++++dup+/=+2;
++++++++}

++++++++String+d2b+=+revArrayofBin2Str(bin);

++++++++System.out.println("Binary+of+"+%2B+num+%2B+"+is:+"+%2B+d2b);
++++}
}|code-block|syntax|javascript|1208503|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here is a program to convert Decimal nos. into Binary.

<pre><code>import java.util.Scanner;

public class decimalToBinary {

 static int howManyTerms (int n) {
 int term = 0;

 while (n != 0) {
 term ++;
 n /= 2;
 }

 return term;
 }

 static String revArrayofBin2Str (int[] Array) {
 String ret = "";
 for (int i = Array.length-1; i &gt;= 0; i--)
 ret += Integer.toString(Array[i]);

 return ret;
 }

 public static void main (String[] args) {

 Scanner sc=new Scanner (System.in);

 System.out.print ("Enter any no.: ");
 int num = sc.nextInt();
 int[] bin = new int[howManyTerms (num)];

 int dup = num, el = -1;

 while (dup != 0) {
 int rem = dup % 2;
 bin [++el] = rem;
 dup /= 2;
 }

 String d2b = revArrayofBin2Str(bin);

 System.out.println("Binary of " + num + " is: " + d2b);
 }
}
</code></pre>

blocks|key|1207723|text|这是一个简单的java代码，只使用原始类型int将decimal转换为binary，希望它能对初学者有所帮助。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1207724|import+java.io.BufferedReader;
import+java.io.InputStreamReader;

public+class+DtoB+{
++++public+static+void+main(String[]+args)+{

++++++++try+{+//+for+Exception+handling+of+taking+input+from+user.

++++++++++++System.out.println("Please+enter+a+number");

++++++++++++BufferedReader+br+=+new+BufferedReader(new+InputStreamReader(System.in));
++++++++++++String+input+=+br.readLine();+++++++
++++++++++++int+x+=+Integer.parseInt(input);

++++++++++++int+bin+=+0;
++++++++++++int+p+=+1;
++++++++++++while+(x+>+0)+{
++++++++++++++++int+r+=+x+%25+2;
++++++++++++++++bin+=+(r+*+p)+%2B+bin;
++++++++++++++++x+=+x+/+2;
++++++++++++++++p+*=+10;
++++++++++++}
++++++++++++System.out.println("Binary+of+"+%2B+input+%2B+"+is+=+"+%2B+bin);
++++++++}+catch+(Exception+e)+{
++++++++++++System.out.println("Please+enter+a+valid+decimal+number.");
++++++++++++System.exit(1);
++++++++++++e.printStackTrace();
++++++++}
++++}
}|code-block|syntax|javascript|1207725|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This is simple java code for decimal to binary using only primitive type int, hopefully it should help beginners.

<pre><code>import java.io.BufferedReader;
import java.io.InputStreamReader;

public class DtoB {
 public static void main(String[] args) {

 try { // for Exception handling of taking input from user.

 System.out.println("Please enter a number");

 BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
 String input = br.readLine(); 
 int x = Integer.parseInt(input);

 int bin = 0;
 int p = 1;
 while (x &gt; 0) {
 int r = x % 2;
 bin = (r * p) + bin;
 x = x / 2;
 p *= 10;
 }
 System.out.println("Binary of " + input + " is = " + bin);
 } catch (Exception e) {
 System.out.println("Please enter a valid decimal number.");
 System.exit(1);
 e.printStackTrace();
 }
 }
}
</code></pre>

I'm having trouble in getting the binary. I do not know what's wrong. The binary number always ends up in gibberish. Also some parts like the <code>new int[31]</code> thing was from HW but I can't get around to make print the actual binary.

<pre><code>public class DectoBinary {
 public static void main(String[]args) {
 Scanner CONSOLE = new Scanner(System.in);
 System.out.print("Please enter a nonnegative integer: ");
 int value = CONSOLE.nextInt();
 while (value &lt; 0) {
 System.out.print("number outside range.");
 System.out.print
 ("Please enter a nonnegative interger more than 0: ");
 value = CONSOLE.nextInt();
 }
 int[] intArray = new int[31];
 decimalToBinary(value, intArray);
 System.out.println(value + "" + intArray);
 }
 public static int[] decimalToBinary(int value, int[]intArray) {
 int i = 0;
 while (value != 0) {
 if (value % 2 == 1)
 intArray[i] = 1;

 else
 intArray[i] = 0;

 value /= 2;
 i++;
 }
 return intArray;
 }
}
</code></pre>

decimal to binary in java

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我在获取二进制文件时遇到了麻烦。我不知道出了什么问题。二进制数总是以胡言乱语结束。还有一些部分，比如new int[31]的东西是来自HW的，但我无法打印出真正的二进制文件。public class DectoBinary {    public static void main(String[]args) {    ...

问在java中将十进制转换为二进制
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问在java中将十进制转换为二进制EN