blocks|key|858673|text|我想解决这个问题的一种方法是为一个循环运行一个脚本，这将是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|858674|检查脚本的其他实例是否正在运行|ordered-list-item|858675|查看队列，处理那里找到的所有东西。|858676|现在，您可以在上午8点之间的每分钟运行这个脚本。晚上8点。唯一的缺点是新的项目可能会有一段时间被处理。|858677|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$]]|$1|E|3|F|5|D|7|M|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|N|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|O|8|@]|9|@]|A|$]]]|J|$]]

I guess one way to work around the issue is having a script for one loop run, that would:

<ol>
<li>check no other instance of the script is running</li>
<li>look into the queue and process everything found there</li>
</ol>

Now, then you can run this script from cron every minute between 8 a.m. and 8 p.m. The only downside is that new items may some time to get processed.

blocks|key|1256294|text|让我给你一个替代方案。看起来你想要实时更新某种信息。可以使用pub/sub接口(发布/订阅)。因为您正在使用python，所以有很多可能性。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1256295|其中之一是使用Redis发布/子功能：http://redis.io/topics/pubsub/+-下面是对应的python模块：红皮|offset|length|1256296|-更新-|style|BOLD|1256297|示例|1256298|下面是dirkk0+(问题+/回答)的一个示例：|1256299|import+sys
import+threading

import+cmd


def+monitor():
++++r+=+redis.Redis(YOURHOST,+YOURPORT,+YOURPASSWORD,+db=0)

++++channel+=+sys.argv[1]
++++p+=+r.pubsub()

++++p.subscribe(channel)

++++print+'monitoring+channel',+channel
++++for+m+in+p.listen():
++++++++print+m['data']


class+my_cmd(cmd.Cmd):
++++"""Simple+command+processor+example."""

++++def+do_start(self,+line):
++++++++my_thread.start()

++++def+do_EOF(self,+line):
++++++++return+True

if+__name__+==+'__main__':
++++if+len(sys.argv)+==+1:
++++++++print+"missing+argument!+please+provide+the+channel+name."
++++else:
++++++++my_thread+=+threading.Thread(target=monitor)
++++++++my_thread.setDaemon(True)

++++++++my_cmd().cmdloop()|code-block|syntax|javascript|1256300|-更新2-|1256301|此外，请参阅本教程：|1256302|http://blog.abourget.net/2011/3/31/new-and-hot-part-6-redis-publish-and-subscribe/|1256303|entityMap|0|LINK|mutability|MUTABLE|url|http://redis.io/|1|http://redis.io/topics/pubsub/|2|https://github.com/andymccurdy/redis-py/|3|https://stackoverflow.com/users/573216/dirkk0|4|https://stackoverflow.com/questions/7871526/is-non-blocking-redis-pubsub-possible|5|https://stackoverflow.com/a/8800112/675065|6^0|0|7|5|0|J|U|1|1U|2|2|0|1|2|0|0|3|6|3|B|2|4|F|2|5|0|0|1|3|0|0|0|2A|6|0^^$0|@$1|2|3|4|5|6|7|1H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|1I|8|@]|9|@$D|1J|E|1K|1|1L]|$D|1M|E|1N|1|1O]|$D|1P|E|1Q|1|1R]]|A|$]]|$1|F|3|G|5|6|7|1S|8|@$D|1T|E|1U|H|I]]|9|@]|A|$]]|$1|J|3|K|5|6|7|1V|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|1W|8|@]|9|@$D|1X|E|1Y|1|1Z]|$D|20|E|21|1|22]|$D|23|E|24|1|25]]|A|$]]|$1|N|3|O|5|P|7|26|8|@]|9|@]|A|$Q|R]]|$1|S|3|T|5|6|7|27|8|@$D|28|E|29|H|I]]|9|@]|A|$]]|$1|U|3|V|5|6|7|2A|8|@]|9|@]|A|$]]|$1|W|3|X|5|6|7|2B|8|@]|9|@$D|2C|E|2D|1|2E]]|A|$]]|$1|Y|3|-4|5|6|7|2F|8|@]|9|@]|A|$]]]|Z|$10|$5|11|12|13|A|$14|15]]|16|$5|11|12|13|A|$14|17]]|18|$5|11|12|13|A|$14|19]]|1A|$5|11|12|13|A|$14|1B]]|1C|$5|11|12|13|A|$14|1D]]|1E|$5|11|12|13|A|$14|1F]]|1G|$5|11|12|13|A|$14|X]]]]

Let me present you an alternative. It looks like you want real-time updates for some kind of information. You could use a pub/sub interface (publish/subscribe). Since you are using python, there are plenty of possibilities.

