blocks|key|748220|text|subprocess.Popen()不会为您组合路径组件。在我看来，您只提供了一个目录。您需要将目标可执行文件的名称添加到提供给Popen的路径中。尝试以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|748221|p+=+subprocess.Popen([os.path.join(SCRIPT_DIR,SCRIPT_NAME),sample_file_directory,'min','edgelen'],stdout=subprocess.PIPE,stderr=subprocess.PIPE)|code-block|syntax|javascript|748222|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

subprocess.Popen() won't combine path components for you. From what I see, you're only providing a directory. You'll need to add the target executable's name to the path being given to Popen. Try the following:

<pre><code>p = subprocess.Popen([os.path.join(SCRIPT_DIR,SCRIPT_NAME),sample_file_directory,'min','edgelen'],stdout=subprocess.PIPE,stderr=subprocess.PIPE)
</code></pre>

blocks|key|748272|text|在运行脚本的位置，SCRIPT_DIR变量是绝对路径还是相对路径有效？如果是后者，它可能无法工作，因为子进程可能在具有不同工作目录的不同环境中启动。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|748273|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Is your SCRIPT_DIR variable the absolute path or a relative path valid in the location you're running the script? If it's the latter, it may not work, as the subprocess may start in a different environment that has a different working directory.

blocks|key|2128154|text|问题出在这里：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2128155|p+=+subprocess.Popen([SCRIPT_DIR,sample_file_directory,'min','edgelen'],stdout=subprocess.PIPE,stderr=subprocess.PIPE)|code-block|syntax|javascript|2128156|请注意这一部分：|2128157|Popen([SCRIPT_DIR,sample_file_directory,'min','edgelen']|2128158|现在，看到了吧，你已经知道subprocess接受一个列表。但问题是，您正在将目录作为列表的一部分进行传递。该列表的格式如下：|offset|length|style|CODE|2128159|命令，arg1，arg2...|2128160|现在，当您运行该命令时，您将执行以下操作：|2128161|[SCRIPT_DIR+->命令|2128162|sample_file_directory+->+arg1|2128163|‘'min’->+arg2|2128164|‘'edgelen’->+arg3]|2128165|看到问题了吗？您将脚本的目录作为要运行的命令传递，并将脚本的名称作为参数传递。导入os模块并执行以下操作：|2128166|p+=+subprocess.Popen([os.path.join(SCRIPT_DIR,sample_file_directory),'min','edgelen'],stdout=subprocess.PIPE,stderr=subprocess.PIPE)|2128167|这样做是这样的：|2128168|[SCRIPT_DIR和sample_file_directory合并在一起->命令|2128169|‘'min’->+arg1|2128170|‘'edgelen’->+arg2]|2128171|os.path.join会自动添加路径分隔符。|2128172|entityMap^0|0|0|0|0|D|A|0|0|0|0|0|0|0|15|2|0|0|0|0|0|0|0|C|0^^$0|@$1|2|3|4|5|6|7|1I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|1J|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|1K|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|1L|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|1M|8|@$M|1N|N|1O|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1P|8|@]|9|@]|A|$]]|$1|S|3|T|5|6|7|1Q|8|@]|9|@]|A|$]]|$1|U|3|V|5|6|7|1R|8|@]|9|@]|A|$]]|$1|W|3|X|5|6|7|1S|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|6|7|1T|8|@]|9|@]|A|$]]|$1|10|3|11|5|6|7|1U|8|@]|9|@]|A|$]]|$1|12|3|13|5|6|7|1V|8|@$M|1W|N|1X|O|P]]|9|@]|A|$]]|$1|14|3|15|5|D|7|1Y|8|@]|9|@]|A|$E|F]]|$1|16|3|17|5|6|7|1Z|8|@]|9|@]|A|$]]|$1|18|3|19|5|6|7|20|8|@]|9|@]|A|$]]|$1|1A|3|1B|5|6|7|21|8|@]|9|@]|A|$]]|$1|1C|3|1D|5|6|7|22|8|@]|9|@]|A|$]]|$1|1E|3|1F|5|6|7|23|8|@$M|24|N|25|O|P]]|9|@]|A|$]]|$1|1G|3|-4|5|6|7|26|8|@]|9|@]|A|$]]]|1H|$]]

