HTTP状态[404]？[未找到](原始服务器没有找到当前的代表)
HTTP状态[404]？[未找到](原始服务器没有找到当前的代表)
提问于 2017-06-09 05:53:07
我使用(jsp、servlet、apache 9、eclipse、oracle11g)创建了一个servlet项目。我已经创建了index.jsp (获取登录详细信息并重定向到LoginServlet以获得数据库表中的用户名和密码验证)。在index.jsp中，我甚至提到了一个"register.jsp“链接，如果第一次用户注册)。当我运行项目时，会打开index.jsp页面。
当我提供用户id和密码详细信息(在数据库中手动输入用户名和密码详细信息)时，它将成功地重定向LoginServlet等servlet。
但是当我点击“注册”的链接时，我会得到上面提到的错误(HTTP状态404？找不到类型状态报告消息/TodayServlet/Regier.jsp描述，源服务器没有找到目标资源的当前表示形式，也不愿意透露其中的存在。Apache Tomcat/9.0.0.M20)
我的问题来自index.jsp，我无法打开"register.jsp“("register.jsp通过index.jsp中的锚标记提供)”。
请查找我的附件中的目录结构和主jsp、servlet和web.xml代码。
index.jsp (主要代码)：
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<center>
<form action="LoginServlet" method="post">
enter name:<input type="text" name="name"><br>
enter pass:<input type="password" name="pass"><br>
<a href="register.jsp">New User Register here...!!!</a><br>
<input type="submit" value="login"><br>
</form>
</center>
</body>
</html>register.jsp (主要代码)：
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<center>
<form action="RegisterServlet" method="post">
enter name:<input type="text" name= "name1"> <br>
enter pass:<input type="text" name= "pass1"><br>
enter email:<input type="text" name="email1"><br>
<input type="submit" value="register"><br>
</form>
</center>
</body>
</html>RegisterServlet.java (主要代码)：
package com.pack;
import java.io.IOException;
import java.io.PrintWriter;
import java.sql.Connection;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class RegisterServlet extends HttpServlet {
protected void doPost(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException {
res.setContentType("text/html");
PrintWriter out=res.getWriter();
String uname1=req.getParameter("name1");
String upass1=req.getParameter("pass1");
String uemail1=req.getParameter("email1");
req.setAttribute("username", uname1);
try{
Connection conn=DbConnection.getConnection();
PreparedStatement ps=conn.prepareStatement("insert into register_table values(?,?,?)");
ps.setString(1, uname1);
ps.setString(2, upass1);
ps.setString(3, uemail1);
int i=ps.executeUpdate();
if(i>0){
req.getRequestDispatcher("WelcomeServlet").forward(req, res);
}
else{
out.print("try registering again ");
req.getRequestDispatcher("register.jsp").include(req, res);
}
}
catch(Exception e){
e.printStackTrace();
}
}
}我在其他servlet中没有遇到任何问题(LoginServlet，WelcomeServlet.)
LoginServlet.java (完整代码)：
package com.pack;
import java.io.IOException;
import java.io.PrintWriter;
import java.sql.Connection;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class LoginServlet extends HttpServlet {
protected void doPost(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException {
RequestDispatcher rd= null;
res.setContentType("text/html");
PrintWriter out=res.getWriter();
String upassword=req.getParameter("pass");
out.println(upassword);
String uname2=req.getParameter("name");
out.println(uname2);
try{
Connection con=DbConnection.getConnection();
out.println("conection established");
PreparedStatement ps=con.prepareStatement("select * from register_table where username=? and password=?");
ps.setString(1, uname2);
ps.setString(2, upassword);
ResultSet rs= ps.executeQuery();
if(rs.next()){
out.println("username is "+rs.getString(1)+" and pwd is "+rs.getString(2));
req.setAttribute("uid", uname2);
req.getRequestDispatcher("MainServlet").forward(req, res);
}else{
out.println("user name or password incorrect.Check and login again or register");
req.getRequestDispatcher("index.jsp").include(req, res);
}
}catch(Exception e){
e.printStackTrace();
}
}
}web.xml (代码)：
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>TodayServlet</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<servlet>
<description></description>
<display-name>LoginServlet</display-name>
<servlet-name>LoginServlet</servlet-name>
<servlet-class>com.pack.LoginServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>LoginServlet</servlet-name>
<url-pattern>/LoginServlet</url-pattern>
</servlet-mapping>
<servlet>
<description></description>
<display-name>RegisterServlet</display-name>
<servlet-name>RegisterServlet</servlet-name>
<servlet-class>com.pack.RegisterServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>RegisterServlet</servlet-name>
<url-pattern>/RegisterServlet</url-pattern>
</servlet-mapping>
<servlet>
<description></description>
<display-name>WelcomeServlet</display-name>
<servlet-name>WelcomeServlet</servlet-name>
<servlet-class>com.pack.WelcomeServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>WelcomeServlet</servlet-name>
<url-pattern>/WelcomeServlet</url-pattern>
</servlet-mapping>
<servlet>
<description></description>
<display-name>MainServlet</display-name>
<servlet-name>MainServlet</servlet-name>
<servlet-class>com.pack.MainServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>MainServlet</servlet-name>
<url-pattern>/MainServlet</url-pattern>
</servlet-mapping>
</web-app>目录结构：
- TodayServlet(项目名称)>src>com.pack>servlets
- web> (web.xml和jsp文件)
Stack Overflow用户
发布于 2018-03-20 19:53:00
我曾多次与这个问题作斗争。
我目前使用的解决方案是webapp (或保存视图(如jsp)的文件夹)是否处于部署程序集中。
试试这个：
右键单击项目> Build Path > Configure Build path > Deployment Assembly > Add(right hand side) > Folder > (添加jsp文件夹，默认为src/main/webapp)
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/44450206
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