如何在UIMenuItems中禁用UIMenuController的复制和定义
如何在UIMenuItems中禁用UIMenuController的复制和定义
提问于 2015-01-02 18:58:49
我正在实现自定义UIMenuController，并试图找出。我如何合法地禁用“复制”和“定义”UIMenuItems of UIMenuController in UITextfield？Textfield不可编辑。我试图禁用“复制”，使用：
-(BOOL)canPerformAction:(SEL)action withSender:(id)sender
{
if (action == @selector(copy:))
{
return NO;
}
return [super canPerformAction:action withSender:sender];
}
- (IBAction)tapTextViewGesture:(id)sender {
UIMenuItem *myItem1 = [[UIMenuItem alloc] initWithTitle:@"myItem1" action:@selector(myItem1Pressed:)];
UIMenuItem *myItem2 = [[UIMenuItem alloc] initWithTitle:@"myItem2" action:@selector(myItem2Pressed:)];
UIMenuItem *myItem3 = [[UIMenuItem alloc] initWithTitle:@"myItem3" action:@selector(myItem3Pressed:)];
// Access the application's shared menu
UIMenuController *menu = [UIMenuController sharedMenuController];
[menu setMenuItems:[NSArray arrayWithObjects:myItem1,myItem2,myItem3, nil]];
CGRect menuRect = CGRectMake(20, 50, 200, 0);
// Show the menu from the cursor's position
[menu setTargetRect:menuRect inView:self.view];
[menu setMenuVisible:YES animated:YES];
}但是菜单仍然显示“复制”和“定义”UIMenuItems。我怎样才能禁用他们，只留下我的物品？
Stack Overflow用户
发布于 2018-11-01 15:03:56
SWIFT4.2. && Xcode 10，适用于我：
public extension UITextView {
override func canPerformAction(_ action: Selector, withSender sender: Any?) -> Bool {
// Requested action to prevent:
guard action != #selector(copy(_:)) else { return false } // disabling copy
// Further actions to prevent:
// guard action != #selector(cut(_:)) else { return false } // disabling cut
// guard action.description != "_share:" else { return false } // disabling share
return super.canPerformAction(action, withSender: sender)
}
}为了完成这项工作，您必须创建UITextField/UITextView的子类，并确保调用super.canPerformAction(_:withSender:)上的super！
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/27747140
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