blocks|key|2224122|text|人们说这个符号并不意味着加法。这是正确的，但并没有解释为什么加号类符号被用于非加法。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2224123|答案是，对于1位值的模加法，0%2B0+==+1%2B1+==+0和0%2B1+==+1%2B0+==+1。这些值与XOR相同。|2224124|所以，在这个上下文中加上一个圆圈意味着“按位加法模-2”。就像每个人都说的，异或表示整数。在数学中，在圆圈中使用加法是很常见的，这是一种加法，但不是常规的整数加法。|2224125|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

People are saying that the symbol doesn't mean addition. This is true, but doesn't explain why a plus-like symbol is used for something that isn't addition.

The answer is that for modulo addition of 1-bit values, 0+0 == 1+1 == 0, and 0+1 == 1+0 == 1. Those are the same values as XOR.

So, plus in a circle in this context means "bitwise addition modulo-2". Which is, as everyone says, XOR for integers. It's common in mathematics to use plus in a circle for an operation which is a sort of addition, but isn't regular integer addition.

blocks|key|2224049|text|这不是加号，而是二进制运算符异或的符号。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2224050|a+++b+++a+XOR+b
0+++0+++0
0+++1+++1
1+++0+++1
1+++1+++0|code-block|syntax|javascript|2224051|entityMap|0|LINK|mutability|MUTABLE|url|http://en.wikipedia.org/wiki/XOR^0|E|2|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

This is not an plus, but the sign for the binary operator <a href="http://en.wikipedia.org/wiki/XOR" rel="noreferrer">XOR</a>

<pre><code>a b a XOR b
0 0 0
0 1 1
1 0 1
1 1 0
</code></pre>

blocks|key|2223991|text|这不是一个额外的，而是一个独家或操作。至少输出确认为相同。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2223992|​|2223993|📷|atomic|offset|length|2223994|2223995|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://developer.qcloudimg.com/http-save/yehe-900000/c9d743dc14e490d0c111dff5fb44d6a8.gif|imageAlt^0|0|0|0|1|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@$G|V|H|W|1|X]]|A|$]]|$1|I|3|C|5|6|7|Y|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|K|$L|$5|M|N|O|A|$P|Q|R|-4]]]]

It's not an addition, but an exclusive OR operation. At least the output confirms to the same.

<a href="https://i.stack.imgur.com/cyBSX.gif" rel="noreferrer"><img src="https://i.stack.imgur.com/cyBSX.gif" alt="enter image description here"></a>

blocks|key|694910|text|那是异或运算符，而不是加号运算符|type|unstyled|depth|inlineStyleRanges|entityRanges|data|694911|XOR一点一点地工作，而不像PLUS那样继续工作。|694912|1+XOR+1+=+0
1+XOR+0+=+1
0+XOR+0+=+0
0+XOR+1+=+1|code-block|syntax|javascript|694913|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

That's the XOR operator, not the PLUS operator

XOR works bit by bit, without carrying over like PLUS does

<pre><code>1 XOR 1 = 0
1 XOR 0 = 1
0 XOR 0 = 0
0 XOR 1 = 1
</code></pre>

blocks|key|2224221|text|希望这个布局能工作，用一个异或把它带到二进制表示中。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2224222|66h+=+102+decimal+=+01100110+binary
FAh+=+250+decimal+=+11111010+binary
------------------------------------
++++++++++++++++++++10011100+binary+<------+that's+9Ch/156+decimal|code-block|syntax|javascript|2224223|XOR规则基本上是：|2224224|1+XOR+1=0+false|unordered-list-item|2224225|1+XOR+0=1真|2224226|0+XOR+0=0+false|2224227|但我之前链接的wiki将提供更多细节，如果needed...thats在您提供的屏幕截图中看起来是这样的话。|2224228|entityMap|0|LINK|mutability|MUTABLE|url|http://en.wikipedia.org/wiki/Exclusive_or^0|D|2|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|11|8|@]|9|@$A|12|B|13|1|14]]|C|$]]|$1|D|3|E|5|F|7|15|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|16|8|@]|9|@]|C|$]]|$1|K|3|L|5|M|7|17|8|@]|9|@]|C|$]]|$1|N|3|O|5|M|7|18|8|@]|9|@]|C|$]]|$1|P|3|Q|5|M|7|19|8|@]|9|@]|C|$]]|$1|R|3|S|5|6|7|1A|8|@]|9|@]|C|$]]|$1|T|3|-4|5|6|7|1B|8|@]|9|@]|C|$]]]|U|$V|$5|W|X|Y|C|$Z|10]]]]

Hope this layout works, take it to the binary representation with an <a href="http://en.wikipedia.org/wiki/Exclusive_or" rel="noreferrer">XOR</a>:

<pre><code>66h = 102 decimal = 01100110 binary
FAh = 250 decimal = 11111010 binary
------------------------------------
 10011100 binary &lt;------ that's 9Ch/156 decimal
</code></pre>

<ul>XOR rules are basically:
<li>1 XOR 1 = 0 false
<li>1 XOR 0 = 1 true
<li>0 XOR 0 = 0 false
</ul>

but the wiki I linked earlier will give you more details if needed...thats what it looks like they are doing in the screenshot you provided

blocks|key|2224019|text|圆圈中的加号不表示加法.这是一个异或操作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2224020|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

The plus-symbol in a circle does not denote addition. It is a XOR operation.

blocks|key|881040|text|这是独家或(异或)。如果我没记错的话，在按位进行数学时，点(.)和加号(%2B)表示OR。在加号周围加上一个圆圈以表示XOR，这与用于OR的样式是一致的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|881041|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

It's an exclusive or (XOR). If I remember correctly, when doing bitwise mathematics the dot (.) means AND and the plus (+) means OR. Putting a circle around the plus to mean XOR is consistent with the style used for OR.

blocks|key|881082|text|我在rampion和schnaader的回复中使用了逻辑。我将总结一下我是如何确认结果的。我将数字改为二进制，然后使用XOR-操作。或者，您可以使用十六进制表：点击这里！|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|881083|entityMap|0|LINK|mutability|MUTABLE|url|http://www.garykessler.net/library/byte_logic_table.html^0|28|5|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

I used the logic in the replies by rampion and schnaader. I will summarise how I confirmed the results. I changed the numbers to binary and then used the XOR-operation. Alternatively, you can use the Hexadecimal tables: <a href="http://www.garykessler.net/library/byte_logic_table.html" rel="nofollow noreferrer">Click here!</a>

blocks|key|695095|text|是异或。XOR函数的另一个名称是不带进位的加法。我想这就是这个符号的意义所在。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|695096|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

It is XOR. Another name for the XOR function is addition without carry. I suppose that's how the symbol might make sense.

I cannot understand the calculation "66 &oplus; fa = 9c". 
The sum is clearly over "ff", so I am confused. 
The topic is simple encryption algorithm.

What does a circled plus mean?

What does a circled plus mean?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋 

腾讯云代码助手

CODING DevOps

Cloud Studio

SDK中心

API中心

命令行工具

我无法理解"66⊕fa = 9c“的计算。和显然超过了"ff"，所以我很困惑。主题是简单的加密算法。圈加是什么意思？

问圆圈加号是什么意思？
EN

回答 9

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问圆圈加号是什么意思？EN

回答 9

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问圆圈加号是什么意思？
EN