我不明白为什么在下面的代码中,当我实例化一个daughter
类型的对象时,会调用默认的grandmother()
构造函数?
我认为要么应该调用grandmother(int)
构造函数(以遵循我的mother
类构造函数的规范),要么根本不应该编译这段代码,因为它是虚拟继承。
在这里,编译器在我背后默默地调用grandmother
默认构造函数,而我从来没有要求过它。
#include <iostream>
class grandmother {
public:
grandmother() {
std::cout << "grandmother (default)" << std::endl;
}
grandmother(int attr) {
std::cout << "grandmother: " << attr << std::endl;
}
};
class mother: virtual public grandmother {
public:
mother(int attr) : grandmother(attr) {
std::cout << "mother: " << attr << std::endl;
}
};
class daughter: virtual public mother {
public:
daughter(int attr) : mother(attr) {
std::cout << "daughter: " << attr << std::endl;
}
};
int main() {
daughter x(0);
}
https://stackoverflow.com/questions/9907722
复制相似问题