blocks|key|653662|text|我认为最直截了当的方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|653663|let+ar+=+[["finalOrderData",1],["finalFabricData",3],["finalDecorationData",3],["finalHtData",3]]

var+maxNumber+=+ar[0]

ar.forEach((element)+=>+maxNumber+=+element[1]+>+maxNumber[1]+?+element+:+maxNumber)|code-block|syntax|javascript|653664|或者用同样的文字写得更详细：|653665|let+ar+=+[["finalOrderData",1],["finalFabricData",3],["finalDecorationData",3],["finalHtData",3]]

var+maxNumber+=+ar[0]

for+(element+of+ar)+{

++let+number+=+element[1]

++if+(number+>+maxNumber[1])
++++maxNumber+=+number
++}|653666|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<p>I think the most straightforward way:</p>
<pre><code>let ar = [[&quot;finalOrderData&quot;,1],[&quot;finalFabricData&quot;,3],[&quot;finalDecorationData&quot;,3],[&quot;finalHtData&quot;,3]]

var maxNumber = ar[0]

ar.forEach((element) =&gt; maxNumber = element[1] &gt; maxNumber[1] ? element : maxNumber)
</code></pre>
<p>or the same written more verbosely:</p>
<pre><code>let ar = [[&quot;finalOrderData&quot;,1],[&quot;finalFabricData&quot;,3],[&quot;finalDecorationData&quot;,3],[&quot;finalHtData&quot;,3]]

var maxNumber = ar[0]

for (element of ar) {

  let number = element[1]

  if (number &gt; maxNumber[1])
    maxNumber = number
  }
</code></pre>


blocks|key|651129|text|您可以使用Array.reduce函数|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|651130|​|651131|let+ar+=+[["finalOrderData",1],["finalFabricData",3],["finalDecorationData",3],["finalHtData",3]]
let+result+=+ar.reduce((acc,cur)+=>+!acc+%7C%7C+cur[1]+>+acc[1]+?+cur+:+acc,+undefined);
console.log(result);|code-block|syntax|javascript|651132|651133|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/reduce^0|5|C|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|T|8|@]|9|@$A|U|B|V|1|W]]|C|$]]|$1|D|3|E|5|6|7|X|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|Y|8|@]|9|@]|C|$I|J]]|$1|K|3|E|5|6|7|Z|8|@]|9|@]|C|$]]|$1|L|3|-4|5|6|7|10|8|@]|9|@]|C|$]]]|M|$N|$5|O|P|Q|C|$R|S]]]]

<p>You can use the <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/reduce" rel="nofollow noreferrer">Array.reduce</a> function</p>
<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>let ar = [["finalOrderData",1],["finalFabricData",3],["finalDecorationData",3],["finalHtData",3]]
let result = ar.reduce((acc,cur) =&gt; !acc || cur[1] &gt; acc[1] ? cur : acc, undefined);
console.log(result);</code></pre>
</div>
</div>
</p>


blocks|key|770524|text|使用Array.sort()|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|770525|​|770526|let+ar+=+[['finalOrderData',+1],+['finalFabricData',+3],+['finalDecorationData',+3],+['finalHtData',+3]];

let+res+=+ar.sort((a,+b)+=>+b[1]+-+a[1])[0];

console.log(res);|code-block|syntax|javascript|770527|770528|请注意，这并不能处理单词的字母顺序。|770529|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort^0|2|C|2|C|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|X|8|@$9|Y|A|Z|B|C]]|D|@$9|10|A|11|1|12]]|E|$]]|$1|F|3|G|5|6|7|13|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|14|8|@]|D|@]|E|$K|L]]|$1|M|3|G|5|6|7|15|8|@]|D|@]|E|$]]|$1|N|3|O|5|6|7|16|8|@]|D|@]|E|$]]|$1|P|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|Q|$R|$5|S|T|U|E|$V|W]]]]

