是否有一种简单的方法可以将以下字符串解析为整数列表:
String s = "1,2,5-9,11,12"
// expected values list: [1,2,5,6,7,8,9,11,12]
List<Integer> values = magicallyGetListFromString(s);我想知道是否有一个简单的方法来做,而不是自己写。
发布于 2014-07-08 11:39:58
List<Integer> out=new ArrayList<Integer>();
String numbers[]=s.split(",");
for(String part:numbers){
if(part.contains("-"){
int a=Integer.parseInt(part.split("-")[0]);
int b=Integer.parseInt(part.split("-")[1]);
while(a<=b){
out.add(a++);
}
}else{
out.add(Integer.parseInt(part));
}
}发布于 2014-07-08 11:32:38
public static void main(String[] args) {
String str = "1,2,5-9,11,12,19-21";
String[] val = str.split(",");
List<Integer> l = new ArrayList<Integer>();
for (String s : val) {
if (s.contains("-")) {
String[] strVal = s.split("-");
int startVal = Integer.parseInt(strVal[0]);
int endVal = Integer.parseInt(strVal[1]);
for (int i = startVal; i <= endVal; i++) {
l.add(i);
}
} else {
l.add(Integer.parseInt(s));
}
}
for (int j : l) {
System.out.println(j);
}
}文书主任:1 2 5 6 7 8 9 11 12 19 20 21
发布于 2014-07-08 11:43:12
这应该是可行的:
public class StringMagic
{
public static void main(String[] args)
{
String s = "1,2,5-9,11,12";
// expected values list: [1,2,5,6,7,8,9,11,12]
List<Integer> values = magicallyGetListFromString(s);
for (Integer integer : values)
{
System.out.println(integer);
}
}
public static List<Integer> magicallyGetListFromString(String s)
{
List<Integer> numberList = new ArrayList<Integer>();
String[] numbers = s.split(",");
for (String string : numbers)
{
if (!string.contains("-"))
{
numberList.add(Integer.parseInt(string));
}
else
{
String[] limits = string.split("-");
int bottomLimit = Integer.parseInt(limits[0]);
int upperLimit = Integer.parseInt(limits[1]);
for(int i = bottomLimit; i <= upperLimit; i++)
{
numberList.add(i);
}
}
}
return numberList;
}
}https://stackoverflow.com/questions/24630698
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