blocks|key|1898165|text|试试下面的代码。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1898166|它迭代从-13到%2B4从当前日期所需的周，并将特定的一天调整为所需的一天(在本例中为Saturday)。|offset|length|style|CODE|1898167|for+(int+i+=+-13;+i+<=+4;+i%2B%2B)
{
++++var+dateBackWithIWeeks+=+DateTime.Now.AddDays(i+*+7);
++++switch+(dateBackWithIWeeks.DayOfWeek)
++++{
++++++++case+DayOfWeek.Sunday:
++++++++++++dateBackWithIWeeks+=+dateBackWithIWeeks.AddDays(-1);
++++++++++++break;
++++++++case+DayOfWeek.Monday:
++++++++++++dateBackWithIWeeks+=+dateBackWithIWeeks.AddDays(5);
++++++++++++break;
++++++++case+DayOfWeek.Tuesday:
++++++++++++dateBackWithIWeeks+=+dateBackWithIWeeks.AddDays(4);
++++++++++++break;
++++++++case+DayOfWeek.Wednesday:
++++++++++++dateBackWithIWeeks+=+dateBackWithIWeeks.AddDays(3);
++++++++++++break;
++++++++case+DayOfWeek.Thursday:
++++++++++++dateBackWithIWeeks+=+dateBackWithIWeeks.AddDays(2);
++++++++++++break;
++++++++case+DayOfWeek.Friday:
++++++++++++dateBackWithIWeeks+=+dateBackWithIWeeks.AddDays(1);
++++++++++++break;
++++++++case+DayOfWeek.Saturday:
++++++++++++break;
++++}

++++Console.WriteLine(dateBackWithIWeeks.Date);
}|code-block|syntax|javascript|1898168|entityMap^0|0|4|3|8|2|15|8|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@$D|Q|E|R|F|G]|$D|S|E|T|F|G]|$D|U|E|V|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|W|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|X|8|@]|9|@]|A|$]]]|N|$]]

Try the following code.

It iterates through the weeks you need from <code>-13</code> to <code>+4</code> weeks from the current date and adjusts the specific day to the one you need (in this case <code>Saturday</code>)

<pre><code>for (int i = -13; i &lt;= 4; i++)
{
 var dateBackWithIWeeks = DateTime.Now.AddDays(i * 7);
 switch (dateBackWithIWeeks.DayOfWeek)
 {
 case DayOfWeek.Sunday:
 dateBackWithIWeeks = dateBackWithIWeeks.AddDays(-1);
 break;
 case DayOfWeek.Monday:
 dateBackWithIWeeks = dateBackWithIWeeks.AddDays(5);
 break;
 case DayOfWeek.Tuesday:
 dateBackWithIWeeks = dateBackWithIWeeks.AddDays(4);
 break;
 case DayOfWeek.Wednesday:
 dateBackWithIWeeks = dateBackWithIWeeks.AddDays(3);
 break;
 case DayOfWeek.Thursday:
 dateBackWithIWeeks = dateBackWithIWeeks.AddDays(2);
 break;
 case DayOfWeek.Friday:
 dateBackWithIWeeks = dateBackWithIWeeks.AddDays(1);
 break;
 case DayOfWeek.Saturday:
 break;
 }

 Console.WriteLine(dateBackWithIWeeks.Date);
}
</code></pre>

blocks|key|1898212|text|基于注释的更新|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|1898213|注意:代码可能需要调整，这取决于您如何定义“13周前”(以及“从现在起的4周”)--您是在考虑日历周，还是真正的13*7天？下面的代码可以追溯到13天*7天。|1898214|有一种方法可以做到：|1898215|创建一个今天的开始日期，减去13周|ordered-list-item|1898216|将开始日期调整到下一个星期六(如果不是星期六)|1898217|创建一个今天的结束日期加上4个星期。|1898218|从开始到结束每7天，把这一天添加到列表中。|1898219|按日期顺序列表，然后降序|1898220|下面是一个示例实现：|1898221|var+saturdays+=+new+List<DateTime>();
var+daysInWeek+=+7;

var+startDate+=+DateTime.Today.Subtract(TimeSpan.FromDays(13+*+daysInWeek));

