我的应用程序包含一个嵌入在UITableViewController中的UIPageViewController,它不时引发这个异常:
Invalid parameter not satisfying: [views count] == 3回溯:
* thread #1: tid = 0x6239fa, 0x03d1d88a libobjc.A.dylib`objc_exception_throw, queue = 'com.apple.main-thread, stop reason = breakpoint 25.3
frame #0: 0x03d1d88a libobjc.A.dylib`objc_exception_throw
frame #1: 0x0404f448 CoreFoundation`+[NSException raise:format:arguments:] + 136
frame #2: 0x03428fee Foundation`-[NSAssertionHandler handleFailureInMethod:object:file:lineNumber:description:] + 116
frame #3: 0x01e7c535 UIKit`-[_UIQueuingScrollView _replaceViews:updatingContents:adjustContentInsets:animated:] + 185
frame #4: 0x01e800ca UIKit`-[_UIQueuingScrollView _didScrollWithAnimation:force:] + 1231
frame #5: 0x01e7bb57 UIKit`-[_UIQueuingScrollView _scrollViewAnimationEnded:finished:] + 104
frame #6: 0x0190583c UIKit`-[UIScrollView(UIScrollViewInternal) animator:stopAnimation:fraction:] + 62
frame #7: 0x0197096e UIKit`-[UIAnimator stopAnimation:] + 533
frame #8: 0x0197100a UIKit`-[UIAnimator(Static) _advanceAnimationsOfType:withTimestamp:] + 325
frame #9: 0x01970b76 UIKit`-[UIAnimator(Static) _LCDHeartbeatCallback:] + 67
frame #10: 0x01663b8a QuartzCore`CA::Display::DisplayLinkItem::dispatch() + 48
frame #11: 0x01663a46 QuartzCore`CA::Display::DisplayLink::dispatch_items(unsigned long long, unsigned long long, unsigned long long) + 310
frame #12: 0x01663f6b QuartzCore`CA::Display::TimerDisplayLink::callback(__CFRunLoopTimer*, void*) + 123
frame #13: 0x0400dbd6 CoreFoundation`__CFRUNLOOP_IS_CALLING_OUT_TO_A_TIMER_CALLBACK_FUNCTION__ + 22
frame #14: 0x0400d5bd CoreFoundation`__CFRunLoopDoTimer + 1181
frame #15: 0x03ff5628 CoreFoundation`__CFRunLoopRun + 1816
frame #16: 0x03ff4ac3 CoreFoundation`CFRunLoopRunSpecific + 467
frame #17: 0x03ff48db CoreFoundation`CFRunLoopRunInMode + 123
frame #18: 0x0533b9e2 GraphicsServices`GSEventRunModal + 192
frame #19: 0x0533b809 GraphicsServices`GSEventRun + 104
frame #20: 0x01874d3b UIKit`UIApplicationMain + 1225有没有人见过这个,或者知道原因是什么?
发布于 2014-11-18 19:19:53
当我试图以编程方式转换到一个新页面时,我看到了这种崩溃。对我来说有意义的一个答案是,在过渡期间不允许他们触摸页面视图。
__block UIView *pageView = pageViewController.view;
// Disable page view to not allow the user to interrupt the page view animation and cause crash
pageView.userInteractionEnabled = NO;
[pageViewController setViewControllers:@[viewController] direction:UIPageViewControllerNavigationDirectionForward animated:YES completion:^(BOOL finished) {
if (finished) {
pageView.userInteractionEnabled = YES; // re-enable
}
}];https://stackoverflow.com/questions/20004310
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