因此,我试图将YYYY-MM-DD
字符串转换为英文格式,如:WEEKDAY DDth MONTH YEAR
,但是,我有问题将字符串转换为日期格式,我认为这是YYYY, MM, DD
格式。
这是我的代码:
from datetime import datetime, date
[...]
def getHumanDate(rawdate):
the_date = date(int(rawdate[0:4]), int(rawdate[6:7]), int(rawdate[9:10]))
weekday = (datetime.date(the_date).strftime('%A'))
month = (datetime.date(the_date).strftime('%B'))
year = int(rawdate[0:4])
day = int(rawdate[9:10])
english = weekday + " " + day + "th of " + month + " " + year
return english
我得到了一个TypeError: descriptor 'date' for 'datetime.datetime' objects doesn't apply to a 'datetime.date' object
错误,坦白地说,我无法控制我的头脑。
任何帮助都将不胜感激!干杯
编辑:这里的是一个使用日历库的工作示例,虽然完全不同,但它可以工作!
import calendar
[...]
def getHumanDate(rawdate):
int_year = int(rawdate[0:4])
int_month = int(rawdate[6:7])
int_day = int(rawdate[9:10])
week_days=["Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","Sunday"]
months=["", "January","February","March","April","May","June","July", "August","September","October","November","December"]
weekday = calendar.weekday(int_year, int_month, int_day)
english = week_days[weekday] + " " + str(int_day) + "th of " + months[int_month] + " " + str(int_year)
return English
发布于 2021-12-19 17:28:00
如果使用datetime中的strptime函数,则可以获得传递给函数的参数的隐式验证的额外优势。因此,我建议:
from datetime import datetime
dsuffix = [None, 'st', 'nd', 'rd', 'th', 'th', 'th', 'th', 'th', 'th', 'th', 'th', 'th', 'th', 'th', 'th', 'th', 'th', 'th', 'th', 'th', 'st', 'nd', 'rd', 'th', 'th', 'th', 'th', 'th', 'th', 'th', 'st']
def getHumanDate(date): # parameter is expect in ISO format YYYY-MM-DD
d = datetime.strptime(date, '%Y-%m-%d')
a = datetime.strftime(d, '%A')
b = datetime.strftime(d, '%B %Y')
return f'{a} {d.day}{dsuffix[d.day]} {b}'
for i in range(1, 32):
d = f'2021-12-{i}'
print(getHumanDate(d))
https://stackoverflow.com/questions/70413377
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