blocks|key|2525296|text|如果您只想从数据范围中查找排除周末，您可以尝试下面的代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2525297|DECLARE+@D1+DATETIME+=+'20190601'
DECLARE+@D2+DATETIME+=+'20190611'
DECLARE+@LoopCount+INT+=+(SELECT+DATEDIFF(DD,@D1,@D2))

DECLARE+@TempTable+TABLE
(
++++date+date
)

WHILE+@LoopCount+>=+0
BEGIN
+++--+Checking+not+in+(1,7)+will+exclude+Suturday+and+Sunday+from+the+counting
+++IF+DATEPART(dw,(DATEADD(DD,-@LoopCount,GETDATE())))+NOT+IN+(1,7)
+++BEGIN+
++++++++INSERT+INTO+@TempTable+(date)
++++++++VALUES+(DATEADD(DD,-@LoopCount,GETDATE()))
++++END
++++SET+@LoopCount+=+@LoopCount+-+1
END


SELECT+COUNT(*)+total_working_days
FROM+@TempTable|code-block|syntax|javascript|2525298|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you are only looking for exclude weekends from a data range, you can try this below code-

<pre><code>DECLARE @D1 DATETIME = '20190601'
DECLARE @D2 DATETIME = '20190611'
DECLARE @LoopCount INT = (SELECT DATEDIFF(DD,@D1,@D2))

DECLARE @TempTable TABLE
(
 date date
)

WHILE @LoopCount &gt;= 0
BEGIN
 -- Checking not in (1,7) will exclude Suturday and Sunday from the counting
 IF DATEPART(dw,(DATEADD(DD,-@LoopCount,GETDATE()))) NOT IN (1,7)
 BEGIN 
 INSERT INTO @TempTable (date)
 VALUES (DATEADD(DD,-@LoopCount,GETDATE()))
 END
 SET @LoopCount = @LoopCount - 1
END


SELECT COUNT(*) total_working_days
FROM @TempTable
</code></pre>

blocks|key|4939007|text|我在网上找到了一个函数，可以解决我的问题。它的作用与Excel中的NETWORKDAYS相同。在这里张贴它，也许它可以帮助其他有同样问题的人。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4939008|创建函数dbo.NetWorkDays(|4939009|@StartDate日期时间|4939010|，@EndDate+datetime|4939011|)返回int作为begin|4939012|声明|4939013|@result+int|4939014|，@StartDate2日期时间|4939015|，@EndDate2+datetime|4939016|，@DateSwap1+datetime|4939017|，@DateSwap2+datetime|4939018|，@ReturnNegative位|4939019|设置@DateSwap1+=+@StartDate|4939020|设置@Dateswap2+=+@EndDate|4939021|设置@ReturnNegative+=0|4939022|如果@EndDate+<+@StartDate|4939023|开始|4939024|设置@ReturnNegative+=1|4939025|设置@StartDate+=+@Dateswap2|4939026|设置@EndDate+=+@DateSwap1|4939027|结束|4939028|set+@StartDate2+=+dateadd(d,8-datepart(dw，@StartDate)，@StartDate)|4939029|set+@EndDate2+=+dateadd(d,1-datepart(dw，@EndDate)，@EndDate)|4939030|set+@result+=+datediff(d，@StartDate2，@EndDate2)+*5/7|4939031|4939032|datediff(d，@StartDate，@StartDate2)+-+1|unordered-list-item|4939033|datediff(d，@EndDate2，@EndDate)|4939034|case+when+datepart(dw，@StartDate)+=1+then+1+then+0+end|4939035|case+when+datepart(dw，@EndDate)+=7+then+1+then+0+end|4939036|<代码>F29|4939037|如果@ReturnNegative+=1|4939038|4939039|设置@result+=+@result+*+-1|4939040|4939041|return+@result|4939042|4939043|去|4939044|entityMap^0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|2A|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|2B|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|2C|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|2D|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|2E|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|2F|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|2G|8|@]|9|@]|A|$]]|$1|N|3|O|5|6|7|2H|8|@]|9|@]|A|$]]|$1|P|3|Q|5|6|7|2I|8|@]|9|@]|A|$]]|$1|R|3|S|5|6|7|2J|8|@]|9|@]|A|$]]|$1|T|3|U|5|6|7|2K|8|@]|9|@]|A|$]]|$1|V|3|W|5|6|7|2L|8|@]|9|@]|A|$]]|$1|X|3|Y|5|6|7|2M|8|@]|9|@]|A|$]]|$1|Z|3|10|5|6|7|2N|8|@]|9|@]|A|$]]|$1|11|3|12|5|6|7|2O|8|@]|9|@]|A|$]]|$1|13|3|14|5|6|7|2P|8|@]|9|@]|A|$]]|$1|15|3|16|5|6|7|2Q|8|@]|9|@]|A|$]]|$1|17|3|18|5|6|7|2R|8|@]|9|@]|A|$]]|$1|19|3|1A|5|6|7|2S|8|@]|9|@]|A|$]]|$1|1B|3|1C|5|6|7|2T|8|@]|9|@]|A|$]]|$1|1D|3|1E|5|6|7|2U|8|@]|9|@]|A|$]]|$1|1F|3|1G|5|6|7|2V|8|@]|9|@]|A|$]]|$1|1H|3|1I|5|6|7|2W|8|@]|9|@]|A|$]]|$1|1J|3|1K|5|6|7|2X|8|@]|9|@]|A|$]]|$1|1L|3|-4|5|6|7|2Y|8|@]|9|@]|A|$]]|$1|1M|3|1N|5|1O|7|2Z|8|@]|9|@]|A|$]]|$1|1P|3|1Q|5|1O|7|30|8|@]|9|@]|A|$]]|$1|1R|3|1S|5|1O|7|31|8|@]|9|@]|A|$]]|$1|1T|3|1U|5|1O|7|32|8|@]|9|@]|A|$]]|$1|1V|3|1W|5|6|7|33|8|@]|9|@]|A|$]]|$1|1X|3|1Y|5|6|7|34|8|@]|9|@]|A|$]]|$1|1Z|3|16|5|6|7|35|8|@]|9|@]|A|$]]|$1|20|3|21|5|6|7|36|8|@]|9|@]|A|$]]|$1|22|3|1E|5|6|7|37|8|@]|9|@]|A|$]]|$1|23|3|24|5|6|7|38|8|@]|9|@]|A|$]]|$1|25|3|1E|5|6|7|39|8|@]|9|@]|A|$]]|$1|26|3|27|5|6|7|3A|8|@]|9|@]|A|$]]|$1|28|3|-4|5|6|7|3B|8|@]|9|@]|A|$]]]|29|$]]

