blocks|key|1222282|text|您可以从dic中获取所有键，然后将键和值添加到新dic中，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1222283|NSDictionary+*myDict+=+@{@"one":@"1",@"two":@"2"};
NSArray+*keys+=+[myDict+allKeys];
for+(NSString+*key+in+keys)+{
++++NSDictionary+*yourDic+=+@{key:+[myDict+valueForKey:key]};
++++NSLog(@"%25@",+yourDic);
}|code-block|syntax|javascript|1222284|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can get all keys from your dic then add the key and value to your new dic like this: 

<pre><code>NSDictionary *myDict = @{@"one":@"1",@"two":@"2"};
NSArray *keys = [myDict allKeys];
for (NSString *key in keys) {
 NSDictionary *yourDic = @{key: [myDict valueForKey:key]};
 NSLog(@"%@", yourDic);
}
</code></pre>

blocks|key|1222297|text|你不是那样创造的。如果您想在另一个NSDictionary中拥有一个NSDictionary，您应该编写如下所示的内容：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1222298|NSDictionary+*myDict+=+@{
++++@"firstDict"+:+@{
++++++++@"one":@"1"
++++},
++++@"secondDict":+@{
++++++++@"two":@"2"
++++}
};|code-block|syntax|javascript|1222299|上面的代码将创建一个带有两个字典的NSDictionary，分别是@firstDict和@secondDict。|1222300|另外，请记住，因为字典是键值对，使用for-in循环，实际上是通过字典中的键循环。因此，您的代码相当于：|1222301|for(NSString+*key+in+dict.allKeys)+{+...+}|1222302|entityMap^0|H|C|Y|C|0|0|H|C|X|A|18|B|0|I|6|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|C]|$9|13|A|14|B|C]]|D|@]|E|$]]|$1|M|3|N|5|6|7|15|8|@$9|16|A|17|B|C]]|D|@]|E|$]]|$1|O|3|P|5|H|7|18|8|@]|D|@]|E|$I|J]]|$1|Q|3|-4|5|6|7|19|8|@]|D|@]|E|$]]]|R|$]]

You didn't create it that way. If you wanted to have a <code>NSDictionary</code> inside another <code>NSDictionary</code> you should write something like this :

<pre><code>NSDictionary *myDict = @{
 @"firstDict" : @{
 @"one":@"1"
 },
 @"secondDict": @{
 @"two":@"2"
 }
};
</code></pre>

Above code will create a <code>NSDictionary</code> with two dictionaries at keys <code>@firstDict</code> and <code>@secondDict</code>.

Also, bear in mind, that because dictionaries are key-value pairs, using a <code>for-in</code> loop, actually loops through the keys in that dictionary. So your code is equivalent to:

<pre><code>for(NSString *key in dict.allKeys) { ... }
</code></pre>

blocks|key|1130691|text|for+in+for+NSDictionary将迭代密钥。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1130692|for+(NSString+*+key+in+myDict)+{
++++NSLog(@"%25@",key);
++++NSString+*+value+=+[myDict+objectForKey:key];
}|code-block|syntax|javascript|1130693|如果你想要一本字典。您必须根据这些值创建一个字典。|1130694|for+(NSString+*+key+in+myDict)+{
++++NSLog(@"%25@",key);
++++NSString+*+value+=+[myDict+objectForKey:key];
++++NSDictionary+*+dict+=+@{key:value};
}|1130695|或者你应该这样说：|1130696|+++NSArray+*arrDict+=+@[{@{"one":@"1"},@{@"two":@"2"}];
+++for+(NSDictionary*+tmp+in+arrDict)+{
++++++NSLog(@"%25@",tmp);
+++}|1130697|entityMap^0|0|6|B|C|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|10|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|12|8|@]|D|@]|E|$]]|$1|Q|3|R|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|S|3|-4|5|6|7|14|8|@]|D|@]|E|$]]]|T|$]]

<code>for in</code> for <code>NSDictionary</code> will iterate the keys.

<pre><code>for (NSString * key in myDict) {
 NSLog(@"%@",key);
 NSString * value = [myDict objectForKey:key];
}
</code></pre>

If you want to get a dictionary. You have to create a dictionary from these values

<pre><code>for (NSString * key in myDict) {
 NSLog(@"%@",key);
 NSString * value = [myDict objectForKey:key];
 NSDictionary * dict = @{key:value};
}
</code></pre>

Or you should init like this:

<pre><code> NSArray *arrDict = @[{@{"one":@"1"},@{@"two":@"2"}];
 for (NSDictionary* tmp in arrDict) {
 NSLog(@"%@",tmp);
 }
</code></pre>

blocks|key|1130708|text|我找到解决办法了|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1130709|NSDictionary+*myDict+=+@{@"one":@"1",@"two":@"2"};
NSMutableArray+*arrayObject+=+[[NSMutableArray+alloc]init];
NSMutableArray+*arrayKey+=+[[NSMutableArray+alloc]init];
NSMutableArray+*arrayObjectKey+=+[[NSMutableArray+alloc]init];
NSMutableDictionary+*dict+=+[[NSMutableDictionary+alloc]init];
for+(NSString+*stringValue+in+myDict.allValues)
{
++[arrayObject+addObject:stringValue];
}
for+(NSString+*stringKey+in+myDict.allKeys)
{
++[arrayKey+addObject:stringKey];
}
for(int+i+=+0;i<[arrayKey+count];i%2B%2B)
{
++++dict+=+[[NSMutableDictionary+alloc]initWithObjectsAndKeys:[NSString+stringWithFormat:@"%25@",[arrayKey+objectAtIndex:i]],@"key",nil];
+++[dict+setObject:[NSString+stringWithFormat:@"%25@",[arrayObject+objectAtIndex:i]]+forKey:@"value"];