One of them is using <a href="http://redis.io/" rel="nofollow noreferrer">Redis</a> pub/sub functionality: <a href="http://redis.io/topics/pubsub/" rel="nofollow noreferrer">http://redis.io/topics/pubsub/</a> - and here is the corresponding python module: <a href="https://github.com/andymccurdy/redis-py/" rel="nofollow noreferrer">redis-py</a>

-Update- 

<h2>Example</h2>

Here is an example from <a href="https://stackoverflow.com/users/573216/dirkk0">dirkk0</a> (<a href="https://stackoverflow.com/questions/7871526/is-non-blocking-redis-pubsub-possible">question</a> / <a href="https://stackoverflow.com/a/8800112/675065">answer</a>):

<pre><code>import sys
import threading

import cmd


def monitor():
 r = redis.Redis(YOURHOST, YOURPORT, YOURPASSWORD, db=0)

 channel = sys.argv[1]
 p = r.pubsub()

 p.subscribe(channel)

 print 'monitoring channel', channel
 for m in p.listen():
 print m['data']


class my_cmd(cmd.Cmd):
 """Simple command processor example."""

 def do_start(self, line):
 my_thread.start()

 def do_EOF(self, line):
 return True

if __name__ == '__main__':
 if len(sys.argv) == 1:
 print "missing argument! please provide the channel name."
 else:
 my_thread = threading.Thread(target=monitor)
 my_thread.setDaemon(True)

 my_cmd().cmdloop()
</code></pre>

-Update 2-

In addition, look at this tutorial:

<a href="http://blog.abourget.net/2011/3/31/new-and-hot-part-6-redis-publish-and-subscribe/" rel="nofollow noreferrer">http://blog.abourget.net/2011/3/31/new-and-hot-part-6-redis-publish-and-subscribe/</a>

blocks|key|1733803|text|我认为保持浏览器页面并不一定会停止python脚本，我建议您在父进程的控制下使用叉启动脚本：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1733804|例子：|unordered-list-item|1733805|输入os，时间，信号|1733806|def+child():
+++print+'A+new+child+',++os.getpid(+)
+++time.sleep(5)
+++os._exit(0)++

def+parent():
+++while+True:
++++++newpid+=+os.fork()
++++++if+newpid+==+0:
+++++++++child()
++++++else:
+++++++++pids+=+(os.getpid(),+newpid)
+++++++++print+"parent:+%25d,+child:+%25d"+%25+pids
+++++++++print+"start+counting+time+for+child+process...!"
+++++++++time1+=+time.clock()
+++++++++while+True:
++++++++++++++++++#time.sleep(1)
++++++++++++++++++time2+=+time.clock()
++++++++++++++++++#+Check+if+the+execution+time+for+child+process+exceeds+10+minutes...+
++++++++++++++++++if+time2-time1+>=+2+:
+++++++++++++++++++++++++++os.kill(int(newpid),+signal.SIGKILL)
+++++++++++++++++++++++++++break

++++++if+raw_input(+)+==+'q':+break

parent()|code-block|syntax|javascript|1733807|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|O|8|@]|9|@]|A|$]]|$1|E|3|F|5|6|7|P|8|@]|9|@]|A|$]]|$1|G|3|H|5|I|7|Q|8|@]|9|@]|A|$J|K]]|$1|L|3|-4|5|6|7|R|8|@]|9|@]|A|$]]]|M|$]]

i think holding browser page does not necessarily stop the python script, I suggest that you start your script under control of a parent process using FORK:

<ul>
<li>Example :</li>
</ul>

import os, time, signal

<pre><code>def child():
 print 'A new child ', os.getpid( )
 time.sleep(5)
 os._exit(0) 

def parent():
 while True:
 newpid = os.fork()
 if newpid == 0:
 child()
 else:
 pids = (os.getpid(), newpid)
 print "parent: %d, child: %d" % pids
 print "start counting time for child process...!"
 time1 = time.clock()
 while True:
 #time.sleep(1)
 time2 = time.clock()
 # Check if the execution time for child process exceeds 10 minutes... 
 if time2-time1 &gt;= 2 :
 os.kill(int(newpid), signal.SIGKILL)
 break

 if raw_input( ) == 'q': break

parent()
</code></pre>

I'm working on a Python script that will constantly scrape data, but it will take quite a long time. Is there a safe way to stop a long running python script? The loop will run for more than 10 minutes and I need a way to stop it if I want, after it's already running.

If I execute it from a cron job, then I'm assuming it'll just run until it's finished, so how do I stop it?

Also, if I run it from a browser and just call the file. I'm assuming stopping the page from loading would halt it, correct?

<hr>

Here's the scenario: I have one python script that is gather info from pages and put it into a queue. Then I want to have another python script that is in an infinite loop that just checks for new items in the queue. Lets say I want the infinite loop to begin at 8am and end at 8pm. How do I accomplish this?

Stop python script in infinite loop

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在编写一个Python脚本，它将不断地抓取数据，但它将花费相当长的时间。有没有安全的方法来阻止长时间运行的python脚本？循环将运行超过10分钟，我需要一个方法来阻止它，如果我想，在它已经运行之后。如果我从cron作业执行它，那么我假设它会一直运行到它完成为止，那么我该如何阻止它呢？另外，如果我在浏览器上运行它，...

问在无限循环中停止python脚本
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