<p>Use <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort" rel="nofollow noreferrer"><code>Array.sort()</code></a>:</p>
<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>let ar = [['finalOrderData', 1], ['finalFabricData', 3], ['finalDecorationData', 3], ['finalHtData', 3]];

let res = ar.sort((a, b) =&gt; b[1] - a[1])[0];

console.log(res);</code></pre>
</div>
</div>
</p>
<p>Note that this doesn't handle the alphabetical order of the word.</p>


blocks|key|770539|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|770540|++++function+getMaxOf2DIndex(arr,+idx)+{
++++let+maxItem+=+arr[0];
++++
++++arr.forEach((item,+i)+=>+{
++++++++if(item[idx]+>=+maxItem[idx])
++++++++++++maxItem+=+item;+
++++});
++++
++++return+maxItem;
}|code-block|syntax|javascript|770541|770542|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|K|8|@]|9|@]|A|$E|F]]|$1|G|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|M|8|@]|9|@]|A|$]]]|I|$]]

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>    function getMaxOf2DIndex(arr, idx) {
    let maxItem = arr[0];
    
    arr.forEach((item, i) =&gt; {
        if(item[idx] &gt;= maxItem[idx])
            maxItem = item; 
    });
    
    return maxItem;
}</code></pre>
</div>
</div>
</p>


blocks|key|770548|text|以下是两个例子：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|770549|​|770550|const+ar+=+[
++["finalOrderData",1],
++["finalFabricData",3],
++["finalDecorationData",3],
++["finalHtData",3]
]

//+the+1st+result+of+the+biggest+value:
const+output1+=+ar.sort((A,B)+=>+B[1]+-+A[1])[0]

console.log(output1)
//+output:+["finalFabricData",3]

//+the+last+result+of+the+biggest+value:
const+output2+=+ar.sort((A,B)+=>+B[1]+<=+A[1]+?+-1+:+1)[0]

console.log(output2)
//+output:+["finalHtData",3]|code-block|syntax|javascript|770551|770552|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|K|$]]

<p>Here are 2 examples:</p>
<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const ar = [
  ["finalOrderData",1],
  ["finalFabricData",3],
  ["finalDecorationData",3],
  ["finalHtData",3]
]

// the 1st result of the biggest value:
const output1 = ar.sort((A,B) =&gt; B[1] - A[1])[0]

console.log(output1)
// output: ["finalFabricData",3]

// the last result of the biggest value:
const output2 = ar.sort((A,B) =&gt; B[1] &lt;= A[1] ? -1 : 1)[0]

console.log(output2)
// output: ["finalHtData",3]</code></pre>
</div>
</div>
</p>


blocks|key|653713|text|使用Array.reduce的另一个解决方案是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|653714|ar.reduce((res,+val)+=>+Math.max(res[1],val[1])+===+res[1]+?++res+:+val++);|code-block|syntax|javascript|653715|这里的诀窍是检查已经计算出来的结果。|653716|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

<p>one more Solution using Array.reduce:</p>
<pre><code>ar.reduce((res, val) =&gt; Math.max(res[1],val[1]) === res[1] ?  res : val  );
</code></pre>
<p>trick here is to check with already calculated result.</p>


<p>Given the array below, how can I return the element containing the max number?</p>
<pre><code>let ar = [[&quot;finalOrderData&quot;,1],[&quot;finalFabricData&quot;,3],[&quot;finalDecorationData&quot;,3],[&quot;finalHtData&quot;,3]]
</code></pre>
<p><strong>Expected Result</strong></p>
<pre><code>let ar = [&quot;finalFabricData&quot;,3]
</code></pre>
<p>This is the function I'm trying with, but it only returns the number itself:</p>
<pre><code>function getMaxOf2DIndex(arr, idx) {
  return Math.max.apply(null, arr.map(function (e) { return e[idx] }))
}
</code></pre>
<p>Appreciate any help!</p>


How to return the element of an array containing the max value (index 1) (Javascript)?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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给定下面的数组，如何返回包含最大值的元素？let ar = [["finalOrderData",1],["finalFabricData",3],["finalDecorationData",3],["finalHtData",3]]预期结果let ar = ["finalFabricData",3]这是我正在尝试的...

问如何返回包含最大值(索引1) (Javascript)的数组元素？
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问如何返回包含最大值(索引1) (Javascript)的数组元素？
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