I found a function online that solves my problem. It acts the same as NETWORKDAYS in Excel. Posting it here, perhaps it can help others who are having the same question. 

CREATE function [dbo].[NetWorkDays](

@StartDate datetime

,@EndDate datetime

) returns int as begin

declare

@result int

,@StartDate2 datetime

,@EndDate2 datetime

,@DateSwap1 datetime

,@DateSwap2 datetime

,@ReturnNegative BIT

set @DateSwap1 = @StartDate

set @Dateswap2 = @EndDate

SET @ReturnNegative = 0

IF @EndDate &lt; @StartDate

BEGIN

SET @ReturnNegative = 1

SET @StartDate = @Dateswap2

SET @EndDate = @DateSwap1

END

set @StartDate2 = dateadd(d,8-datepart(dw, @StartDate), @StartDate)

set @EndDate2 = dateadd(d,1-datepart(dw ,@EndDate), @EndDate)

set @result = datediff(d, @StartDate2, @EndDate2) * 5 / 7

<ul>
<li>datediff(d, @StartDate, @StartDate2) - 1</li>
<li>datediff(d, @EndDate2, @EndDate)</li>
<li>case when datepart(dw,@StartDate) = 1 then 1 else 0 end</li>
<li>case when datepart(dw,@EndDate) = 7 then 1 else 0 end</li>
</ul>

if @ReturnNegative = 1

BEGIN

SET @result = @result * -1

END

return @result

end

GO

I need to calculate working days and exclude weekends for an updated column Invoice_Date_to_Scan_Start_Date_Cal. I used to following code to get the result :

<pre><code>UPDATE FBL1IN_working
SET FBL1IN_working.Invoice_Date_to_Scan_Start_Date_Cal 
 = (datediff (DD, Doc_Date, Scan_Start_Date_Calc) +1) 

-(datediff (wk, Doc_Date, Scan_Start_Date_Calc) *2)

-(case when datename(dw, Doc_Date ) = 'Sunday' then 1 else 0 end)

-(case when datename(dw, Scan_Start_Date_Calc) = 'Saturday' then 1 else 0 end) 
</code></pre>

However, I noticed, there is a difference of one or two days counts in some of the calculated field (<code>Invoice_Date_to_Scan_Start_Date_Cal</code>). For example: 

<code>Doc_Date = 2019-05-02</code> and
<code>Scan_Start_Date_Calc = 2018-11-19</code>
Hence, the <code>Invoice_Date_to_Scan_Start_Date_Cal</code> result should be <code>-119</code>. But with the above code, I am getting the result of <code>-117</code>. I do not know where the mistake is in that code. Could anyone please help me on this. 

Thank you.

Calculate Business Working Days exclude weekends

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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对于更新后的列Invoice_Date_to_Scan_Start_Date_Cal，我需要计算工作日并排除周末。我习惯于使用下面的代码来获得结果：UPDATE FBL1IN_workingSET FBL1IN_working.Invoice_Date_to_Scan_Start_Date_Cal  = (datedi...

问计算工作日(不包括周末)
EN

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问计算工作日(不包括周末)EN