//+Adjust+start+date+so+it+is+the+first+Saturday+after+13+weeks+before+today
startDate+=+startDate.AddDays(DayOfWeek.Saturday+-+startDate.DayOfWeek);

var+endDate+=+DateTime.Today.Add(TimeSpan.FromDays(4+*+daysInWeek));

for+(var+curDate+=+startDate;+curDate+<=+endDate;+curDate+=+curDate.AddDays(daysInWeek))
{
++++saturdays.Add(curDate);
}

//+Order+by+date,+descending
saturdays+=+saturdays.OrderByDescending(d+=>+d).ToList();

//+Output+list+of+Saturdays+to+console+for+verification
saturdays.ForEach(s+=>+Console.WriteLine(s.ToShortDateString()));|code-block|syntax|javascript|1898222|entityMap^0|5|2|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|13|8|@$9|14|A|15|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|16|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|17|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|18|8|@]|D|@]|E|$]]|$1|M|3|N|5|L|7|19|8|@]|D|@]|E|$]]|$1|O|3|P|5|L|7|1A|8|@]|D|@]|E|$]]|$1|Q|3|R|5|L|7|1B|8|@]|D|@]|E|$]]|$1|S|3|T|5|L|7|1C|8|@]|D|@]|E|$]]|$1|U|3|V|5|6|7|1D|8|@]|D|@]|E|$]]|$1|W|3|X|5|Y|7|1E|8|@]|D|@]|E|$Z|10]]|$1|11|3|-4|5|6|7|1F|8|@]|D|@]|E|$]]]|12|$]]

UPDATED BASED ON COMMENTS

Note: Code may need to be adjusted depending on how you define '13 weeks ago' (and '4 weeks from now') - are you considering calendar weeks, or literally 13 * 7 days? The code below looks back 13 * 7 days.

Here's one way to do it:

<ol>
<li>Create a start date of today minus 13 weeks</li>
<li>Adjust the start date to the next Saturday (if it isn't a Saturday)</li>
<li>Create an end date of today plus 4 weeks</li>
<li>For every 7 days from start to end, add the day to a list</li>
<li>Order the list by date, descending</li>
</ol>

Here's a sample implementation:

<pre><code>var saturdays = new List&lt;DateTime&gt;();
var daysInWeek = 7;

var startDate = DateTime.Today.Subtract(TimeSpan.FromDays(13 * daysInWeek));

// Adjust start date so it is the first Saturday after 13 weeks before today
startDate = startDate.AddDays(DayOfWeek.Saturday - startDate.DayOfWeek);

var endDate = DateTime.Today.Add(TimeSpan.FromDays(4 * daysInWeek));

for (var curDate = startDate; curDate &lt;= endDate; curDate = curDate.AddDays(daysInWeek))
{
 saturdays.Add(curDate);
}

// Order by date, descending
saturdays = saturdays.OrderByDescending(d =&gt; d).ToList();

// Output list of Saturdays to console for verification
saturdays.ForEach(s =&gt; Console.WriteLine(s.ToShortDateString()));
</code></pre>

blocks|key|1898235|text|这个怎么样：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1898236|public+static+void+Main()
{
++++var+start+=+DateTime.Now;
++++var+saturdays+=+GetSaturdays(start,+13,+4).OrderBy(d+=>+Math.Abs((start+-+d).Days));
++++foreach+(var+s+in+saturdays)+
++++{
++++++++Console.WriteLine(s.ToLongDateString());
++++}
}