+++[arrayObjectKey+addObject:dict];
}
NSLog(@"The+arrayObjectKey+is+-+%25@",arrayObjectKey);|code-block|syntax|javascript|1130710|输出是|1130711|The+arrayObjectKey+is+-
(
++++{
++++key+=+one;
++++value+=+1;
},
++++{
++++key+=+two;
++++value+=+2;
}
)|1130712|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

I got the solution

<pre><code>NSDictionary *myDict = @{@"one":@"1",@"two":@"2"};
NSMutableArray *arrayObject = [[NSMutableArray alloc]init];
NSMutableArray *arrayKey = [[NSMutableArray alloc]init];
NSMutableArray *arrayObjectKey = [[NSMutableArray alloc]init];
NSMutableDictionary *dict = [[NSMutableDictionary alloc]init];
for (NSString *stringValue in myDict.allValues)
{
 [arrayObject addObject:stringValue];
}
for (NSString *stringKey in myDict.allKeys)
{
 [arrayKey addObject:stringKey];
}
for(int i = 0;i&lt;[arrayKey count];i++)
{
 dict = [[NSMutableDictionary alloc]initWithObjectsAndKeys:[NSString stringWithFormat:@"%@",[arrayKey objectAtIndex:i]],@"key",nil];
 [dict setObject:[NSString stringWithFormat:@"%@",[arrayObject objectAtIndex:i]] forKey:@"value"];

 [arrayObjectKey addObject:dict];
}
NSLog(@"The arrayObjectKey is - %@",arrayObjectKey);
</code></pre>

The Output is 

<pre><code>The arrayObjectKey is -
(
 {
 key = one;
 value = 1;
},
 {
 key = two;
 value = 2;
}
)
</code></pre>

blocks|key|3002186|text|创建字典：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3002187|NSDictionary+*myDict+=+[NSDictionary+dictionaryWithObjectsAndKeys:@"1",@"One",@"2","Two",nil];|code-block|syntax|javascript|3002188|使用以下方法获取一个值：(这个示例tmp将为1)|3002189|NSString+*tmp+=+[myDict+objectForKey:@"One"];|3002190|在控制台中显示输出：|3002191|NSLog(@"%25@",tmp);|3002192|显示整个NSDictionary|3002193|NSLog+(@"contents+of+myDict:+%25@",myDict);|3002194|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|Y|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|10|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

Create the dictionary:

<pre><code>NSDictionary *myDict = [NSDictionary dictionaryWithObjectsAndKeys:@"1",@"One",@"2","Two",nil];
</code></pre>

Get a value out using:(this example tmp will be 1)

<pre><code>NSString *tmp = [myDict objectForKey:@"One"];
</code></pre>

Display the output in console:

<pre><code>NSLog(@"%@",tmp);
</code></pre>

To display the whole NSDictionary

<pre><code>NSLog (@"contents of myDict: %@",myDict);
</code></pre>

blocks|key|1222360|text|您所做的是创建一个具有键值对的字典。我认为你想做的是有一个字典数组。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1222361|NSArray+*myArray+=+@[@{@"one":@"1"},+@{@"two":@"2"}];
for+(NSDictionary*+tmp+in+myArray)+{
++++NSLog(@"%25@",tmp);
}|code-block|syntax|javascript|1222362|然而，我认为这样做没有任何意义。你能做的就是：|1222363|NSDictionary+*myDict+=+@{@"one":@"1",@"two":@"2"};

for+(NSString*+key+in+[myDict+allKeys])+{
++++NSLog(@"%25@+=+%25@",+key,+myDict[key]);
}|1222364|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

What you are doing is creating a dictionary with key-value pairs. I think what you want to do is have an array with dictionaries. 

<pre><code>NSArray *myArray = @[@{@"one":@"1"}, @{@"two":@"2"}];
for (NSDictionary* tmp in myArray) {
 NSLog(@"%@",tmp);
}
</code></pre>

However I don't see a point in doing this. What you could do is:

<pre><code>NSDictionary *myDict = @{@"one":@"1",@"two":@"2"};

for (NSString* key in [myDict allKeys]) {
 NSLog(@"%@ = %@", key, myDict[key]);
}
</code></pre>

<pre><code>NSDictionary *myDict = @{@"one":@"1",@"two":@"2"};

for (NSDictionary* tmp in myDict) {
 NSLog(@"%@",tmp);
}
</code></pre>

resut:
<a href="https://i.stack.imgur.com/IVybP.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/IVybP.png" alt="image"></a>

my <code>tmp</code>is NSString

I want to get a <code>dictionary</code> with <code>key</code>= one , <code>value</code> = 1

how to get nsDictionary element by using for-in

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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NSDictionary *myDict = @{@"one":@"1",@"two":@"2"};for (NSDictionary* tmp in myDict) {    NSLog(@"%@",tmp);}调查结果：​我的tmp是NSString我想要一个dictionary，key= 1，value =1

问如何使用for-in获取nsDictionary元素
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问如何使用for-in获取nsDictionary元素EN