blocks|key|637061|text|setScale返回一个带有结果的新BigDecimal，它不会更改调用它的实例。因此，将返回值赋值给value|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|637062|value+=+value.setScale(0,+RoundingMode.UP);|code-block|syntax|javascript|637063|实例化|637064|我还把它改成了RoundingMode.UP，因为你说你一直想聚在一起。但是，根据您的需要，您可能需要RoundingMode.CEILING；这取决于您希望-451.2变成什么(-452+UP或-451+CEILING)。有关更多信息，请参见RoundingMode。|637065|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/8/docs/api/java/math/BigDecimal.html#setScale-int-int-|1|http://ideone.com/B5Xmu8|2|http://docs.oracle.com/javase/8/docs/api/java/math/RoundingMode.html^0|0|8|I|A|1F|5|0|8|0|0|0|0|3|1|0|7|F|1F|K|27|6|2I|4|2N|2|2Q|4|2V|7|3E|C|3E|C|2|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]|$9|13|A|14|B|C]|$9|15|A|16|B|C]]|D|@$9|17|A|18|1|19]]|E|$]]|$1|F|3|G|5|H|7|1A|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1B|8|@]|D|@$9|1C|A|1D|1|1E]]|E|$]]|$1|M|3|N|5|6|7|1F|8|@$9|1G|A|1H|B|C]|$9|1I|A|1J|B|C]|$9|1K|A|1L|B|C]|$9|1M|A|1N|B|C]|$9|1O|A|1P|B|C]|$9|1Q|A|1R|B|C]|$9|1S|A|1T|B|C]|$9|1U|A|1V|B|C]]|D|@$9|1W|A|1X|1|1Y]]|E|$]]|$1|O|3|-4|5|6|7|1Z|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]|W|$5|R|S|T|E|$U|X]]|Y|$5|R|S|T|E|$U|Z]]]]

<a href="http://docs.oracle.com/javase/8/docs/api/java/math/BigDecimal.html#setScale-int-int-"><code>setScale</code></a> returns a new <code>BigDecimal</code> with the result, it doesn't change the instance you call it on. So assign the return value back to <code>value</code>:

<pre><code>value = value.setScale(0, RoundingMode.UP);
</code></pre>

<a href="http://ideone.com/B5Xmu8">Live Example</a>

I also changed it to <code>RoundingMode.UP</code> because you said you always wanted to round up. But depending on your needs, you might want <code>RoundingMode.CEILING</code> instead; it depends on what you want <code>-451.2</code> to become (<code>-452</code> [<code>UP</code>] or <code>-451</code> [<code>CEILING</code>]). See <a href="http://docs.oracle.com/javase/8/docs/api/java/math/RoundingMode.html"><code>RoundingMode</code></a> for more.

blocks|key|774937|text|用途：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|774938|value.setScale(0,+RoundingMode.CEILING);|code-block|syntax|javascript|774939|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

use:

<pre><code>value.setScale(0, RoundingMode.CEILING);
</code></pre>

blocks|key|774973|text|从方法描述：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|774974|请注意，由于BigDecimal对象是不可变的，所以setScale方法的调用不会导致修改原始对象，这与通常的方法名为setX变异字段X的惯例相反。相反，setScale返回一个具有适当比例的对象；返回的对象可能是新分配的，也可能不是新分配的。|blockquote|774975|public+void+test()+{
++BigDecimal+value+=+new+BigDecimal(450.90);
++System.out.println(value.setScale(0,+RoundingMode.HALF_UP));+//+prints+451
}|code-block|syntax|javascript|774976|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|M|8|@]|9|@]|A|$]]|$1|E|3|F|5|G|7|N|8|@]|9|@]|A|$H|I]]|$1|J|3|-4|5|6|7|O|8|@]|9|@]|A|$]]]|K|$]]

From method description:

<blockquote>
 Note that since BigDecimal objects are immutable, calls of setScale
 method do not result in the original object being modified, contrary
 to the usual convention of having methods named setX mutate field X.
 Instead, setScale returns an object with the proper scale; the
 returned object may or may not be newly allocated.
</blockquote>

<pre><code>public void test() {
 BigDecimal value = new BigDecimal(450.90);
 System.out.println(value.setScale(0, RoundingMode.HALF_UP)); // prints 451
}
</code></pre>

blocks|key|774924|text|您需要使用返回的值|type|unstyled|depth|inlineStyleRanges|entityRanges|data|774925|BigDecimal+value+=+new+BigDecimal(450.90);
value+=+value.setScale(0,+RoundingMode.HALF_UP);+//Also+tried+with+RoundingMode.UP|code-block|syntax|javascript|774926|注意，BigDecimal是不变的|offset|length|774927|缩放/舍入操作(setScale和圆形)返回的值大约(或完全)等于操作数的值，但其规模或精度是指定值；也就是说，它们增加或降低存储数字的精度，但对其值的影响最小。|blockquote|774928|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/7/docs/api/java/math/BigDecimal.html^0|0|0|3|A|0|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|W|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|X|8|@]|9|@$I|Y|J|Z|1|10]]|A|$]]|$1|K|3|L|5|M|7|11|8|@]|9|@]|A|$]]|$1|N|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|O|$P|$5|Q|R|S|A|$T|U]]]]

you need to use the returned value

<pre><code>BigDecimal value = new BigDecimal(450.90);
value = value.setScale(0, RoundingMode.HALF_UP); //Also tried with RoundingMode.UP
</code></pre>

note that <a href="http://docs.oracle.com/javase/7/docs/api/java/math/BigDecimal.html" rel="nofollow">BigDecimal</a> is invariant 

<blockquote>
 Scaling/rounding operations (setScale and round) return a BigDecimal
 whose value is approximately (or exactly) equal to that of the
 operand, but whose scale or precision is the specified value; that is,
 they increase or decrease the precision of the stored number with
 minimal effect on its value.
</blockquote>

blocks|key|1873757|text|使用Math.ceil()函数。ceil方法提供大于或等于参数的最小整数。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1873758|你可以在上面读这里|1873759|entityMap|0|LINK|mutability|MUTABLE|url|http://www.tutorialspoint.com/java/number_ceil.htm^0|2|B|0|7|2|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|S|8|@]|D|@$9|T|A|U|1|V]]|E|$]]|$1|H|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|I|$J|$5|K|L|M|E|$N|O]]]]

use the <code>Math.ceil()</code> function. The method ceil gives the smallest integer that is greater than or equal to the argument.

You can read up on it <a href="http://www.tutorialspoint.com/java/number_ceil.htm" rel="nofollow">here</a>

I have a BigDecimal which value is 450.90, I want to round up to next hole integer value, and then print the Integer value without any decimal points, like this;

Val: 450.90 -> Rounded: 451.00 -> Output: 451

Val: 100.00001 -> Rounded: 101.00000 Output: 101

Checked some solutions but I'm not getting the expected result, heres my code;

<pre><code>BigDecimal value = new BigDecimal(450.90);
value.setScale(0, RoundingMode.HALF_UP); //Also tried with RoundingMode.UP
return value.intValue();
</code></pre>

Thanks!

Round up BigDecimal to Integer value

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个值为450.90的BigDecimal，我想把它集合到下一个洞整数值，然后打印不带任何小数点的整数值，如下所示；阀值: 450.90 ->四舍五入: 451.00 ->输出: 451阀值: 100.00001 ->四舍五入: 101.00000输出: 101检查了一些解决方案，但我没有得到预期的结果，这是我的代码；BigDecimal value = new BigDecimal(450.

问将BigDecimal集合为整数值
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