public+static+IEnumerable<DateTime>+GetSaturdays(DateTime+start,+int+weeksBack,+int+weeksForward)
{
++++var+startingSat+=+start.AddDays(6+-+(int)start.DayOfWeek);
++++for+(int+i+=+-weeksBack;+i+<+weeksForward;+i%2B%2B)
++++{
++++++++yield+return+startingSat.AddDays(i+*+7);
++++}
}|code-block|syntax|javascript|1898237|你的问题仍然有点不清楚，你希望如何这些有序，但你可以改变排序，以反映它是你想要的。听起来，你想要他们的排序，因为他们离开始日期有多近，这几乎是没有道理的。如果您只希望它们按日期降序(如果这是您实际需要的话，您应该这么说)，那么只需将OrderBy替换为：|offset|length|style|CODE|1898238|.OrderByDescending(d+=>+d);|1898239|这是一个小提琴|1898240|entityMap|0|LINK|mutability|MUTABLE|url|https://dotnetfiddle.net/vVArbq^0|0|0|38|7|0|0|4|3|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|10|8|@$I|11|J|12|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|14|8|@]|9|@$I|15|J|16|1|17]]|A|$]]|$1|Q|3|-4|5|6|7|18|8|@]|9|@]|A|$]]]|R|$S|$5|T|U|V|A|$W|X]]]]

How about this:

<pre><code>public static void Main()
{
 var start = DateTime.Now;
 var saturdays = GetSaturdays(start, 13, 4).OrderBy(d =&gt; Math.Abs((start - d).Days));
 foreach (var s in saturdays) 
 {
 Console.WriteLine(s.ToLongDateString());
 }
}

public static IEnumerable&lt;DateTime&gt; GetSaturdays(DateTime start, int weeksBack, int weeksForward)
{
 var startingSat = start.AddDays(6 - (int)start.DayOfWeek);
 for (int i = -weeksBack; i &lt; weeksForward; i++)
 {
 yield return startingSat.AddDays(i * 7);
 }
}
</code></pre>

Your question is still a little unclear on how you want these ordered, but you can change the ordering to reflect whatever it is you want. It sounds like you want them ordered by how close they are to the start date which almost certainly doesn't make sense. If you just want them ordered by date descending (which is what you should have said if that's what you actually want) Then just replace the <code>OrderBy</code> with:

<pre><code>.OrderByDescending(d =&gt; d);
</code></pre>

Here's a <a href="https://dotnetfiddle.net/vVArbq" rel="nofollow">fiddle</a>

blocks|key|1898300|text|List<DateTime>+saturdays+=+new+List<DateTime>();
for+(int+i+=+-13;+i+<+4;+i%2B%2B)
++++saturdays.Add(DateTime.Now.AddDays(i+*+7+-+(DateTime.Now.DayOfWeek+-+DayOfWeek.Saturday)));
DateTime+today+=+DateTime.Now;
var+more_recent+=+saturdays.OrderBy(day+=>+Math.Abs(today.Subtract(day).Days)).ToList();|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1898301|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>List&lt;DateTime&gt; saturdays = new List&lt;DateTime&gt;();
for (int i = -13; i &lt; 4; i++)
 saturdays.Add(DateTime.Now.AddDays(i * 7 - (DateTime.Now.DayOfWeek - DayOfWeek.Saturday)));
DateTime today = DateTime.Now;
var more_recent = saturdays.OrderBy(day =&gt; Math.Abs(today.Subtract(day).Days)).ToList();
</code></pre>

I am trying to make a custom collection of DateTime objects that represent all Saturdays from the current date time to 4 weeks forward, and 13 weeks back. I am trying to order this collection by that which is most recent in regards to the current datetime at the top of the collection.

TIA!

Get Saturday DateTime 4 weeks forward, and 13 weeks back

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在尝试制作一个DateTime对象的自定义集合，这些对象表示从当前日期到提前4周和13周前的所有星期六。我试图按最近在集合顶部的当前日期时间排序这个集合。蒂娅！

问周六DateTime提前4周，13周前
EN

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问周六DateTime提前4周，13周前EN