文本节点xpath的Jsoup选择器
文本节点xpath的Jsoup选择器
提问于 2015-02-18 01:38:28
HTML代码张贴在末尾，我想选择"OF“元素。这是CSS选择器
Elements position = doc.select("#content > table:nth-child(4) > tbody > tr > td:nth-child(1) > table > tbody > tr:nth-child(1) > td > div:nth-child(5) > strong:nth-child(4)");
for (Element p : position) {
System.out.println(p);
}这是输出
p returns "<strong>Position:</strong>"
p.text() returns "Position:"当我高亮显示“OF”时，使用chrome中的xpath：
//*@id="content"]/table[1]/tbody/tr/td[1]/table/tbody/tr[1]/td/div[3]/text()[4]HTML代码
<div style="font-size: 10pt; padding-left:5px;">
<strong>Birthdate:</strong> 8/7/1991 (23 y, 6 m, 10 d)
<strong>Bats/Throws:</strong> R/R
<strong>Height/Weight:</strong> 6-2/230
<strong>Position:</strong> OF<br /><b>Drafted:</b> <a href="statss.aspx?playerid=10155&position=OF#draft" style="text-decoration:none;">2009 June Amateur Draft - Round: 1, Pick: 25, Overall: 25, Team: Los Angeles Angels</a><br />
<strong>Contract:</strong> <a href="statss.aspx?playerid=10155&position=OF#contract" style="text-decoration:none;">$144.5M / 6 Years (2015 - 2020)</a>
</div>
<div style="font-size: 10pt; padding-left:5px;">
<strong>Birthdate:</strong> 8/7/1991 (23 y, 6 m, 10 d)
<strong>Bats/Throws:</strong> R/R
<strong>Height/Weight:</strong> 6-2/230
<strong>Position:</strong> OF<br /><b>Drafted:</b> <a href="statss.aspx?playerid=10155&position=OF#draft" style="text-decoration:none;">2009 June Amateur Draft - Round: 1, Pick: 25, Overall: 25, Team: Los Angeles Angels</a><br />
<strong>Contract:</strong> <a href="statss.aspx?playerid=10155&position=OF#contract" style="text-decoration:none;">$144.5M / 6 Years (2015 - 2020)</a>
</div>如果有人感兴趣的话，这是http://www.fangraphs.com/statss.aspx?playerid=10155&position=OF的页面
回答 1
Stack Overflow用户
回答已采纳
发布于 2015-02-18 01:52:35
您不能为文本节点编写css选择器("OF“是包含在目标div元素中的第四个文本节点)。因此，您需要像这样以编程的方式进行抓取(需要>= 1.6.2)：
// select container div element
Elements position = doc.select("#content > table:nth-child(4) > tbody > tr > td:nth-child(1) > table > tbody > tr:nth-child(1) > td > div:nth-child(5)");
// extract the element from the list returned
Element element = ....
// TODO will need to check that the List exists and have at least four elements here
TextNode ofNode = element.textNodes().get(4);
ofNode.text(); // this will contain "OF"页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/28574500
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