The problem lies here:

<pre><code>p = subprocess.Popen([SCRIPT_DIR,sample_file_directory,'min','edgelen'],stdout=subprocess.PIPE,stderr=subprocess.PIPE)
</code></pre>

Notice this part:

<pre><code>Popen([SCRIPT_DIR,sample_file_directory,'min','edgelen']
</code></pre>

Now, see, you already know that <code>subprocess</code> takes a list. But the problem is that you are passing the directory as part of the list. The list is formatted like this:

[command, arg1, arg2...]

Now, when you run that command, you are doing this:

[SCRIPT_DIR -> command 
sample_file_directory -> arg1 
'min' -> arg2 
'edgelen' -> arg3]

See the problem? You are passing the script's directory as the command to run and the script's name as an argument. Import the <code>os</code> module and do this:

<pre><code>p = subprocess.Popen([os.path.join(SCRIPT_DIR,sample_file_directory),'min','edgelen'],stdout=subprocess.PIPE,stderr=subprocess.PIPE)
</code></pre>

This does this:

[SCRIPT_DIR and sample_file_directory joined together -> command 
'min' -> arg1 
'edgelen' -> arg2] 

<code>os.path.join</code> automatically adds the path separator.

blocks|key|4254350|text|“另一个可能的问题是，你试图在没有安装32位库的64位系统上运行32位二进制文件。实际上，我今天早些时候遇到了这个问题。这里记录了一个修复程序。我对你的系统一无所知，所以这可能是完全无关紧要的建议，但我想提一下也没什么坏处。”丹·艾伯特。他想出了解决方案的答案！非常感谢，丹！|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4254351|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

"One other thing it could potentially be is that you're trying to run a 32-bit binary on a 64-bit system without the 32-bit libraries installed. I actually ran into this issue earlier today. A fix is documented here. I don't know anything about your system, so this may be completely irrelevant advice, but I figured it wouldn't hurt to mention it." Dan Albert. He came up with the answer to the solution! Thanks so much Dan!

<pre><code>import subprocess

sample_file_directory = "..." # directory where file is
SCRIPT_DIR = "..." # directory where script is

p = subprocess.Popen([SCRIPT_DIR,sample_file_directory,'min','edgelen'],stdout=subprocess.PIPE,stderr=subprocess.PIPE) 
min_side_len, err = p.communicate()
print len(err)
</code></pre>

So i have this script that analyzes .ply files (3d file format) and gives me data about the file. I am trying to find out in my directory which files are corrupted and which aren't. So I am trying to use the subprocess library to run the script to find an arbitrary feature of the .ply files (in this case the minimum edge length) If err has anything in it, it means it couldn't retrieve the arbitrary feature and the file is corrupted. Here, I am only running it on one file. However, I keep getting an error.

<pre><code>p = subprocess.Popen([SCRIPT_DIR,sample_file_directory,'min','edgelen'],stdout=subprocess.PIPE,stderr=subprocess.PIPE)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/subprocess.py", line 679, in __init__
errread, errwrite)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/subprocess.py", line 1249, in _execute_child
raise child_exception
OSError: [Errno 2] No such file or directory
</code></pre>

Can anyone help me figure out why I am getting this error? Both my data directory and script directory are valid. Also, sorry if I left anything out that's important. First time posting.

subprocessing library in Python

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

import subprocesssample_file_directory = "..." # directory where file isSCRIPT_DIR = "..." # directory where script isp = subprocess.Popen([SCRIPT_DIR,sample_fi...

问Python中的子处理库
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问Python中的子处理库EN