blocks|key|1187387|text|试一试如下：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1187388|awk+'NR%253==0{print+$0}'+file|code-block|syntax|javascript|1187389|这将打印一行为三。或者：|1187390|awk+'NR%2510<9{print+$0}'+file+|1187391|会打印10行中的9行。|1187392|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Try something like:

<pre><code>awk 'NR%3==0{print $0}' file
</code></pre>

This will print one line in three. Or:

<pre><code>awk 'NR%10&lt;9{print $0}' file 
</code></pre>

will print 9 lines out of ten.

blocks|key|2080030|text|你可以用sed做这件事。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2080031|sed+-n+-e+'p;N;d;'+file+#+print+every+other+line,+starting+with+line+1|code-block|syntax|javascript|2080032|如果你有GNU，那就很容易了|2080033|sed+-n+-e+'0~10p'+file+#+print+every+10th+line
sed+-n+-e+'1~2p'+file+#+print+every+other+line+starting+with+line+1
sed+-n+-e+'0~2p'+file+#+print+every+other+line+starting+with+line+2|2080034|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You could possibly do it with sed, e.g.

<pre><code>sed -n -e 'p;N;d;' file # print every other line, starting with line 1
</code></pre>

If you have GNU sed it's pretty easy

<pre><code>sed -n -e '0~10p' file # print every 10th line
sed -n -e '1~2p' file # print every other line starting with line 1
sed -n -e '0~2p' file # print every other line starting with line 2
</code></pre>

blocks|key|1157965|text|这很容易用awk实现。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1157966|移除每一行：|1157967|awk+'NR+%25+2+==+0'+file+>+newfile|code-block|syntax|javascript|1157968|每隔10行删除一次：|1157969|awk+'NR+%25+10+!=+0'+file+>+newfile|1157970|awk中的NR变量是行号。在awk中，{}之外的任何内容都是有条件的，默认操作是打印。|1157971|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

This is easy to accomplish with awk.

Remove every other line:

<pre><code>awk 'NR % 2 == 0' file &gt; newfile
</code></pre>

Remove every 10th line:

<pre><code>awk 'NR % 10 != 0' file &gt; newfile
</code></pre>

The NR variable in awk is the line number. Anything outside of { } in awk is a conditional, and the default action is to print.

blocks|key|1187465|text|您可以使用awk和shell脚本。Awk可能很难但是..。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1187466|这将删除告诉它的特定行：|1187467|nawk+-f+awkfile.awk+[filename]

awkfile.awk+contents

BEGIN+{
if+(!lines)+lines="3+4+7+8"
n=split(lines,+lA,+FS)
for(i=1;i<=n;i%2B%2B)
+linesA[lA[i]]
}
!(FNR+in+linesA)|code-block|syntax|javascript|1187468|另外，我不记得VIM是否附带了标准的Ubuntu。如果得不到的话。|1187469|然后用vim+vim文件名打开文件。|1187470|然后键入|1187471|:%25!awk+NR\%252+or+:%25!awk+NR\%252+|1187472|这将删除所有其他行。只需将2改为另一个整数就可以得到不同的频率。|1187473|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|W|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|X|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|Y|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|Z|8|@]|9|@]|A|$]]|$1|O|3|P|5|F|7|10|8|@]|9|@]|A|$G|H]]|$1|Q|3|R|5|6|7|11|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

You can use a awk and a shell script. Awk can be difficult but... 

This will delete specific lines you tell it to:

<pre><code>nawk -f awkfile.awk [filename]

awkfile.awk contents

BEGIN {
if (!lines) lines="3 4 7 8"
n=split(lines, lA, FS)
for(i=1;i&lt;=n;i++)
 linesA[lA[i]]
}
!(FNR in linesA)
</code></pre>

Also I can't remember if VIM comes with the standard Ubuntu or not. If not get it.

Then open the file with vim
 vim [filename]

Then type

<pre><code>:%!awk NR\%2 or :%!awk NR\%2 
</code></pre>

This will delete every other line. Just change the 2 to another integer for a different frequency.

blocks|key|2075425|text|perl怎么样？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2075426|perl+-n+-e+'$.%2510==0&&print'+++++++#+print+every+10th+line|code-block|syntax|javascript|2075427|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

How about perl?

<pre><code>perl -n -e '$.%10==0&amp;&amp;print' # print every 10th line
</code></pre>

blocks|key|1158027|text|这可能对您有用(GNU+sed)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1158028|seq+10+%7C+sed+'0~2d'+#+delete+every+2nd+line
1
3
5
7
9
seq+100+%7C+sed+'0~10!d'+#+delete+9+out+of+10+lines
10
20
30
40
50
60
70
80
90
100|code-block|syntax|javascript|1158029|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This might work for you (GNU sed):

<pre><code>seq 10 | sed '0~2d' # delete every 2nd line
1
3
5
7
9
seq 100 | sed '0~10!d' # delete 9 out of 10 lines
10
20
30
40
50
60
70
80
90
100
</code></pre>

Consider a text file with scientific data, e.g.:

<pre><code>5.787037037037037063e-02 2.048402977658663748e-01
1.157407407407407413e-01 4.021264347118673754e-01
1.736111111111111049e-01 5.782032163406526371e-01
</code></pre>

How can I easily delete, for instance, every second line, or every 9 out of 10 lines in the file? Is it for example possible with a bash script?

Background: the file is very large but I need much less data to plot. Note that I am using Ubuntu/Linux.

How can I delete every Xth line in a text file?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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考虑具有科学数据的文本文件，例如：5.787037037037037063e-02 2.048402977658663748e-011.157407407407407413e-01 4.021264347118673754e-011.736111111111111049e-01 5.782032163406526371...

问如何删除文本文件中的每一行？
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问如何删除文本文件中的每一行？EN